# IBPS SO Number Series Quiz 1

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# IBPS SO Number Series Quiz 1

### Introduction

is one of the important topic in the Quantitative Aptitude section . Number Series is the arrangement of numbers in a certain order where some numbers are wrongly kept or some numbers are missing from that series. So accurate series are to be found. Number Series in competitive exams are divided into two. One is missing series and the other is wrong series. A number series is given in which a number is wrongly placed is the wrong series. Candidates are asked to identify that particular wrong number. A number series in which a specific number is missing is the missing series. Candidates have to identify the missing number. The article IBPS SO Number Series Quiz 1 lists important number series practice questions for competitive exams like RRB ALP/Technical Exams/Junior Engineer Recruitment Exams, SSC, IBPS PO Exams and etc.

### Quiz

Direction: In the following number series, a wrong number is given. Find out that wrong number.

1. 3.2, 4.8, 2.4, 3.6, ?, 2.7

A. 12.5
B. 1.8
C. 6.8
D. 13.2

Explanation –

The series is

3.2 × 1.5= 4.8

4.8 ÷ 2= 2.4

2.4 × 1.5= 3.6

3.6 ÷ 2= 1.8

2. 5, 6, 14, 45, ?, 925, 5556

A. 194
B. 184
C. 202
D. 143

Explanation –

The pattern of the series can be judged by the logical sequence given below:

5 × 1 + 1 = 6

6 × 2 + 2 = 14

14 × 3 + 3 = 45

45 × 4 + 4 = 184

184 × 5 + 5 = 925

92 × 6 + 6 = 5556

Key note: Multiple operations i.e. (×,+), (×,-), (÷,+), (÷, -) are majorly used in the number series questions.

3. 1, 5, 9, 17, 25, ?

A. 35
B. 37
C. 25
D. 28

Explanation –

$${1}^{2}$$ = 1

$${2}^{2}$$ + 1 = 5

$${3}^{2}$$ = 9

$${4}^{2}$$ + 1 = 17

$${5}^{2}$$ = 25

$${6}^{2}$$ + 1 = 37

4. 2, 4, 10, 32, ?, 652

A. 130
B. 150
C. 170
D. 190

Explanation –

The pattern followed is: 2, 4, 10, 32, ?, 652

4 = 2 × 1 + 2

10 = 4 × 2 + 2

32 = 10 × 3 + 2

? = 32 × 4 + 2, i.e. ? = 130

652 = 130 × 5 + 2

5. 1, 9, 36, 100, 225, ?

A. 441
B. 484
C. 400
D. 289

Explanation –

1, 9, 36, 100, 225, (441)

$${1}^{2}, {3}^{2}, {6}^{2}, {10}^{2}, {15}^{2}, {21}^{2}$$

(3 – 1) = 2

(6 – 3) = 3

(10 – 6) = 4

(15 – 10) = 5

(X – 15) = 6

X = 21

Required term = $${21}^{2}$$ = 441

Direction: In the following number series, a wrong number is given. Find out that wrong number.

1. 14, 9, 20, 12 , ?, 15

A. 55
B. 14
C. 30
D. 26

Explanation –

14 ÷ 2 + 2 = 9

9 × 2 + 2 = 20

20 ÷ 2 + 2 = 12

12 × 2 + 2 = 26

26 ÷ 2 + 2 = 15

2. 142, 143, 156, 193, 272, 417, ?

A. 653
B. 658
C. 659
D. 657

Explanation –

The difference between numbers is $$+ {1}^{3} + 0, + {2}^{3} + 5,+ {3}^{3} + 10 , +{4}^{3} + 15, + {5}^{3} + 20, + {6}^{3} + 25$$

3. 8544, 1420, ?, 66, 18, 5

A. 862
B. 548
C. 495
D. 280

Explanation –

8544 (÷ 6 – 4), 1420 (÷ 5 – 4) 280 (÷ 4 – 4) 66 (÷ 3 – 4) 18 (÷ 2 – 4) 5

4. 9, 19, 59, ?, 1199, 7199

A. 319
B. 279
C. 259
D. 239

Explanation –

9,

19 = 9 × 2 + 1,

59 = 19 × 3 + 2,

Thus,? = 59 × 4 + 3 = 239,

1199 = 239 × 5 + 4

7199 = 1199 × 6 + 5

239 is the missing number.

5. 7, 14, 23, 34, ?, 62

A. 47
B. 55
C. 49
D. 52

Explanation –

Direction: In the following number series, a wrong number is given. Find out that wrong number.

1. 25, 21, 48, 30, 157, 121

A. 25
B. 157
C. 21
D. 30

Explanation –

25, 21, 48, (32), 157, 121

The Pattern is:-

→ 25

→ 21 = 25 – $${2}^{2}$$

→ 48 = 21 + $${3}^{3}$$

→ 32 = 48 – $${4}^{2}$$

→ 157= 32 + $${5}^{3}$$

→ 121= 157 – $${6}^{2}$$

2. 100, 101, 97, 106, 92, 115, 79

A. 101
B. 97
C. 92
D. 115

3. 4, 15, 41, 130, 378, 1141, 3415

A. 4
B. 41
C. 378
D. 130

Explanation –

The series is 4 $$\times$$ + 3 = 15

15 $$\times$$ 3 – 4 = 41

41 $$\times$$ 3 + 5 = 128

128 $$\times$$ 3 – 6 = 378

378 $$\times$$ 3 + 7 = 1141

1141 $$\times$$ 3 – 8 = 3415

Hence, there should be 128 in place of 130.

4. 1, 5, 19, 77, 307, ?

A. 1265
B. 1266
C. 1229
D. 1270

Explanation –

The given series is

5 = 1 $$\times$$ 4 + 1

19 = 5 $$\times$$ 4 -1

77 = 19 $$\times$$ 4 + 1

307 = 77 $$\times$$ 4 – 1

1229 = 307 $$\times$$ 4 + 1

5. 20, 19, 17, ?, 10, 5

A. 14
B. 13
C. 15
D. 12