SP Quiz - SPLessons
boy2

Mensuration – Quiz 1

Home > > Tutorial
SPLessons 5 Steps, 3 Clicks
5 Steps - 3 Clicks

Mensuration – Quiz 1

shape Introduction

Mensuration is one of important topic in Quantitative Aptitude Section. In Mensuration – Quiz 1 article candidates can find a question with an answer. By solving this question candidates can improve and maintain, speed, and accuracy in the exams. Mensuration - Quiz 1 questions a very useful for different exams such as IBPS PO, Clerk, SSC CGL, SBI PO, NIACL Assistant, NICL AO, IBPS SO, RRB, Railways, Civil Services etc.

shape Q1

What is the area of an equilateral triangle of side 16 cm?
    A. 48 [latex]\sqrt{3}[/latex] [latex]{cm}^{2}[/latex] B. 128 [latex]\sqrt{3}[/latex] [latex]{cm}^{2}[/latex] C. 9.6 [latex]\sqrt{3}[/latex] [latex]{cm}^{2}[/latex] D. 64 [latex]\sqrt{3}[/latex] [latex]{cm}^{2}[/latex]

SPLessons

Area of an equilateral triangle = [latex]\frac{\sqrt{3}}{4} {cm}^{2}[/latex]
If S = 16, Area of triangle = [latex]\frac{\sqrt{3}}{4} \times 16 \times 16 = 64 \sqrt{3} {cm}^{2}[/latex]

shape Q2

If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?
    A. 120 [latex]{cm}^{2}[/latex] B. 130 [latex]{cm}^{2}[/latex] C. 312 [latex]{cm}^{2}[/latex] D. 315 [latex]{cm}^{2}[/latex]

SPLessons

The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle = [latex]\frac{1}{2} \times 24 \times 10 = 120 {cm}^{2}[/latex]

shape Q3

Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 15 cm.
    A. 225 [latex]{cm}^{2}[/latex] B. 275 [latex]{cm}^{2}[/latex] C. 285 [latex]{cm}^{2}[/latex] D. 315 [latex]{cm}^{2}[/latex]

SPLessons

Area of a trapezium = [latex]\frac{1}{2} (sum of parallel sides) \times (perpendicular distance between them)[/latex]
= [latex]\frac{1}{2} (20 + 18) \times (15) = 285 {cm}^{2}[/latex]

shape Q4

Find the area of a parallelogram with base 24 cm and height 16 cm.
    A. 262 [latex]{cm}^{2}[/latex] B. 384 [latex]{cm}^{2}[/latex] C. 192 [latex]{cm}^{2}[/latex] D. 131 [latex]{cm}^{2}[/latex]

SPLessons

Area of a parallelogram = base [latex]\times[/latex] height = 24 [latex]\times[/latex] 16 = 384 [latex]{cm}^{2}[/latex]

shape Q5

The perimeter of a triangle is 28 cm and the in radius of the triangle is 2.5 cm. What is the area of the triangle?
    A. 25 [latex]{cm}^{2}[/latex] B. 42 [latex]{cm}^{2}[/latex] C. 49 [latex]{cm}^{2}[/latex] D. 35 [latex]{cm}^{2}[/latex]

SPLessons

Area of a triangle = r * s
Where r is the in radius and s is the semi perimeter of the triangle.
Area of triangle = [latex]2.5 \times \frac{28}{2} = 35 {cm}^{2}[/latex]
Hide Index Show Index