Reasoning Ability - SPLessons

Alpha Numeric Sequence Puzzle

Chapter 2

SPLessons 5 Steps, 3 Clicks
5 Steps - 3 Clicks

Alpha Numeric Sequence Puzzle

shape Introduction

In Alpha numeric sequence puzzle, a mix up sentence consisting of some letters, numbers and symbols are given followed by some certain questions based on it.


Reasoning Ability -BANKING|SSC|RAILWAYS|INSURANCE|RECRUITMENT EXAMS – EBOOKS


shape Concept

Based on following types, questions are categorized:


  • Satisfying certain conditions in the given sequence, it is required to find elements(letters, numbers or symbols.

  • At a certain given relative position in the sequence, it is need to determine the element.

  • By converting the hidden part in relation to the position of the elements in the sequence, it is required to complete a series consisting of terms formed by a combination of the elements of the sequence.

  • By finding the common property which other combinations share as per their positions in the given sequence, It is required to find the odd combination from among a given set of combinations of elements.

  • To determine the analogical relationship between a given pair of combination of elements, later find a combination which carry same relationship with another given combination.


shape Samples

1. Study the following arrangement of symbols, letters and numbers. Answer the following questions?

2 P J @ 8 $ L B 1 V # U 6 δ G W 9 K C D 3 © . € 5 F R 7 A Y 4


    a. Which one among QK5, L6D, PLδ, 1G©, K€4 doesn’t belong to the group?

    b. P@L is to Y75 in the same way what is $1# ?


2. Y W @ 1 & C N 3 P L B 9 ↑ = D * € 2 U M V $ 7 # 4 F G 5 is the alpha numeric series.

    a. How many such symbols are there in the above arrangement which are not immediately preceded by a number and also not immediately followed by a letter?

    b. C13W : 74VG in the same way as N@B= : ?


Solution:


    1. a) Given series is

      2 P J @ 8 $ L B 1 V # U 6 δ G W 9 K C D 3 © . € 5 F R 7 A Y 4
      QK5: Gap between Q & K is 6, K & 5 is 7
      L6D: Gap between L & 6 is 6, 6 & D is 7
      PLδ: Gap between P & L is 5, L & δ is 7
      1G©: Gap between 1 & G is 6, G & © is 7
      K€4: Gap between K & € is 6, € & 4 is 7
      Therefore, PLδ doen’t belong to the same group.


    b) Given series is

      2 P J @ 8 $ L B 1 V # U 6 δ G W 9 K C D 3 © . € 5 F R 7 A Y 4
      P@L is to Y75
      Here, P is second from left whereas Y is second from right.
      @ is fourth from the left whereas 7 is fourth from right.
      L is seventh from the left whereas 5 is seventh from right.
      Similarly consider $1#
      If $ is sixth from left, then sixth letter from right is F.
      If 1 is ninth from left, then letter from right is dot.
      If # is eleventh from left, then eleventh letter from right is 3.
      Therefore, F.3 is the same as $1#.


    2. a) Given series is :

      Y W @ 1 & C N 3 P L B 9 ↑ = D * € 2 U M V $ 7 # 4 F G 5
      Also given that the symbol will be in the middle and it must not be preceded by a number. So on left side of symbol either a letter or symbol can come and to right side of the symbol either number or symbol can come.
      Here, the series consists of numbers, letters and symbols.
      Now, check the symbols from the given series. Then
      W@1, V$7, are the two possible pairs.


    b) C13W : 74VG

      Here C is sixth from left whereas 7 is sixth from right.
      1 is fourth from left whereas 4 is fourth from right.
      3 is eighth from left whereas V is eighth from right.
      W is second from left whereas G is second from right.
      Similarly, consider N@B=
      If N is seventh from left, then seventh from right is $.
      If @ is third from left, then third from right is F.
      If B is eleventh from left, then eleventh from right is 2.
      If = is fourteenth from left, then fourteenth from right is D.
      Therefore, N@B= : $F2D.


2. The series is:
E & G B D M 4 N K H 2 A C Z S V 3 F 1 J L O Q 5 P


    a) If every alternate letter or number is dropped starting from E onwards, then which letter or number will be the second to the left of the tenth letter or number from the left.

    b) What will come in place of question mark in the given sequence like GDR, BMP, D45, ?


Solution:


    a) Given series is:

      E & G B D M 4 N K H 2 A C Z S V 3 F 1 J L O Q 5 P
      Given that every alternate letter or number is dropped.
      After dropping, the series is & B M N H A Z V F J O 5 R.
      Now, tenth from left is J and second to the left of J is V.


    b) Given series is:

      E & G B D M 4 N K H 2 A C Z S V 3 F 1 J L O Q 5 P
      For GDR, in between G and D one letter/number is skipped and R is first from right.
      For BMP, same one letter/number is skipped and second letter from right is placed next to them i.e. P
      Similarly for D45, and 5 is third from right.
      Here, the pairs are following one by one in a particular sequence.
      Therefore. it is clear that the next pair is MNQ.


3. 2 * 8 5 6 B 9 $ Q 3 E 1 7 R D 4 € (13) U @ K (18) A (14) P is the given series. then answer the following:

    a) Four of the following five groups of elements are alike in a certain way and so form a group. Which is the one from Q$9, 56B, 13E, DR7, 2*8 that doesn’t belong to?

    b) If each of the letters in the above series of elements is given a value equivalent to the serial number in the English alphabet, what will be the difference between the sum of the consonants and sum of the vowels used in the series?


Solution:


    a) Given series is:

      2 * 8 5 6 B 9 $ Q 3 E 1 7 R D 4 € (13) U @ K (18) A (14) P
      Here, Q$9 is following right direction.
      56B is following left direction.
      13E has no direction.
      DR7 is following right direction.
      2*8 is following left direction.
      Therefore, 13E doesn’t belong to the group.


    b) Given series is:

      2 * 8 5 6 B 9 $ Q 3 E 1 7 R D 4 € (13) U @ K (18) A (14) P
      Here, need to consider the given alphabets with numerical values according to the English alphabets.
      B Q E R D U K A P
      Now take consonants and add i.e.
      B + Q + R + D + K + P = 2 + 17 + 18 + 4 + 11 + 16 = 68
      Take vowels and add i.e.
      E + U + A = 5 + 21 + 1 = 27
      Therefore,
      Difference between sum of consonants and sum of vowels = 68 – 27 = 41.


4. Which symbol/letter/number is sixth to the left of the eighteenth element from the left. If the series is:
R * T J L 2 $ D = M # 8 C % B < K 1 & A W ? P E + Q @ 7 f 6


Solution:


    Given Series is:
    R * T J L 2 $ D = M # 8 C % B < K 1 & A W ? P E + Q @ 7 f 6
    First find the 18th element i.e. 1
    Again move back six places to the left of 1 i.e. 8.
    otherwise, 18 – 6 = 12th i.e. 12th from left is 8.


5. If the series is:
S E 6 T A Q # 2 U J P 8 1 D * 4 V % U 3 N X 5 δ K 9 M. Then,
How many such vowels are there in the above arrangement, each of which is immediately followed by a number but not by a consonant?


Solution:


    Given series is :
    S E 6 T A Q # 2 U J P 8 1 D * 4 V % U 3 N X 5 δ K 9 M
    First identify the vowels from given series i.e. E, A, I, U are four vowels.
    By given condition, the required pattern or pair should be like first element shouldn’t be consonant that means it can contain number/symbol. Second element should be an vowel. Third element should be a number.
    Therefore, only one pair is present in the series which satisfies the given conditions.

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