Scheme of Screening Test for recruitment to the post of Panchayat Secretary in A.P. Panchayat Raj Subordinate Service.

• The screening test consist of 2 parts i.e., Part A and Part B.


• Both the parts consists of 75 Questions each with 75 Marks respectively.


• This test would be of 150 Minutes duration.


• All Papers will be of OBJECTIVE TYPE.


• Screening Test will be conducted in Offline Mode.

General and Mental Ability:

• Events of national and international importance.


• Current affairs- international, national and regional.


• General Science and it applications to the day to day life Contemporary developments in Science & Technology and information Technology


• Social- economic and political history of modern India with emphasis on Andhra Pradesh.


• Indian polity and governance: constitutional issues, public policy, reforms and e-governance initiatives with specific reference to Andhra Pradesh.


• Economic development in India since independence with emphasis on Andhra Pradesh.


• Physical geography of Indian sub-continent and Andhra Pradesh.


• Disaster management: vulnerability profile, prevention and mitigation strategies, Application of Remote Sensing and GIS in the assessment of Disaster.


• Sustainable Development and Environmental Protection


• Logical reasoning, analytical ability and data interpretation.

• Data Analysis:


• Tabulation of data


• Visual representation of data


• Basic data analysis (Summary Statistics such as mean, median, mode, variance and coefficient of variation) and Interpretation


• Bifurcation of Andhra Pradesh and its Administrative, Economic, Social, Cultural, Political, and Legal implications/problems.

1. Look at this series: 2, 6, 18, 54, ... What number should come next

A. 108 B. 148 C. 162 D. 216

Answer: Option C
2. Statements: I. All the schools in the area had to be kept closed for most part of the week. II. Many parents have withdrawn their children from the local schools.

A. Statement I is the cause and statement II is its effect B. Statement II is the cause and statement I is its effect C. Both the statements I and II are independent causes D. Both the statements I and II are effects of independent causes

Answer: Option D
3. Which word does NOT belong with the others

A. tyre B. steering wheel C. engine D. car

Answer: Option D
4. Window is to pane as book is to

A. novel B. glass C. cover D. page

Answer: Option D
Explanation: A window is made up of panes, and a book is made up of pages. The answer is not (choice a) because a novel is a type of book. The answer is not (choice b) because glass has no relationship to a book. (Choice c) is incorrect because a cover is only one part of a book; a book is not made up of covers.
5. Statement: Should family planning be made compulsory in India? Arguments: I. Yes. Looking at the miserable conditions in India, there is no other go. II. No. In India, there are people of various religions and family planning is against the tenets of some of the religions.

A. Only argument I is strong B. Only argument II is strong C. Either I or II is strong D. Both I and II are strong

Answer: Option D
6. Find the number of triangles in the given figure.

A. 12 B. 18 C. 22 D. 26

Answer: Option B
Explanation:

The simplest triangles are AHB, GHI, BJC, GFE, GIE, IJE, CEJ and CDE i.e. 8 in number.
The triangles composed of two components each are HEG, BEC, HBE, JGE and ICE i.e. 5 in number.
The triangles composed of three components each are FHE, GCE, and BED i.e. 3 in number.
There is only one triangle i.e. AGC composed of four components.
There is only one triangle i.e. AFD composed of nine components.
Thus, there are 8 + 5 + 3 + 1 + 1 = 18 triangles in the given figure.
7. Find the number of triangles in the given figure.

A.18 B. 20 C. 24 D. 27

Answer: Option C
Explanation:

The simplest triangles are IJO, BCJ, CDK, KQL, MLQ, GFM, GHN and NIO i.e. 8 in number.
The triangles composed of two components each are ABO, AHO, NIJ, IGP, ICP, DEQ, FEQ, KLM, LCP and LGP i.e.10 in number.
The triangles composed of four components each are HAB, DEF, LGI, GIC, ICL and GLC i.e. 6 in number.
Total number of triangles in the figure = 8 + 10 + 6 = 24.
8. Which of the following is a non-metal that remains liquid at room temperature

A. Phosphorous B. Bromine C. Chlorine D. Helium

Answer: Option B
Study the following table and answer the questions.

9. What is the different between the number of students passed with 30 as cut-off marks in Chemistry and those passed with 30 as cut-off marks in aggregate

A. 3 B. 4 C. 5 D. 6

Answer: Option D
Explanation:
Required difference
= (No. of students scoring 30 and above marks in Chemistry) - (Number of students scoring 30 and above marks in aggregate)
= 27 - 21
= 6.

1. A $ B means A is the father of B; A # B means A is the sister of B; A * B means A is the daughter of B and A @ B means A is the brother of B. Which of the following indicates that M is the wife of Q?

A. Q $ R # T @ M B. Q $ R @ T # M C. Q $ R * T # M D. Q $ R @ T * M

Answer: Option D
2. If A $ B means A is the brother of B; B * C means B is the son of C; C @ D means C is the wife of D and A # D means A is the son of D, how C is related to A

A. Maternal grandmother B. Maternal aunt C. Aunt D. Mother

Answer: Option D
3. Pointing to a girl Sandeep said, "She is the daughter of the only sister of my father." How is sandeep related to the girl

A. Uncle B. Cousin C. Father D. Grandfather

Answer: Option B
4. Pointing to a boy in the photograph Reena said, "He is the only son of the only child of my grandfather." How Reena is related to that boy

A. High per capita real income B. Large proportion of labor force in the tertiary sector C. State of deprivation of large proportion of population D. All the above

Answer: Option B
5. A * B means A is the sister of B A $ B means B is the mother of A A + B means A is the brother of B A = B means B is the father of A. Which of the following means M is the maternal uncle of N

A. M = P + Q * N B. N + P = Q * M C. N * P $ Q * M D. None of these

Answer: Option D
6. If M x N means M is the daughter of N; M + N means M is the father of N; M % N means M is the mother of N and M - N means M is the brother of N then P % Q + R - T x K indicates which relation of P to K

A. Daughter-in-law B. Sister-in-law C. Aunt D. None of these

Answer: Option D
7. If P + Q means P is the brother of Q; P x Q means P is the father of Q and P - Q means P is the sister of Q, which of the following relations shows that I is the niece of K

A. K + Y + Z - I B. K + Y x I - Z C. Z - I x Y + K D. K x Y + I - Z

Answer: Option B
8. Pointing towards a girl, Abhisek says, "This girl is the daughter of only a child of my father." What is the relation of Abhisek's wife to that girl

A. Daughter B. Mother C. Aunt D. Sister

Answer: Option B
9. If A $ B means B is the father of A; A # B means B is the mother of A; A * B means B is the sister of A and A @ B means B is the husband of A, which of the following indicates that N is the grandmother of P

A. P * Q # M $ N B. P @ Q $ M # N C. P # Q $ N * M D. None of these

Answer: Option D
10. Anupam said to a lady sitting in a car, "The only daughter of the brother of my wife is the sister-in-law of the brother of your sister." How the husband of the lady is related to Anupam

A. Maternal uncle B. Uncle C. Father D. Son-in-law

Answer: Option D

Directions(1-8):1. A clock is set right at 8 a.m. The clock gains 10 minutes in 24 hours will be the true time when the clock indicates 1 p.m. on the following day

A. 48 min. past 12. B. 46 min. past 12. C. 45 min. past 12 D. 47 min. past 12.

Answer: Option A
Explanation:
Time from 8 a.m. on a day to 1 p.m. on the following day = 29 hours.
24 hours 10 min. of this clock = 24 hours of the correct clock.
[latex]{145}^{6}[/latex] hrs of this clock = 24 hours of the correct clock.
29 hours of this clock = 24*[latex]\frac{614}{5}[/latex]*29 hrs of the correct clock
= 28 hrs 48 min of the correct clock.
Therefore, the correct time is 28 hrs 48 min. after 8 a.m.
This is 48 min. past 12.
2. An accurate clock shows 8 o'clock in the morning. Through how may degrees will the hour hand rotate when the clock shows 2 o'clock in the afternoon

A. 360 B. 180 C. 90 D. 60

Answer: Option B
Explanation:
Angle traced by the hour hand in 6 hours= ([latex]\frac{360}{12}[/latex])*6
3. At what time between 4 and 5 o'clock will the hands of a watch point in opposite directions

A. 54 past 4 B. (53 + [latex]\frac{7}{11}[/latex]) past 4 C. (54 + [latex]\frac{8}{11}[/latex]) past 4 D. (54 + [latex]\frac{6}{11}[/latex]) past 4

Answer: Option D
Explanation:
4 o'clock, the hands of the watch are 20 min. spaces apart.
To be in opposite directions, they must be 30 min. spaces apart.
Minute hand will have to gain 50 min. spaces.
55 min. spaces are gained in 60 min
50 min. spaces are gained in 6055×50 min. or 54611
Required time = 54611 min. past 4.
4. A watch which gains uniformly, is 5 min,slow at 8 o'clock in the morning on Sunday and it is 5 min 48 sec.fast at 8 p.m on following Sunday. when was it correct?

A. 7 pm on Wednesday B. 20 min past 7pm on Wednesday C. 15 min past 7pm on Wednesday D. 8 pm on Wednesday

Answer: Option B
Explanation:
This Sunday morning at 8:00 AM, the watch is 5 min. Slow, and the next Sunday at 8:00 PM it becomes 5 min 48 sec fast. The watch gains 5+54860 min in a time of (7×24)+12 = 180 hours.
To show the correct time, it has to gain 5 min.
545 min→180 hours
5 min -& ([latex]\frac{5542}{180}[/latex])
8313 hrs=72 hrs+1113 hrs=3 days+ +20 min
5. A clock is set right at 5 a.m. The clock loses 16 minutes in 24 hours.What will be the true time when the clock indicates 10 p.m. on 4th day

A. 11pm B. 12 pm C. 1 pm D. 2 pm

Answer: Option A
Explanation:
Time from 5 am. on a day to 10 pm. on 4th day = 89 hours.
Now 23 hrs 44 min. of this clock = 24 hours of correct clock.
356/15 hrs of this clock = 24 hours of correct clock
89 hrs of this clock = (24 x 31556 x 89) hrs of correct clock.
= 90 hrs of correct clock.
So, the correct time is 11 p.m.
6. At what time between 5 and 6 o' clock are the hands of a 3 minutes apart

A. 24 min B. 12 min C. 13 min D. 14 min

Answer: Option A
Explanation:
In this type of problems the formuae is
(5*x+ or - t)*12/11
Here x is replaced by the first interval of given time. Here x is 5.
t is spaces apart
Case 1 : (5*x + t) * [latex]\frac{12}{11}[/latex]
(5*5 + 3) * [latex]\frac{12}{11}[/latex]
28 * [latex]\frac{12}{11}[/latex] = [latex]\frac{336}{11}[/latex]= 31511 min
therefore the hands will be 3 min apart at 31 [latex]\frac{5}{11}[/latex] min past 5.
Case 2 : (5*x - t) * [latex]\frac{12}{11}[/latex]
(5*5 -3 ) * [latex]\frac{12}{11}[/latex]
22 *[latex]\frac{12}{11}[/latex] = 24 min
therefore the hands will be 3 min apart at 24 min past 5
7. At what time between 2 and 3 o'clock will the hands of a clock be together

A. (9 + [latex]\frac{10}{11}[/latex]) min past 2 B. (10 + [latex]\frac{10}{11}[/latex]) min past 2 C. (11 + [latex]\frac{10}{11}[/latex]) min past 2 D. (12 + [latex]\frac{10}{11}[/latex]) min past 2

Answer: Option B
Explanation:
At 2 o'clock, the hour hand is at 2 and the minute hand is at 12, i.e. they are 10 min spaces apart.
To be together, the minute hand must gain 10 minutes over the hour hand.
Now, 55 minutes are gained by it in 60 min.
10 minutes will be gained in 6055 × 10 min. = 101011 min.
The hands will coincide at 101011 min. past 2.
8. Find the angle between the hour hand and the minute hand of a clock when the time is 3.25

A. 47.5 degrees B. 57.5 degrees C. 45.5 degrees D. 55.5 degrees

Answer: Option A
Explanation:
At 3 O'clock, Minute hand is at 12 while the Hour hand is at 3. Again the minute hand has to sweep through ( 30 x 5 ) ie 150° for reaching the figure 5 to show 25 mins.
Simultaneously the Hour hand will also rotate for 25 mins. Thus starting from the mark, 3 the hour hand will cover an angle = [latex]\frac{25 × 30 }{60}[/latex] = 12.5°
Hence, Angle between Hour and the Minute hand = ( 60 - 12.5 ) = 47.5°

Directions(1-6):
1. It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010

A. Sunday B. Saturday C. Friday D. Wednesday

Answer: Option C
Explanation:
On [latex]{31}^{st}[/latex]31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
2. What was the day of the week on 28th May, 2006

A. Thursday B. Friday C. Saturday D. Sunday

Answer: Option D
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
3. What was the day of the week on 17th June, 1998

A. Monday B. Tuesday C. Wednesday D. Thursday

Answer: Option C
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
4. What will be the day of the week 15th August, 2010

A. Sunday B. Monday C. Tuesday D. Friday

Answer: Option A
Explanation:
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.
Jan. Feb. March April May June July Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days 227 days = (32 weeks + 3 days) 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.
Given day is Sunday.
5. Today is Monday. After 61 days, it will be:

A. Wednesday B. Saturday C. Tuesday D. Thursday

Answer: Option B
Explanation:
Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
After 61 days, it will be Saturday.
6. If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004:

A. Sunday B. Saturday C. Tuesday D. Wednesday

Answer: Option A
Explanation:
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).

Directions(1-5):
1. Father is four times the age of his daughter. If after 5 years, he would be three times of daughter’s age, then further after 5 years, how many times he would be of his daughter’s age?

A. 1.5 times B. 2 times C. 2.5 times D. 3 times

Answer: Option C
Explanation:Let the daughter's age be x and father's age be 4x.
So as per question, 4x + 5 = 3(x + 5). So x = 10.
Hence present age of daughter is 10 years and present age of father is 40 years.
So after 5 + 5 = 10 years, daughter age would be 20 years and father’s age would be 50 years.
Hence father would be 50/20 = 2.5 times of daughter’s age.
2. What is Aman's present age, if after 20 years his age will be 10 times his age 10 years back

A. 6.2 B. 7.7 years C. 13.3 years D. 10 years

Answer: Option C
Explanation:Let the daughter's age be x and father's age be 4x.
Let Aman's present age be x
Aman's age before 10 years = x - 10)
Aman's age after 20 years = (x + 20)
We are given that, Aman's age after 20 years (x + 20) is 10 times his age 10 years back (x – 10)
Therefore, (x + 20) = 10 (x – 10)
Solving the equation, we get x + 20 = 10x – 100
9x = 120, x = 13.3 years
3. Nisha is 15 years elder to Romi. If 5 years ago, Nisha was 3 times as old as Romi, then find Nisha’s present age.

A. 32.5 years B. 27.5 years C. 25 years D. 24.9 years

Answer: Option B
Explanation:Let the daughter's age be x and father's age be 4x.
Let age of Romi be y
Nisha is 15 years elder than Romi = (y + 15). So Nisha's age 5 years ago = (y + 15 – 5).
Romi's age before 5 years = (y – 5)
5 years ago, Nisha is 3 times as old as Romi
(y + 15 – 5) = 3 (y – 5)
(y + 10) = (3y – 15)
2y = 25 ⇒ y = 12.5
Romi's age = 12.5 years
Nisha's age = (y + 15) = (12.5 + 15) = 27.5 years.
4. One year ago, the ratio of Honey and Piyush ages was 2: 3 respectively. After five years from now, this ratio becomes 4: 5. How old is Piyush now

A. 5 years B. 25 years C. 10 years D. 15 years

Answer: Option C
Explanation:Let the daughter's age be x and father's age be 4x.
We are given that age ratio of Honey: Piyush = 2: 3
Honey’s age = 2x and Piyush’s age = 3x
One year ago, their age was 2x and 3x.
Hence at present, Honey's age = 2x +1 and Piyush's age = 3x +1
After 5 years, Honey’s age = (2x +1) + 5 = (2x + 6)
Piyush's age = (3x +1) + 5 = (3x + 6)
After 5 years, this ratio becomes 4: 5. Therefore,
[latec]\frac{2x+6}{3x+6}[/latex] = [latec]\frac{4}{5}[/latex]
10x + 30 = 12x + 24 ⇒ x = 3
Piyush's present age = (3x + 1) = (3x 3 + 1) = 10 years
Honey's present age = (2x + 1) = (2x 3 + 1) = 7 years
5. Ten years ago, the age of mother was three times the age of her son. After ten years, mother’s age will be twice that of his son. Find the ratio of their present ages.

A. 11 : 7 B. 9 : 3 B.7 : 4 D. 7 : 3

Answer: Option D
Explanation:
Let the daughter's age be x and father's age be 4x.
10 years ago, age of mother was three times the age of her son. Say, the age of son was x and mother's age was 3x.
At present: Mother's age is (3x + 10) and son’s age is (x + 10)
After ten years: Mother's age will be (3x + 10) +10 and son’s age will be (x + 10) + 10. Given that, mother’s age is twice that of son after ten years.
(3x + 10) +10 = 2 [(x + 10) + 10]
(3x + 20) = 2[x + 20]
Solving the equation, we get x = 20
(3x + 10): (x + 10) = 70: 30 = 7: 3.

Directions(1-5):
1. One morning Udai and Vishal were talking to each other face to face at a crossing. If Vishal's shadow was exactly to the left of Udai, which direction was Udai facing?

A. East B. West C. North D. South

Answer: Option C
2. Y is in the East of X which is in the North of Z. If P is in the South of Z, then in which direction of Y, is P

A. North B. South C. South-East D. None of these

Answer: Option D
3. If South-East becomes North, North-East becomes West and so on. What will West become

A. North-East B. North-West C. South-East D. South-West

Answer: Option C
4. A man walks 5 km toward south and then turns to the right. After walking 3 km he turns to the left and walks 5 km. Now in which direction is he from the starting place?

A. West B. South C. North-East D. South-West

Answer: Option C
5. Rahul put his timepiece on the table in such a way that at 6 P.M. hour hand points to North. In which direction the minute hand will point at 9.15 P.M. ?

A. South-East B. South C. North D. West

Answer: Option D

Directions(1-5):
1. In a certain code 'MISSIONS' is written as 'MSIISNOS'. How is 'ONLINE' written in that code

A. OLNNIE B. ONILEN C. NOILEN D. LNOENI

Answer: Option A
Explanation:
First and last letter remain same. The others interchange their positions in pair of two. So, NL become LN IN become NI so code of ONLINE will be OLNNIE
2. In certain code 'TIGER' is written as 'QDFHS'. How is 'FISH' written in that code

A. GERH B. GRHE C. GREH D. GHRE

Answer: Option B
Explanation:
Reverse the word and move each letter –1. Reverse of FISH is HSIF subtract 1 from each letter of HSIF. So code of FISH become GRHE.
3. In certain code 'FROZEN' is written as 'OFAPSG'. Then how would 'MOLTEN' be written in that code

A. OFPOMN B. OFSMPN C. OFUMPN D. OFUNPM

Answer: Option C
Explanation:
Reverse the word and move each letter +1. Reverse of MOLTEN is NETLOM add 1 to each letter of NETLOM. So code of MOLTEN become OFUMPN.
4. In a certain code 'ROAR' is written as 'URDU'. How is 'URDU' written in that code

A. V X D B. XUGX C. ROAR D. VSOV

Answer: Option B
Explanation:
Each letter moves +3. Add 3 to each letter of URDU,so code of URDU will be XUGX
5. In a certain code 'LIMCA' is written as 'HJLDZ'. Which of the following words is written as 'IFWJBP'

A. M E X I C O B. MERCURY C. JAPAN D. MIDNIGHT5. H O N D U S

Answer: Option A
Explanation:
Each letter moves +1, -1, ....alternately except for L, which is –4. We have to find the word for the code IFWJBP. Add 4 to I then -1, +1 alternately to the remaining letters. The word will be MEXICO.