Introduction
What is Direction Sense Test?
Direction Sense Test – Verbal Reasoning Questions and Answers. … The main objective of these questions is to test the candidate’s ability to identify the direction in respect of a person who has moved in different directions from his original position.
Direction Sense is one of important topic in Reasoning Ability Section. In Direction Sense – Quiz 2 article candidates can find questions with an answer. By solving this questions candidates can improve and maintain, speed, and accuracy in the exams. Direction Sense – Quiz 2 questions are very useful for different exams such as IBPS PO, Clerk, SSC CGL, SBI PO, NIACL Assistant, NICL AO, IBPS SO, RRB, Railways, Civil Services etc.
Q1
A boy rode his bicycle Northward, then turned left and rode 1 km and again turned left and rode 2 km. He found himself 1 km west of his starting point. How far did he ride northward initially?
The boy rode 2 km. Northward.
- A. 1 km
B. 2 km
C. 3 km
D. 5 km
Q2
K is 40 m South-West of L. If M is 40 m South-East of L, then M is in which direction of K?
Hence M is in the East of K.
- A. East
B. West
C. North-East
D. South
Q3
Golu started from his house towards North. After covering a distance of 8 km. he turned towards left and covered a distance of 6 km. What is the shortest distance now from his house?
Required distance = AC
= [latex]\sqrt {{8}^{2} + {6}^{2}}[/latex]
= [latex]\sqrt {64 + 36}[/latex]
= [latex]\sqrt {100}[/latex]
= 10 km
- A. 10 km.
B. 16 km.
C. 14 km.
D. 2 km
Q4
X started to walk straight towards south. After walking 5 m he turned to the left and walked 3 m. After this he turned to the right and walked 5 m Now to which direction X is facing?
Hence X will face in the end towards South.
- A. North-East
B. South
C. North
D. South-West
Q5
The length and breadth of a room are 8 m and 6 m respectively. A cat runs along all the four walls and finally along a diagonal order to catch a rat. How much total distance is covered by the cat?
Required distance = 8 + 6 + 8 + 6 + [latex]\sqrt {{8}^{2} + {6}^{2}}[/latex]
= 28 + [latex]\sqrt {64 + 36}[/latex]
= 28 + [latex]\sqrt {100}[/latex]
= 28 + 10 km = 38 km
- A. 10
B. 14
C. 38
D. 48