A candidate with **quantitative aptitude** knowledge will be in a better position to analyse and make sense of the given data. Quantitative Aptitude knowledge is an **important** measure for a prospective business executive’s **abilities**.

The article **IBPS RRB PO Quantitative Aptitude Quiz 13** provides Quantitative Aptitude questions with answers useful to the candidates preparing for** Competitive exams, Entrance exams, Interviews** etc. **IBPS RRB** has released **IBPS RRB Officer 2019 **Official Notification for Officer Scale(I, II, and II). Quantitative Aptitude plays major role to qualify examination. The article **IBPS RRB PO Quantitative Aptitude Quiz 13** will assist the students to know the expected questions from **Quantitative Aptitude**.

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**Answer –** Option C

**Explanation –**

\(\frac {?%} {100}\) = * 120 = 90

? = 75%

**2. After decreasing 24% in the price of an article costs Rs.912. Find the actual cost of an article?**

**Answer –** Option A

**Explanation –**

CP* \(\frac {76} {100}\)

= 912

CP= 12 * 100 => CP = 1200

**3. How much 60% of 50 is greater than 40% of 30?**

**Answer –** Option A

**Explanation –**

\(\frac {60} {100}\) * 50 â€“ \(\frac {40} {100} –\)* 30

30 – 12 = 18

**4. 40% of a number is more than 20% of 650 by 190. Find the number?**

**Answer –** Option C

**Explanation –**

\(\frac {40} {100}\)* X â€“ – \(\frac {20} {100}\) * 650 = 190

\(\frac {2} {5}\)X = 320

X = 800

**5. 60% of a number is added to 120, the result is the same number. Find the number?**

**Answer –** Option A

**Explanation –**

\(\frac {60} {100}\) * X + 120 = X

2X = 600

X = 300

**Answer –** Option A

**Explanation –**

\(\frac {8} {12}\) + \(\frac {6} {x}\)

x = 18 days

**2. A can do a piece of work in 15 days and B in 20 days. They began the work together but 5 days before the completion of the work, A leaves. The work was completed in?**

**Answer –** Option B

**Explanation –**

\(\frac {x â€“ 5} {15}\) + \(\frac {x} {20}\) = 1

11 \(\frac {3} {7}\) days

**3. A, B and C can do a piece of work in 24, 30 and 40 days respectively. They start the work together but C leaves 4 days before the completion of the work. In how many days is the work done?**

**Answer –** Option D

**Explanation –**

Let the investment be Rs. x. Then

\(\frac {x} {24} \) + \(\frac {x} {30} \) + \(\frac {x} {40} \) = 1

x = 11 days

**4. A, B and C can do a piece of work in 7 days, 14 days and 28 days respectively. How long will they taken, if all the three work together?**

**Answer –** Option B

**Explanation –**

\( \frac 1} {7}\) + \( \frac {1} {14}\) + \( \frac {1} {28}\) = \( \frac {7} {28}\)

= \( \frac {1} {4}\) => 4 days

**5. A is twice as good a work man as B and together they finish the work in 14 days. In how many days A alone can finish the work?**

**Answer –** Option B

**Explanation –**

WC = 2:1

2x + x = = \( \frac {1} {21}\)

<2x = \(\frac {100 * 2x} {x * 10}\)years = 20 years

**Answer –** Option D

**Explanation –**

Three consecutive numbers can be taken as (P – 1), P, (P + 1).

So, (P – 1) + P + (P + 1) = 102

3P = 102 => P = 34.

The lowest of the three = (P – 1) = 34 – 1 = 33.

**2. The sum of the two digits of a number is 10. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number?**

**Answer –** Option B

**Explanation –**

Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.

P + Q = 10 —– (1)

(10Q + P) – (10P + Q) = 54

9(Q – P) = 54

(Q – P) = 6 —– (2)

Solve (1) and (2) P = 2 and Q = 8

The required number is = 28

**3. The sum of three consecutive even numbers is 42. Find the middle number of the three?**

**Answer –** Option A

**Explanation –**

Three consecutive even numbers (2P – 2), 2P, (2P + 2).

(2P – 2) + 2P + (2P + 2) = 42

6P = 42 => P = 7.

The middle number is: 2P = 14.

**4. The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?**

**Answer –** Option C

**Explanation –**

A + B = 60, A = 2B

2B + B = 60 => B = 20 then A = 40.

5 years, their ages will be 45 and 25.

Sum of their ages = 45 + 25 = 70.

**5. The ratio of the present ages of P and Q is 3:4. 5 years ago, the ratio of their ages was 5:7. Find the their present ages?**

**Answer –** Option A

**Explanation –**

Their present ages be 3X and 4X.

5 years age, the ratio of their ages was 5:7, then (3X – 5):(4X – 5) = 5:7

X = 35 – 25 => X = 10.

Their present ages are: 30, 40.