A. 24.7

B. 25.4

C. 26.6

D. 27.2

E. 28.5

Answer: Option A

Solution: x = \( \frac{38} {5}\) × 3.25

= 24.7

**2. 17.8 + \( \frac{3} {7}\) of 89.6** = ?

A. 52.8

B. 54.4

C. 56.2

D. 58.6

E. 60.4

Answer: Option C

Solution: 17.8 + 38.4

= 56.2

**3. 373.816 + 274.102 – 199.573 – 108.108** = ?

A. 338.147

B. 339.787

C. 340.237

D. 341.347

E. 342.107

Answer: Option C

Solution: x = 647.918 – 307, 681

= 340.237

**4. 14.8 × 7.25 = 20% of** = ?

A. 524.5

B. 528.5

C. 532.5

D. 536.5

E. 540.5

Answer: Option D

Solution: 107.3 = \( \frac{20} {100}\) × x

x = 536.5

**5. \( \sqrt{1156} \) x \( \sqrt{42.25} \)** = ?

A. 212

B. 215

C. 218

D. 220

E. 221

Answer: Option E

Solution: x = 34 × 6.5

= 221

**6. 2\( \frac{1} {6}\) + (3 \( \frac{3}{4} \) – 1\( \frac{1}{4}) \)** = ?

A. 4\( \frac{5} {12}\)

B. 4\( \frac{1} {4}\)

C. 4\( \frac{7} {12}\)

D. 5\( \frac{1} {4}\)

E. None of these

Answer: Option E

Solution: (2 + 3 – 1) + \( \frac{1}{6} \) + \( \frac{3}{4}) \) – \( \frac{1}{4} \)

= \( \frac{2 + 9 – 3}{12} \)

= 4 + \( \frac{8}{12} \)

= \( \frac{42}{3} \)

**7. 36251 + 43261** = ? **+ 52310**

A. 27202

B. 28102

C. 29302

D. 26602

E. None of these

Answer: Option A

Solution: 36251 + 43261 = x + 52310

79512 = x + 52310

79512 – 52310 = x

x = 27202

**8. 7 \( \frac{3} {6}\) of 534 + 262 ** = **61800 – ** ?

A. 56533

B. 57533

C. 58533

D. 37355

E. None of these

Answer: Option B

Solution: \( \frac{45} {6}\) × 534 + 262 = 61800 – x

4005 + 262 = 61800 – x

x = 57533

**9. 72% of 486 – 64% of 261 ** = ?

A. 184.66

B. 183.66

C. 188.88

D. 182.88

E. 186.24

Answer: Option D

Solution: x = 349.92 – 167.04

= 182.88

**10. ? ÷ 62 × 12 = 264 **

A. 1364

B. 1284

C. 1348

D. 1388

E. None of these

Answer: Option A

Solution: \( \frac{x} {62}\) × 12

= 264

x = 1364

The students are studying in various universities and within each university percentage of boys and girls is given.

Universities | Percentage of Students | Percentage of Boys | Percentage of Girls |
---|---|---|---|

A | 12 | 55 | 45 |

B | 15 | 60 | 40 |

C | 8 | 30 | 70 |

D | 28 | 75 | 25 |

E | 17 | 20 | 80 |

F | 20 | 64 | 36 |

**1. What is the ratio of total number of boys in University B and D together to the total number of girls in the same universities together**?

A. 25 : 19

B. 35 : 21

C. 20 : 7

D. 30 : 13

E. 5 : 3

Answer: Option D

Solution: Total boys in B = \( \frac{15} {100}\) × 32500 × \( \frac{60} {100}\) = 2925

Total boys in D = \( \frac{28} {100}\) × 32500 × \( \frac{75} {100}\) = 6825

Total girls in B = \( \frac{15} {100}\) × 32500 × \( \frac{40} {100}\)= 1950

Total girls in D = \( \frac{28} {100}\) × 32500 × \( \frac{25} {100}\)= 2275

Reqd. Ratio = (\( \frac{2925 + 6825} {1950 + 2275})\)

Reqd. Ratio = \( \frac{9750} {4225}\)

Reqd. Ratio = \( \frac{30} {13}\)

**2. The total number of students in the University A is what per cent of the total number of students in University F**?

A. 55%

B. 67%

C. 60%

D. 48%

E. 58%

Answer: Option C

Solution: \( \frac{12} {100}\) × 32500

= \( \frac{x} {100}\) × \( \frac{20} {100}\) × 32500

x = 60

**3. What is the total number of boys from university A,C and E together**?

A. 6030

B. 5030

C. 7030

D. 4030

E. 3030

Answer: Option D

Directions (4 – 7): The following graph shows the number of students participated in annual talent show of Kurukshetra university from different colleges. Study the graph carefully to answer the given questions.

A. 28 : 27

B. 25 : 26

C. 25 : 29

D. 27 : 29

E. None of these

Answer: Option B

Solution: Ratio = \( \frac{340 + 190 + 220} {240 + 320 + 220}\)

= 25 : 26

**5. From which of these colleges the total number of students participated is 2nd minimum**?

A. College P

B. College Q

C. College R

D. College S

E. None of these

Answer: Option D

Solution: Collage P = 840

Q = 900

R = 780

S = 740

T = 790

U = 730

V = 870

Q > V > P > T > R > S >U

**6. If 40% of the total students of college S who participated in acting, are doing solo acting and other are in group acting. 66\( \frac{2} {3}\)% of the students participated in group acting are a part of comedy dramas. Then find the total number of students who are acting in comedy dramas.**?

A. 104

B. 120

C. 110

D. 108

E. None of these

Answer: Option A

Solution: Total in S = 260

Number of students acting In comedy drama

= \( \frac{60} {100}\) × \( \frac{2} {3}\) × 260

= 104

**7. The difference between the no. of students participating in dancing from college P and R and that in singing from T and U**?

A. 165

B. 170

C. 82

D. 94

E. None of these

Answer: Option B

Solution: Total in dance from P & R

= 340 + 260 = 600

= Number of students singing

From T & U is = 280 + 150 = 430

Difference = 600 – 430

= 170

**8. The length and breadth of a plot are 35 m and 16 m respectively. If the rate of fencing is Rs. 7 per meter, what is cost of its fencing**?

A. Rs. 3920

B. Rs. 602

C. Rs. 714

D. Rs. 357

E. None of these

Answer: Option C

Solution: Perimeter of plot = 2 (c + b) = 2

(35 + 16) = 102 m

Total cost of fencing = 7 × 102 = Rs 714

Directions (9 – 10): In the following number series one number is missing. Find out the missing number.

**9. 2, 21, 138, 705,**?

A. 2386

B. 3540

C. 2820

D. 3236

E. None of these

Answer: Option E

Solution: 2 × 7 + 1 × 7 = 21

21 × 6 + 2 × 6 = 138

138 × 5 + 3 × 5 = 705

705 × 4 + 4 × 4 = 2836

**17, 52, 158, 477, ?, 4310**

A. 1433

B. 1432

C. 1435

D. 1434

E. None of these

Answer: Option C

Solution: 17 × 3 + 1 = 52

52 × 3 + 2 = 158

158 × 3 + 3 = 477

477 × 3 + 4 = 1435

1435 × 3 + 5 = 4310