Prepositions
1. The mother was anxious -------- the safety of her son.

A. upon B. about C. for D. at

Answer: Option B
2. After having tea, he settled himself -------- his armchair.

A. into B. over C. to D. on

Answer: Option A
Active Voice and Passive Voice
1. Who teaches you English?

A. By whom are you taught English? B. English is taught by whom? C. By whom were you taught English? D. By whom will you be taught English?

Answer: Option A
2. Rain disrupted the last day's play between India and Sri Lanka.

A. The last day’s play between India and Sri Lanka was disrupted by rain. B. The last day’s play between India and Sri Lanka were disrupted by rain. C. India and Sri Lanka’s play of the last day were disrupted by rain. D. The last day’s play of India and Sri Lanka was disrupted by rain.

Answer: Option A
Joining Sentences
1. Germany and Japan have been successful in making superfast trains. They had been working on it for the past 20 years. (A) Germany and Japan have been successful in making superfast trains for them..... (B) Since Germany and Japan had been working on ..... (C) While Germany and Japan have been successful in .....

A. Only A B. A and B C. B and C D. Only B E. All the three

Answer: Option B
Explanation: The second sentence gives the reason why Germany and Japan have been successful in their endeavor. 'As', 'since', 'for' etc. when used as conjunctions can bring out the idea effectively. But the use of 'while' distorts the idea.
2. The police arrested everyone. Only the leader was not arrested by the police. (A) The police arrested everyone except ..... (B) Besides the leader, the police ..... (C) The police arrested all but the...

A. A and B B. B and C C. A and C D. Only A E. All the three

Answer: Option C
Explanation: The second sentence gives additional information to what is stated in the first. They can be combined to form a simple sentence with the use of 'except' or 'but for'. 'Besides' means 'apart from' or 'in addition to' and hence the use of 'besides' is inappropriate in the given context.
Spotting Errors
1. The road (a) / to famous monument (b) / passes through a forest (c) / No error (d)

A. the road B. to famous monument C. passes through a forest D. no error

Answer: Option B
2. I am not wealthy (a) / so I cannot afford (b) / to buy a expensive car (c) / No error (d)

A. I am not wealthy B. so I cannot afford C. to buy an expensive car D. no error

Answer: Option C
Synonyms
1. Saccharine

A. Leave B. Sweet C. Arid D. Quit

Answer: Option B
Explanation: Saccharine means overly sweet
2. Jovial

A. Incredulous B. Merry C. Revolting D. Dizzy

Answer: Option B
Explanation: Jovial means good-humored or merry
Sentence Improvement
1. My copy is as good or better than yours.

A. as good as or B. as good as C. as good and better D. none

Answer: Option B
2. Would you mind help me with these questions?

A. to help B. of helping C. helping D. helped

Answer: Option C
Error Correction (Phrase in colour)
1. When he is short of money, he earns a little extra cash on being told the fortunes using a pack of tarot cards.

A. by being told fortunes B. by telling fortunes C. by telling of the fortune of D. on telling fortunes E. No correction required

Answer: Option B
Explanation: He is short of money. So he earns extra cash 'by' doing something. Hence 'by' has to replace on. He earns it telling fortunes using the tarot cards.' 'Fortune-telling' is taken up as a profession.
2. Mobile phones are now-a-days used not just to make calls or send and receive text messages but to also carry on financial transactions.

A. but also to carry on B. but to carry out also C. but also to carry out D. and to carry out E. No correction required

Answer: Option C
Explanation: They are used 'not only to make calls but also to carry out'. The use of'to before also' is ungrammatical. Also, financial transactions are 'carried out'. 'carry on' is in apt in this context. The correction is 'but also to carry out'.
Para Completion
1. With the release of foreign exchange for travel through liberalization, the number of non-business travelers increased. ---- Realising the Indian's penchant for shopping, many countries opened up their visa regime and made it easier for the visitors from the subcontinent to spend a few days in their countries. (A) The holidaying Indians went on a shopping spree wherever they could. (B) With the introduction of more airlines and low air, fares travel abroad has become so much cheaper and accessible to a vast multitude of Indians today. (C) It may have been just Sri Lanka or Singapore, to begin with, but the ambit grew and the outbound tourism industry recorded phenomenal growth.

A. Only A B. A and B C. Only B D. Only C E. A and C

Answer: Option E
Explanation: The first sentence talks about the increase in non-business travelers. Statement A follows the first statement as it carries the idea forward. C is a continuation of A. Therefore statements A and C can be inserted between the two given statements.
2. In April, the World Bank asked for bids for a high-tech project - laying a 110-mile-long canal that would channel water from the Red Sea to the Dead Sea. --- The system would also desalinate sea water - one reason why the scheme is popular with the Kingdom of Jordan, which suffers a severe water shortage. (A) The project, estimated to cost $5 billion, would have additional benefits - the water cascading from sea level at the tip of the Red sea to minus 1,400 feet at the Dead sea would create hydroelectricity. (B) A low-tech alternative to this project has been suggested by the environmental organization, Friends of the Earth, Middle East. (C) This alternative is to radically change the consumption habits of the millions of people who live in Jordan.

A. A and B B. B and C C. Only C D. Only A E. Only B

Answer: Option D
Explanation: The opening sentence tells us about a 'high-tech project'. Sentence A further elaborates on it stating the 'additional benefits' of the project. The last sentence gives us another use of the proposed project namely 'desalinating water'. Hence the first and the last sentences along with sentence A makes a meaningful paragraph. Sentences B and C suggest an alternative to this project and hence are not required in between.
Sentence Completion
1. Although the villagers’ lives were profoundly different from her own, Jing-Mae felt a deep ______ for the people when she served in the Peace Corps.

A. reparation B. affinity C. injunction D. exigency E. analogy

Answer: Option B
Explanation: An affinity (n.) is a natural attraction or liking; a feeling of kinship, connection or closeness, similarity; relationship by marriage.
2. Sometimes late at night Sharon would gaze joyfully at her children as they slept and ______ in their innocence.

A. sneer B. ostracize C. revel D. repudiate E. antiquate

Answer: Option C
Explanation: To revel (v.) is to take great pleasure or delight.
Fill in the blanks
1. The island looks very _____ because there are hardly any inhabitants dwelling in it. (A) parlous (B) perilous (C) commodious (D) picturesque (E) deserted (F) desolate

A. A and B B. B and D C. C and D D. C and F E. E and F

Answer: Option E
Explanation: When nobody is living in a place, the place looks 'deserted' or 'desolate' which are the most appropriate words for the blank.
2. One must not be _____ by failure because it is often said that failure is the stepping stone to success. (A) influenced (B) hapless (C) affronted (D) disheartened (E) discouraged (F) inspired

A. A and E B. A and B C. B and C D. D and E E. A and F

Answer: Option D
Explanation: Failure can dishearten or discourage someone.
3. Leadership is the ability to secure desirable actions from a group of followers voluntarily without the use of _____. (A) coercion (B) blandishments (C) discipline (D) deception (E) punishment (F) cajolery

A. A and F B. B and C C. B and D D. B and C E. D and E

Answer: Option A
Explanation: A leader should be able to secure desirable actions from his followers 'voluntarily' without the use of force or 'coercion' or cajolery. Both force or coercion and/or flattery or cajolery can be used to make an unwilling person do the work. Hence logically A and F can fit into the blank.
Error Correction (Underlined Part)
1. Neither the design nor the color of the cloth appeal me.

A. appeals me B. appeal to me C. appeals to me D. has appealed me E. No correction required

Answer: Option C
Explanation: 'Neither...nor' is followed by the verb in the singular form (i.e) appeals. 'Appeals' is always followed by 'to'.
2. As we did not have a route map, we lost.

A. we are lost B. we got lost C. we were losing D. we all lost E. No correction required

Answer: Option B
Explanation: The route map was not there, hence we got lost. It is not the map that 'we lost'. Hence, the given sentence is illogical. The first option is given in present tense where as the given sentence uses past tense - 'did not have'.
3. The self-portrait is a picture one makes of oneself.

A. one make of oneself B. one makes on oneself C. one draws to one's self D. one makes of one's self E. No correction required

Answer: Option E
Explanation: The given sentence is grammatically correct.
Passage Completion
In economics, the term recession generally describes the reduction of a country’s Gross Domestic Product (GDP) for at least two quarters. A recession is…( I )…by rising unemployment, an increase in government borrowing,…( II)…, of share and stock prices, and falling investment. All of these characteristics have effects on people. Some recessions have been anticipated by stock market declines. The real estate market also usually…( III )…before a recession.
1. Choose the best word in place of ( I ) from the given passage

A. imagined B. depict C. shown D. visualized E. characterized

Answer: Option E
2. Choose the best word in place of ( II ) from the given passage

A. Increase B. variance C. more D. decrease E. abundance

Answer: Option D
3. Choose the best word in place of ( III ) from the given passage

A. weakens B. initiates C. awakens D. strengthens E. volatile

Answer: Option A
Substitution
1. A gane in which no one wins.

A. drawn B. postponed C. abandoned D. obsolete

Answer: Option A
2. The government in which all regions are honored.

A. secular B. catholic C. progressive D. fanatic

Answer: Option A
3. A word no longer in use.

A. extant B. nervous C. obsolete D. out dated

Answer: Option C
Idioms and Phrases
1. She exhibited remarkable sang froid during the crisis.

A. Composure B. Temper C. Anger D. Irritation

Answer: Option A
2. None of this hanky panky, please talk straight.

A. jugglery B. indifference C. diversification D. obsession

Answer: Option A
3. The leader must have the lion’s share of the booty.

A. the worthy part B. the smaller part C. the larger part D. the stronger part

Answer: Option C
Antonyms
1. Malodorous

A. Acrid B. Pungent C. Fragrant D. Delicious

Answer: Option C
Explanation: Malodorous means to have a bad smell; Fragrant means smelling sweet or delicate
2. Expound

A. Besmirch B. Confuse C. Confine D. Condemn

Answer: Option B
Explanation: To Expound means to explain; to Confuse, or confound, is the opposite of expound
3. Pique

A. Value B. Gully C. Smooth D. Soothe

Answer: Option D
Explanation: To pique means to excite or irritate; to Soothe means to calm
Sentence Arrangement
1. The house (P) about half a mile distant (Q) that stunds in front of us (R) was built of stones (S) which were dug out of its own site

A. QSPR B. QRPS C. QPRS D. QRSP

Answer: Option C
2. Towards midnight (P) so that the sky was lighted with (Q) and the clouds drifted away (R) the rain ceased (S) the incredible lamp of stars

A. SPQR B. SQPR C. RPQS D. RQPS

Answer: Option D
3. The exhibition committee (P) attractive and useful (Q) to make the exhibition (R) making efforts (S) has been

A. SRQP B. QPRS C. SRPQ D. QPSR

Answer: Option A

Number Coding
1. In a certain code language, if F R A M E = 48 and H U R D L E = 74, then F I G M E N T = ?

A. 74 B. 89 C. 91 D. 87 E. 81

Answer: Option E
Explanation: F R A M E = 6 + 18 + 1 + 13 + 5 = 43 and 43 + 5 = 48. In this, the sum of the place values is added to the number of letters in the word and given as its value. H U R D L E = 8 + 21 + 18 + 4 + 12 + 5 = 68 and 68 + 6 = 74. Similarly, F I G M E N T = 6 + 9 + 7 + 13 + 5 + 14 + 20 = 74 and 74 + 7 = 81.
2. In a certain code language, if APPLE is coded as 28726, LEAVE is coded as 76987 and LETTER is coded as 376347, then what is the code for the word TRAVELLER?

A. 348967764 B. 349876764 C. 348796674 D. 348976674 E. 348969879

Answer: Option D
Explanation: Words Codes 1.APPLE 28726 2.LEAVE 76987 3.LETTER 376347 From (1), P and 2 are repeated. Hence, 2 is code for P. From (2) and (3), E is 7 and T is 3. Similarly, the codes for the remaining letters can be determined. i.e., L is 6, R is 4, A is 8 and V is 9. The code for TRAVELLER is 348976674
3. If 'P' means 'x', 'R' means '+', 'T' means '÷' and 'S' means '-', then 18T3P9S8R6 = ?

A. -1 1/3 B. 46 C. 58 D. 2/3 E. None of these

Answer: Option E
Explanation: After decoding , we get 18 ÷ 3 x 9 - 8 + 6 = 6 x 9 - 8 + 6 = 52
Inserting Correct Mathematical Sign
1. Select the correct combination of mathematical signs to replace * signs so as to balance the equation. 8 * 8 * 1 * 11 * 11

A. + = ÷ - B. x + = ÷ C. ÷x + = D. - + = ÷

Answer: Option D
2. Substitute the correct mathematical symbols in place of * in the following equation: 16 * 4 * 5 * 14 * 6

A. ÷ - = × B. – x += C. ÷x = + D. ÷ + = -

Answer: Option C
3. If ‘x’ means ‘-' , ‘-' means ‘x’, ‘+’ means ‘÷' and ‘÷' means ‘-', then (15 - 10) ÷ (130 + 10) x 50 = ?

A. 1800 B. 113 C. 2000 D. 87

Answer: Option D
Odd Man Out
1. 1, 4, 9, 16, 23, 25, 36

A. 9 B. 23 C. 25 D. 36

Answer: Option B
Explanation: Each of the numbers except 23, is a perfect square.
2. 8, 27, 64, 100, 125, 216, 343

A. 27 B. 100 C. 125 D. 343

Answer: Option B
Explanation: The pattern is 2[latex]^{3}[/latex], 3[latex]^{3}[/latex], 4[latex]^{3}[/latex], 5[latex]^{3}[/latex], 6[latex]^{3}[/latex], 7[latex]^{3}[/latex]. But, 100 is not a perfect cube.
3. 835, 734, 642, 751, 853, 981, 532

A. 751 B. 853 C. 981 D. 532

Answer: Option A
Explanation: In each number except 751, the difference of third and first digit is the middle one.
Mutual Relation Problem
1. How is Ravi's mother's father's son related to Ravi's father ?

A. Cousin B. Uncle C. Brother-in-law D. Son-in-law E. Mother

Answer: Option C
Explanation: Ravi's mother's father's son is Ravi's mother's brother i.e. Ravi's uncle. Ravi's uncle is Ravi's father's brother-in-law.
2. My father's only brother's wife's only daughter's paternal uncle is my mother's

A. Father-in-law B. Husband C. Son D. Uncle E. Father

Answer: Option B
Explanation: My father's only brother's wife is my father's sister-in-law. My father's sister-in-law's only daughter is my father's niece. My father's niece's paternal uncle is my father. My father is my mother's husband.
3. Sanjana's brother-in-law is the son of Ramya. How is Sanjana's husband related to Ramya's husband if Sanjana had no siblings?

A. Nephew B. Son C. Son-in-law D. Father-in-law E. Cannot be determined

Answer: Option B
Explanation: Sanjana's brother-in-law is the son of Ramya means Ramya is Sanjana's mother-in-law. Sanjana's husband is Ramya's son i.e. Sanjana's husband is Ramya's husband's son.
Number Puzzle
1. Which number replaces the question mark?

A. 11 B. 12 C. 10 D. 15

Answer: Option C
Explanation: We have, 3+4 = number below 4 =7; 3+4+5 = number below 5 = 12; 3+7+12 = number below 12 = 22; So, answer is = 3+7 = 10.
2. Find the missing number?

A. 555 B. 577 C. 575 D. 585

Answer: Option B
Explanation: In the first column, 3 * 100 + 5 * 9 = 345. In the second column, 4 * 100 + 6 * 10 = 460. In the third column, missing number = 5 * 100 + 7 * 11 = 577.
3. Which number replaces the question mark?

A. 15 B. 16 C. 20 D. 17

Answer: Option D
Explanation: It is the sum of the two digits(9 + 8) in the quadrant opposite.
Human Relation
1. Pointing to a lady a man said” The son of her only brother is the brother of my wife, How is the lady related to the man?

A. Mother’s sister B. Grand Mother C. Mother-in-law D. Sister of Father-in-law

Answer: Option D
Explanation: Wife brother – Brother-in-law Son of lady’s brother is the brother-in-law of the man , so lady’s brother is man’s father-in-law i.e..., the lady is the sister of man’s father-in-law.
2. Looking at a portrait of a man Harsh said,” His mother is the wife of my father’s son brother and sister I have none at whose portrait was harsh looking?

A. His son B. His cousin C. His uncle D. His Nephew

Answer: Option A
Explanation: Since Harsh has no brother or sister. So he is his father only son, So the wife of harsh’s father’s son –Harsha wife.Thus harsh’s wife is the man’s mother i.e.., or the man is harsh’s son.
3. Deepak said to Nitin “ That boy playing football is the younger of the two brothers of the daughter of my father wife”, How is the boy playing football related to Deepak?

A. Son B. Brother C. Cousin D. Nephew

Answer: Option B
Explanation: Father’s wife –mother, Mother’s daughter-sister.Deepak’s sister’s younger’s brother –Deepak’s younger brother . So the boy is Deepak’s brother.
Non-Verbal Reasoning
1. Choose the alternative which is closely resembles the mirror image of the given combination.

A. 1 B. 2 C. 3 D. 4

Answer: Option B
2. Choose the alternative which closely resembles the mirror image of the given combination.

A. 1 B. 2 C. 3 D. 4

Answer: Option D
3. Choose the alternative which closely resembles the mirror image of the given combination.

A. 1 B. 2 C. 3 D. 4

Answer: Option D
Distance and Direction Sense Test
1. One evening before sunset Rekha and Hema were talking to each other face to face. If Hema's shadow was exactly to the right of Hema, which direction was Rekha facing?

A. North B. South C. East D. Data is inadequate

Answer: Option B
Explanation:

In the evening sunsets in West. Hence then any shadow falls in the East. Since Hema's shadow was to the right of Hema. Hence Rekha was facing towards South.
2. A boy rode his bicycle Northward, then turned left and rode 1 km and again turned left and rode 2 km. He found himself 1 km west of his starting point. How far did he ride northward initially?

A. 1 km B. 2 km C. 3 km D. 5 km

Answer: Option B
Explanation:

The boy rode 2 km. Northward.
3. P started from his house towards west. After walking a distance of 25 m. He turned to the right and walked 10 m. He then again turned to the right and walked 15 m. After this, he is to turn right at 135o and to cover 30 m. In which direction should he go?

A. West B. South C. South-West D. South-East

Answer: Option C
Explanation:

Hence he should go in the South-West direction.
Dictionary Words
1. Arrange the given words in alphabetical order and tick the one that comes in the middle?

A. Plane B. Plain C. Plenty D. Player E. Place

Answer: Option A
Explanation: Place, Plain, Plane, Player, Plenty
2. Arrange the given words in alphabetical order and tick the one that comes in the middle?

A. Reprimand B. Reverence C. Amazed D. Acquire E. Disturb

Answer: Option E
Explanation: Acquire, Amazed, Disturb, Reprimand, Reverence
3. Arrange the given words in alphabetical order and tick the one that comes in the middle?

A. Sound B. Socks C. Shock D. Snooker E. Sharp

Answer: Option D
Explanation: Sharp, Shock, Snooker, Socks, Sound
Tallest, Youngest Relation
1. There are five friends --- Sachin, Kunal, Mohit, Anuj and Rohan. Sachin is shorter than Kunal but taller than Rohan. Mohit is the tallest. Anuj is a little shorter than Kunal and little taller than Sachin. Who is the second tallest?

A. Sachin B. Kunal C. Anuj D. Rohan E. None of these

Answer: Option B
Explanation: Let us denote the five boys by the first letter of their names, namely S, K, M A and R. Then, R < S < K < M and S < A < K. R < S < A < K < M. Kunal is second tallest.
2. There are five friends --- Sachin, Kunal, Mohit, Anuj, and Rohan. Sachin is shorter than Kunal but taller than Rohan. Mohit is the tallest. Anuj is a little shorter than Kunal and little taller than Sachin. Who is the second tallest?

A. Sachin B. Kunal C. Anuj D. Rohan E. None of these

Answer: Option B
Explanation: Let us denote the five boys by the first letter of their names, namely S, K, M A and R. Then, R < S < K < M and S < A < K. R < S < A < K < M. Kunal is second tallest.
3. (i) There is a group of five girls. (ii) Kamini is second in height but younger than Rupa. (iii) Pooja is taller than Monika but younger in age. (iv) Rupa and Monika are of the same age but Rupa is tallest between them. (v) Neelam is taller than Pooja and elder Rupa. If they are arranged in the descending order of their ages, who will be in fourth position?

A. Monika or Rupa B. Kamini C. Monika D. Data inadequate E. None of these

Answer: Option E
Explanation: We first find the sequence of height : By (iii), we have : M < P. By (v), we have : P < N. Now, Rupa is tallest and Kamini is second in height. So, the sequence of heights is : M < P < N < K < R. Now, we determine the age sequence : By (ii), we have K < R. By (iii), we have P < M. By (iv), we have : R = M. By (v), we have : R < N. So, the sequence of ages is : N < R = M < K < P or N < R = M < P < K. Clearly, in the decreasing order of ages, Neelam will be in the fourth position (because Monika and Rupa both lie at third position). Hence, the answer is (e).
Number Ranking & Time Sequence Test
1. Manoj and Sachin are ranked seventh and eleventh respectively from the top in a class of 31 students. What will be their respective ranks from the bottom in the class?

A. 20th and 24th B. 24th and 20th C. 25th and 21st D. 26th and 22nd E. None of these

Answer: Option C
Explanation: Number of students behind Manoj in rank = (31 - 7) = 24. So, Manoj is 25th from the bottom. Number of students behind Sachin in rank = (31 - 11) = 20. So, Sachin is 21st from the bottom.
2. Ravi is 7 ranks ahead of Sumit in a class of 39. If Sumit's rank is seventeenth from the last, what is Ravi's rank from the start?

A. 14th B. 15th C. 16th D. 17th

Answer: Option C
Explanation: Sumit is 17th from the last and Ravi is 7 ranks ahead of Sumit. So, Ravi is 24th from the last.
3. In a queue of Children, Kashish is fifth from the left and Mona is Sixth from the right. When they interchange their places among themselves, Kashish becomes thirteenth from the left. Then, What will be Mona's position from the right?

A. 4th B. 8th C. 14th D. 15th

Answer: Option C
Explanation: Since Kashish and Mona interchange places, so Kashish's new position (13th from left) is the same as Mona's earlier position (6th from right). So,number of children in the queue = (12 + 1 + 5) = 18. Now, Mona's new position is the same as Koshis's earlier position i.e. fifth from left.
coding and decoding
1. In a certain code, TRIPPLE is written as SQHOOKD. How is DISPOSE written in that code?

A. CHRONRD B. DSOESPI C. ESJTPTF D. ESOPSID E. None of these

Answer: Option A
Explanation Each letter in word is moved one step backward to obtain corresponding letter of the code.
2. If in a code language, COULD is written as BNTKC and MARGIN is written as LZQFHM, how will MOULDING be written in that code?

A. CHMFINTK B. LNKTCHMF C. LNTKCHMF D. NITKHCMF E. None of these

Answer: Option C
Explanation Each letter in the word is moved one step backward to obtain the corresponding letter of the code.
3. If FRAGRANCE is written as SBHSBODFG, how can IMPOSING be written?

A. NQPTJHOJ B. NQPTJOHI C. NQTPJOHJ D. NQPTJOHJ E. None of these

Answer: Option D
Explanation Each letter in the word is moved one step forward and the first letter of the group so obtained is put at the end, to obtain the code.
Assign Artificial Values to Mathematical Digit
1. If + means x, – means ÷, x means – and ÷ means +, then— 2 + 15 ÷ 15 – 3 x 8 = ? A. 43 B. 27 C. 35 D. 28 E. None of these
Answer: Option B
2. If + means x, ÷ means –, x means ÷ and means +, then— 5 + 12 ÷ 7 – 44 x 2 = ? A. 75 B. 89 C. 65 D. 82 E. None of these
Answer: Option A
3. If + means ÷, ÷ means –, – means x and x means +, then— 9 + 3 ÷ 5 – 3 x 7 = ? A. 5 B. 15 C. 25 D. 10 E. None of these
Answer: Option E

Simple Interest.
1. Find the simple interest on Rs.500 for 9 months at 6 paisa per month?

A. Rs.345 B. Rs.270 C. Rs.275 D. Rs.324

Answer: Option B
Explanation I = (500*9*6)/100 = 270
2. A certain sum of money at simple interest amounted Rs.840 in 10 years at 3% per annum, find the sum?

A. Rs.500 B. Rs.515 C. Rs.525 D. None

Answer: Option D
Explanation 840 = P [1 + (10*3)/100] P = 646
3. In what time a sum of money double itself at 3% per annum simple interest?

A. 29 years B. 33 1/3 years C. 23 1/3 years D. 13 1/3 years

Answer: Option B
Explanation P = (P*3*R)/100 R = 33 1/3%
Height and Distance
1. The angle of elevation of the sun is 60°. Find the length of the shadow of a man who is 180 cm tall.

A. 127.27 cm B. 103.92 cm C. 311.77 cm D. None of these

Answer: Option B
Explanation:

Let AB be the man and BC be his shadow
AB = 180 tan60° = AB/BC [latex]\sqrt {3}[/latex] = 180/BC BC = 103.92 cm
2. What is the distance between a tower and an observer if the angle of elevation from the observer’s eye to the top of the tower (height = 50 m) is 30°? The observer is 1.5 m tall.

A. 84 B. 28 C. 30 D. 90

Answer: Option A
Explanation:

Let AB be the tower and CD be the observer tan30° = AE/CE 1/[latex]\sqrt {3}[/latex] = (AB – CD) / x = (50 – 1.5)/ x = 48.5/x x = 84 m
3. Two boats are spotted on the two sides of a lighthouse. If the angle of depression made by both the boats from top of the lighthouse is 30° and 45° and the height of the lighthouse is 125 m then find the distance between the two boats.

A. 1 B. 188.56 m C. 250 m D. 197.17 m

Answer: Option D
Explanation:
Let AB be the light house and the two boats be at C and D AB = 125 m tan30° = BC/AB = x/125 = 1/[latex]\sqrt {3}[/latex] x = 72.17 m tan45° = BD/AB = y/125 = 1 y = 125 m Therefore, the distance between the two boats is = x + y = 72.17 + 125 = 197.17 m
Volume and Surface Area
1. 66 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be:

A. 84 B. 90 C. 168 D. 336

Answer: Option A
Explanation: Let the length of the wire be h. Radius = [latex]\frac {1}{2}[/latex] mm = [latex]\frac {1}{20}[/latex] cm. Then, [latex]\frac {22}{7}[/latex] x [latex]\frac {1}{20}[/latex] x [latex]\frac {1}{20}[/latex] x h = 66. h = [latex]\frac {66 \times 20 \times 20 \times 7}{22}[/latex] = 8400 cm = 84 m.
2. In a shower, 5 cm of rain falls. The volume of water that falls on 1.5 hectares of the ground is:

A. 75 cu. m B. 750 cu. m C. 7500 cu. m D. 75000 cu. m

Answer: Option B
Explanation: 1 hectare = 10,000 m[latex]^ {2}[/latex] So, Area = (1.5 x 10000) m[latex]^ {2}[/latex] = 15000 m[latex]^ {2}[/latex]. Depth =[latex]\frac {5}{100}[/latex] m = [latex]\frac {1}{20}[/latex] m. Volume = (Area x Depth) =[latex]\frac {15000\times 1}{20}[/latex] m[latex]^ {3}[/latex] = 750 m[latex]^ {3}[/latex].
3. For a rectangular box, what is the product of the areas of the 3 adjacent faces that meet at a point?

A. The volume of the box B. Twice the volume of the box C. Half of the volume of the box D. Square of the volume of the box

Answer: Option D
Explanation: The area of the 3 adjacent faces of a rectangular box of length ‘l’, breadth ‘b’, and depth ‘h’ are ‘l*b’, ‘b*h’, and ‘l*h’. Therefore, lb*bh*lh = l[latex]^ {2}[/latex] b[latex]^ {2}[/latex] h[latex]^ {2}[/latex] = (lbh)[latex]^ {2}[/latex] = square of the volume of the box.
Logarithm
1. f log 27 = 1.431, then the value of log 9 is:

A. 0.934 B. 0.945 C. 0.954 D. 0.958

Answer: Option C
Explanation: log 27 = 1.431 log (3[latex]^ {3}[/latex] ) = 1.431 3 log 3 = 1.431 log 3 = 0.477 log 9 = log(3[latex]^ {2}[/latex] ) = 2 log 3 = (2 x 0.477) = 0.954.
2. [latex]\frac {log\sqrt {8}}{log 8}[/latex] is equal to:

A. [latex]\frac {1}{\sqrt {8}}[/latex] B. [latex]\frac {1}{4}[/latex] C. [latex]\frac {1}{2}[/latex] D. [latex]\frac {1}{8}[/latex]

Answer: Option C
Explanation: [latex]\frac {log\sqrt {8}}{log 8}[/latex] = [latex]\frac {log (8)^{1/2}}{log 8}[/latex] = [latex] \frac{1/2\times log 8}{log 8}[/latex] = [latex]\frac {1}{2}[/latex].
3. Which of the following statements is not correct?

A. [latex]log_{10}[/latex] 10 = 1 B. log (2 + 3) = log (2 x 3) C. [latex]log_{10}[/latex] 1 = 0 D. log (1 + 2 + 3) = log 1 + log 2 + log 3

Answer: Option B
Answer: Option A. Since [latex]log_{a}[/latex] a = 1, so [latex]log_{10}[/latex] 10 = 1. B. log (2 + 3) = log 5 and log (2 x 3) = log 6 = log 2 + log 3 log (2 + 3) ≠ log (2 x 3) C. Since [latex]log_{a}[/latex] 1 = 0, so [latex]log_{10}[/latex] 1 = 0. D. log (1 + 2 + 3) = log 6 = log (1 x 2 x 3) = log 1 + log 2 + log 3. So, B is incorrect.
Races and Games
1. In a race of 800m, if the ratio of the speeds of two participants P and R is 3:4, and P has a start of 120m, then R beats P by:

A. 100m B. 80m C. 90m D. 110m

Answer: Option B
Answer: Option As P has a start of 120m, P has to cover 680m while R has to cover 800m. Now, when P covers 3m, R covers 4m. Hence, when R covers 800m, P covers (800 * 3) / 4 = 600m Therefore, R beats P by 80m.
2. If in a race of 120m X can beat Y by 20m and Z by 35m, then Y can beat Z by:

A. 12m B. 10m C. 15m D. 18m

Answer: Option D
Answer: Option In a race of 120m, as X beats Y by 20m, when X runs 120m, Y runs 100m. Similarly, as X beats Z by 35m, when X covers 120m, Z covers 85m. Hence, when Y runs 100m, Z runs 85m. When Y runs 120m, Z runs (120 * 85) / 100 = 102m Hence, Y beats Z by 18m.
3. If in a game of 80, P can give 16 points to Q and R can give 20 points to P, then in a game of 150, how many points can R give to Q?

A. 48 B. 60 C. 54 D. 90

Answer: Option B
Answer: Option When P scores 80, Q scores 64. When R scores 80, P scores 60 Hence, when R scores 150, Q scores (60 * 64 * 150) / (80 * 80) = 90 Therefore, in a game of 150, R can give 60 points to Q.
Simplification
1. The price of 2 sarees and 4 shirts is Rs. 1600. With the same money, one can buy 1 saree and 6 shirts. If one wants to buy 12 shirts, how much shall he have to pay?

A. Rs. 1200 B. Rs. 2400 C. Rs. 4800 D. Cannot be determined E. None of these

Answer: Option B
Explanation: Let the price of a saree and a shirt be Rs. x and Rs. y respectively. Then, 2x + 4y = 1600 .... (i) and x + 6y = 1600 .... (ii) Divide equation (i) by 2, we get the below equation. => x + 2y = 800. --- (iii) Now subtract (iii) from (ii) x + 6y = 1600 (-) x + 2y = 800 ---------------- 4y = 800 ---------------- Therefore, y = 200. Now apply the value of y in (iii) => x + 2 x 200 = 800 => x + 400 = 800 Therefore x = 400 Solving (i) and (ii) we get x = 400, y = 200. Cost of 12 shirts = Rs. (12 x 200) = Rs. 2400.
2. A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes, and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has?

A. 45 B. 60 C. 75 D. 90

Answer: Option D
Explanation: Let the number of notes of each denomination be x. Then x + 5x + 10x = 480 16x = 480 x = 30. Hence, total number of notes = 3x = 90.
3. In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for?

A. 160 B. 175 C. 180 D. 195

Answer: Option B
Explanation: Suppose the man works overtime for x hours. Now, working hours in 4 weeks = (5 x 8 x 4) = 160. 160 x 2.40 + x x 3.20 = 432 3.20x = 432 - 384 = 48 x = 15. Hence, total hours of work = (160 + 15) = 175.
Time and Distance.
1. In what time will a railway train 60 m long moving at the rate of 36 kmph pass a telegraph post on its way?

A. 9 sec B. 8 sec C. 7 sec D. 6 sec

Answer: Option D
Explanation T = 60/36 * 18/5 = 6 sec
2. The speed of a car is 90 km in the first hour and 60 km in the second hour. What is the average speed of the car?

A. 72 kmph B. 75 kmph C. 30 kmph D. 80 kmph

Answer: Option B
Explanation S = (90 + 60)/2 = 75 kmph
3. Two cars cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower car takes 1 hour more than the faster car.

A. 906 km B. 960 m C. 960 km D. 966 km

Answer: Option C
Explanation 60(x + 1) = 64x X = 15 60 * 16 = 960 km
Chain Rule
1. A wheel that has 6 cogs is meshed with a larger wheel of 12 cogs. If the smaller wheel has made 22 revolutions, then find the number of revolutions made by the larger wheel.

A. 11 B. 13 C. 15 D. 17

Answer: Option A
Explanation As the number of cogs increases, the revolutions made decrease. Hence, this is a problem related to indirect proportion. Let the number of wheels be x. More cogs (↑), Less revolutions (↓) Given: 6 cogs meshed with a wheel of 12 cogs and smaller wheel made 22 revolutions Therefore, 12: 6:: 22:x 12 × x = 6 × 22 x = [latex]\frac {6 \times 22}{12}[/latex] = 11
2. If 30 men can do a piece of work in 20 hours, then in how many hours will 12 men do it?

A. 18 hours B. 30 hours C. 40 hours D. 50 hours

Answer: Option D
Explanation The number of workers increases, the time required decreases. Hence, this is a problem related to indirect proportion. Workers (↑), Time (↓) Let the number of hours be x. 12 : 30 :: 20 : x [latex]\frac {20}{30}[/latex] = [latex]\frac {20}{x}[/latex] x = [latex]\frac {20 \times 30}{12}[/latex] = 50 12 men require 50 hours to complete the same work.
3. 5 mat-weavers can weave 5 mats in 5 days. At the same time, how many mats would be woven by 10 mat- weavers in 10 days?

A. 10 mats B. 15 mats C. 20 mats D. 30 mats

Answer:
Explanation More mats are weaved if more weavers work. Hence, this problem is related to a direct proportion. Let the required number of mats be x. Total 5 mats can be weaved in 5 days by 5 weavers. \[5: x:: \begin{cases} 5 : 10 - - - (Weavers)\\ 5 : 10 - - - (Days) \end{cases} \] 5 × 5 × x = 10 × 10 × 5 x = [latex]\frac {10 \times 10 \times 5}{5 \times 5}[/latex] = 20 20 mats can be weaved in 10 days by 10 mat weavers.
Permutations and Combinations
1. A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?

A. 21 B. 12 C. 9 D. 108 E. 101

Answer: Option D
Explanation The boy can select one trouser in nine ways. The boy can select one shirt in 12 ways. The number of ways in which he can select one trouser and one shirt is 9 * 12 = 108 ways.
2. Using all the letters of the word "NOKIA", how many words can be formed, which begin with N and end with A?

A. 3 B. 6 C. 24 D. 120 E. 12

Answer: Option B
Explanation There are five letters in the given word. Consider 5 blanks .... The first blank and last blank must be filled with N and A all the remaining three blanks can be filled with the remaining 3 letters in 3! ways. The number of words = 3! = 6.
3. The number of arrangements that can be made with the letters of the word MEADOWS so that the vowels occupy the even places?

A. 720 B. 144 C. 120 D. 36 E. 204

Answer: Option B
Explanation The word MEADOWS has 7 letters of which 3 are vowels. -V-V-V- As the vowels have to occupy even places, they can be arranged in the 3 even places in 3! i.e., 6 ways. While the consonants can be arranged among themselves in the remaining 4 places in 4! i.e., 24 ways. Hence the total ways are 24 * 6 = 144.
Surds and Indices
1. If 9[latex]^ {x}[/latex] – 9[latex]^ {x – 1 }[/latex]= 648, then find the value of x[latex]^ {x}[/latex]

A. 4 B. 9 C. 27 D 64

Answer: Option C
Explanation x[latex]^ {m}[/latex] × x[latex]^ {n}[/latex]n = x[latex]^ {m + n}[/latex] 9[latex]^ {X}[/latex] – 9[latex]^ {x – 1}[/latex] = 648 9[latex]^ {x – 1}[/latex] (9 – 1) = 648 9[latex]^ {x – 1}[/latex] = (648/8) = 81 9[latex]^ {x – 1}[/latex] = 9[latex]^ {2}[/latex] x – 1 = 2 x = 2 + 1 = 3 x[latex]^ {X}[/latex] = 3[latex]^ {3}[/latex] = 27
2. If a and b are whole numbers such that a[latex]^ {b}[/latex]= 121, then find the value of (a – 1)[latex]^ {b + 1}[/latex]

A. 0 B. 10 C. 10[latex]^ {2}[/latex] D. 10[latex]^ {3}[/latex]

Answer: Option D
Explanation 121 = 11[latex]^ {2}[/latex] , hence value of a = 11 and b = 2 can be considered. Therefore, the value of (a – 1)[latex]^ {b + 1}[/latex] = (11 – 1)[latex]^ {2 + 1}[/latex] = 10[latex]^ {3}[/latex]
3. (1331)[latex]^ {– (2/3)}[/latex]

A. –[latex]\frac {1}{11}[/latex] B. –[latex]\frac {11}{121}[/latex] C. [latex]\frac {1}{121}[/latex] D. [latex]\frac {121}{11}[/latex]

Answer: Option C
Explanation Cube root of 1331 is 11. Therefore, (11)[latex]^ {(3)\times – (2/3)}[/latex] Remember the law of indices (x[latex]^ {(m){n}}[/latex]) = x[latex]^ {mn}[/latex] (11)[latex]^ {– 3 \times (2/3)}[/latex] = 11[latex]^ { –2}[/latex] x[latex]^ {–1 }[/latex]=[latex]\frac {1}{x}[/latex] Hence, 11[latex]^ {–2}[/latex] = [latex]\frac {1}{11^{2}}[/latex] = [latex]\frac {1}{121}[/latex]
Pipes and Cistern
1. Two pipes A & B can fill the tank in 12 hours and 36 hours respectively. If both the pipes are opened simultaneously, how much time will be required to fill the tank?

A. 6 hours B. 9 hours C. 12 hours D. 15 hours

Answer: Option B
Explanation If a pipe requires 'x' hrs to fill up the tank, then part filled in 1 hr = 1/x If pipe A requires 12 hrs to fill the tank, then part filled by pipe A in 1 hr = 1/12 If pipe B requires 36 hrs to fill the tank, then part filled by pipe B 1 hr = 1/36 Hence, part filled by (A + B) together in 1 hr = 1/12 + 1/36 = 48 / 432 = 1/9 In 1 hr both pipes together fill the 1/9th part of the tank. This means, together they fill the tank in 9 hrs.
2. Two pipes can fill a tank in 6 hours and 8 hours respectively while a third pipe empties the full tank in 12 hours. If all the three pipes operate simultaneously, in how much time will the tank be filled?

A. 7(1/2) hrs B. 4(4/5) hrs C. 3 (2/7) hrs D. 1(1/5) hrs

Answer: Option B
Explanation If one pipe fills the tank in 'x' hrs, another pipe fills the same tank in 'y' hrs but the third pipe empties the tank in 'z' hrs and all of them are opened together, then The net part filled in 1hr = [latex]\frac {1}{X} + \frac {1}{Y} - \frac {1}{Z}[/latex] From the given data, net part filled in 1 hour = 1/6 + 1/8 -1/12 = 5/24 So, the total time to fill the tank with all pipes open = 24/5 hrs.
3. Two pipes can fill a tank in 10 and 14 minutes respectively and a waste pipe can empty 4 gallons per minute. If all the pipes working together can fill the tank in 6 minutes, what is the capacity of the tank?

A. 120 gallons B. 240 gallons C. 450 gallons D. 840 gallons

Answer: Option D
Explanation Work done by waste pipe in 1 min = (Part filled by total pipes together) -(part filled by first pipe + part filled by second pipe) = 1/6 – [(1/10) + (1/14)] = 1/6 – (24/140) = -1/210 Here, negative (-) sign indicates emptying of tank. To find the capacity, we need to determine the volume of 1/210 part. Therefore, volume of 1/210 part = 4 gallons ---------(given condition) Hence, the capacity of tank = volume of whole = 4 x 210 = 840 gallons.
Boats and Streams
1. A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man's rate is?

A. 1 kmph B. 5 kmph C. 8 kmph D. 3 kmph

Answer: Option A
Explanation DS = 6 US = 4 S =? S = (6 - 4)/2 = 1 kmph
2. A man can swim in still water at 4.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?

A. 3 B. 7.5 C. 2.25 D. 1.5

Answer: Option D
Explanation M = 4.5 S = x DS = 4.5 + x US = 4.5 + x 4.5 + x = (4.5 - x)2 4.5 + x = 9 -2x 3x = 4.5 x = 1.5
3. A man can row with a speed of 15 kmph in still water. If the stream flows at 5 kmph, then the speed in downstream is?

A. 10 kmph B. 5 kmph C. 20 kmph D. 22 kmph

Answer: Option C
Explanation M = 15 S = 5 DS = 15 + 5 = 20
Numbers
1. The sum of the two digits of a number is 10. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number?

A. 34 B. 28 C. 12 D. 17

Answer: Option B
Explanation Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place. P + Q = 10 ----- (1) (10Q + P) - (10P + Q) = 54 9(Q - P) = 54 (Q - P) = 6 ----- (2) Solve (1) and (2) P = 2 and Q = 8 The required number is = 28
2. The sum of three consecutive even numbers is 42. Find the middle number of the three?

A. 14 B. 16 C. 18 D. 24

Answer: Option A
Explanation Three consecutive even numbers (2P - 2), 2P, (2P + 2). (2P - 2) + 2P + (2P + 2) = 42 6P = 42 => P = 7. The middle number is: 2P = 14.
3. The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?

A. 50 B. 60 C. 70 D. 80

Answer: Option C
Explanation A + B = 60, A = 2B 2B + B = 60 => B = 20 then A = 40. 5 years, their ages will be 45 and 25. Sum of their ages = 45 + 25 = 70.
Partnership
1. A, B and C jointly thought of engaging themselves in a business venture. It was agreed that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. Calculate the share of B in the profit.

A. Rs. 1900 B. Rs. 2660 C. Rs. 2800 D. Rs. 2840

Answer: Option B
Explanation For managing, A received = 5% of Rs. 7400 = Rs. 370. Balance = Rs. (7400 - 370) = Rs. 7030. Ratio of their investments = (6500 x 6) : (8400 x 5) : (10000 x 3) = 39000 : 42000 : 30000 = 13 : 14 : 10 B's share = Rs. (7030 x [latex]\frac {14}{37}[/latex] = Rs. 2660.
2. A, B, C subscribe Rs. 50,000 for a business. A subscribes Rs. 4000 more than B and B Rs. 5000 more than C. Out of a total profit of Rs. 35,000, A receives:

A. Rs. 8400 B. Rs. 11,900 C. Rs. 13,600 D. Rs. 14,700

Answer: Option D
Explanation Let C = x. Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000. So, x + x + 5000 + x + 9000 = 50000 3x = 36000 x = 12000 A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12. A's share = Rs. (35000 x [latex]\frac {21}{50}[/latex]) = Rs. 14,700.
3. A starts a business with Rs. 3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B's contribution to the capital?

A. Rs. 7500 B. Rs. 8000 C. Rs. 8500 D. Rs. 9000

Answer: Option D
Explanation Let B's capital be Rs. x. Then,([latex]\frac {3500 \times 12}{7x}[/latex] = [latex]\frac {2}{3}[/latex]) 14x = 126000 x = 9000.
Ratio and Proportion
1. A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B's share?

A. Rs. 500 B. Rs. 1500 C. Rs. 2000 D. None of these

Answer: Option C
Explanation Let the shares of A, B, C, and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively. Then, 4x - 3x = 1000 x = 1000. B's share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.
2. Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40: 57. What is Sumit's salary?

A. Rs. 17,000 B. Rs. 20,000 C. Rs. 25,500 D. Rs. 38,000

Answer: Option D
Explanation Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively. Then,[latex]\frac {2x + 4000}{3x + 4000}[/latex] = [latex]\frac {40}{57}[/latex] 57(2x + 4000) = 40(3x + 4000) 6x = 68,000 3x = 34,000 Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000.
3. If 0.75 : x :: 5 : 8, then x is equal to:

A. 1.12 B. 1.2 C. 1.25 D. 1.30

Answer: Option B
Explanation (x x 5) = (0.75 x 8) => x = [latex]\frac {6}{5}[/latex] = 1.20
Banker’s Discount
1. The banker's discount on Rs. 1600 at 15% per annum is the same as true discount on Rs. 1680 for the same time and at the same rate. The time is:

A. 3 months B. 4 months C. 6 months D. 8 months

Answer: Option B
Explanation S.I. on Rs. 1600 = T.D. on Rs. 1680. Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is on Rs. 1600 at 15%. Time = [latex]\frac {100 \times 80}{1600 \times 15}[/latex] year = [latex]\frac {1}{3}[/latex] year = 4 months.
2. The banker's gain of a certain sum due 2 years hence at 10% per annum is Rs. 24. The present worth is:

A. Rs. 480 B. Rs. 520 C. Rs. 600 D. Rs. 960

Answer: Option C
Explanation T.D. = [latex]\frac {B.G. \times 100}{Rate \times Time}[/latex] = Rs.[latex]\frac {24 \times 100}{10 \times 2}[/latex] = Rs. 120. P.W. = [latex]\frac {100 \times T.D.}{Rate \times Time}[/latex] = Rs.[latex]\frac {100 \times 120}{10 \times 2}[/latex] = Rs. 600.
3. The banker's gain on a sum due 3 years hence at 12% per annum is Rs. 270. The banker's discount is:

A. Rs. 960 B. Rs. 840 C. Rs. 1020 D. Rs. 760

Answer: Option C
Explanation T.D. = [latex]\frac {B.G. \times 100}{R \times T}[/latex] = Rs. [latex]\frac {270 \times 100}{12 \times 3}[/latex] = Rs. 750. B.D. = Rs.(750 + 270) = Rs. 1020.
Time and Work
1. A and B complete a work in 6 days. A alone can do it in 10 days. If both together can do the work in how many days?

A. 3.75 days B. 4 days C. 5 days D. 6 days

Answer: Option A
Explanation: 1/6 + 1/10 = 8/30 = 4/15 15/4 = 3.75 days
2. A work which could be finished in 9 days was finished 3 days earlier after 10 more men joined. The number of men employed was?

A. 18 B. 20 C. 22 D. 24

Answer: Option B
Explanation: x ------- 9 (x + 10) ---- 6 x * 9 = (x + 10)6 x = 20
Mixtures or Allegations
1. Two varieties of wheat - A and B costing Rs. 9 per kg and Rs. 15 per kg were mixed in the ratio 3 : 7. If 5 kg of the mixture is sold at 25% profit, find the profit made?

A. Rs. 13.50 B. Rs. 14.50 C. Rs. 15.50 D. Rs. 16.50 E. None of these

Answer: Option D
Explanation: Let the quantities of A and B mixed be 3x kg and 7x kg. Cost of 3x kg of A = 9(3x) = Rs. 27x Cost of 7x kg of B = 15(7x) = Rs. 105x Cost of 10x kg of the mixture = 27x + 105x = Rs. 132x Cost of 5 kg of the mixture = 132x/10x (5) = Rs. 66 Profit made in selling 5 kg of the mixture = 25/100 (cost of 5 kg of the mixture) = 25/100 * 66 = Rs. 16.50
2. In a mixture of milk and water, the proportion of milk by weight was 80%. If, in a 180 gm mixture, 36 gms of pure milk is added, what would be the percentage of milk in the mixture formed?

A. 80% B. 100% C. 84% D. 87.5% E. None of these

Answer: Option E
Explanation: Percentage of milk in the mixture formed = [80/100 (180) + 36] / (180 + 36) * 100% = (144 + 36)/216 * 100% = 5/6 * 100% = 83.33%.
Decimal Fraction
1. [latex]\frac {0.009}{?}[/latex] = 0.01

A. 0.0009 B. 0.09 C. 0.9 D. 9

Answer: Option C
Explanation: Let[latex]\frac {0.009}{x}[/latex] = 0.01; Then x = [latex]\frac {0.009}{0.01}[/latex] =[latex]\frac {0.9}{1}[/latex] = 0.9
2. The expression (11.98 x 11.98 + 11.98 x x + 0.02 x 0.02) will be a perfect square for x equal to:

A. 0.02 B. 0.2 C. 0.04 D. 0.4

Answer: Option C
Explanation: Given expression = (11.98)[latex]^ {2}[/latex] + (0.02)[latex]^ {2}[/latex] + 11.98 x x. For the given expression to be a perfect square, we must have 11.98 x x = 2 x 11.98 x 0.02 or x = 0.04
Average
1. The average of 11 numbers is 10.9. If the average of first six is 10.5 and that of the last six is 11.4 the sixth number is?

A. 11.0 B. 11.3 C. 11.4 D. 11.5

Answer: Option D
Explanation: 1 to 11 = 11 * 10.9 = 119.9 1 to 6 = 6 * 10.5 = 63 6 to 11 = 6 * 11.4 = 68.4 63 + 68.4 = 131.4 – 119.9 = 11.5 6th number = 11.5
2. The average of first ten prime numbers which are odd is?

A. 12.9 B. 13.8 C. 17 D. 15.8

Answer: Option D
Explanation: Sum of first 10 prime no. which are odd = 158 Average = 158/10 = 15.8
Stocks and Share
1. Find the number of shares that can be bought for Rs.8200 if the market value is Rs.20 each with brokerage being 2.5%.

A. 450 B. 500 C. 400 D. 410

Answer: Option C
Explanation: Cost of each share = (20 + 2.5% of 20) = Rs.20.5 Therefore, number of shares = 8200/20.5 = 400
2. What is the investment made if one invests in 15% stock at 50 and earns Rs.2000?

A. 8000 B. 7000 C. 5000 D. 6000

Answer: Option C
Explanation: To earn Rs.15, investment = Rs.50. Hence, to earn Rs.1500, investment = (1500*50)/15 = Rs.5000.
Square Root and Cube Root
1. 28[latex]\sqrt {x}[/latex] + 1426 =[latex]\frac {3}{4}[/latex] of 2984. Find x?

A. 659 B. 694 C. 841 D. 859

Answer: Option C
Explanation: 28[latex]\sqrt {x}[/latex]x + 1426 = [latex]\frac {3}{4}[/latex] of 2984. 28[latex]\sqrt {x}[/latex]x + 1426 =[latex]\frac {3}{4}[/latex] × 2984= 2238 28[latex]\sqrt {x}[/latex]x = 2250 – 1426 = 812 x = 29 x = 841
2. If 3[latex]\sqrt{5}[/latex] + [latex]\sqrt{125}[/latex] = 17.88, then what will be the value of [latex]\sqrt{80}[/latex] + 6[latex]\sqrt{5}[/latex] ?

A. 13.41 B. 20.46 C. 21.66 D. 22.35

Answer: Option D
Explanation: 3[latex]\sqrt{5}[/latex]+ [latex]\sqrt{125}[/latex]= 17.88 3[latex]\sqrt{5}[/latex] + [latex]\sqrt{12 \times 5}[/latex] = 17.88 3[latex]\sqrt{5}[/latex] + 5[latex]\sqrt{5}[/latex] = 17.88 8[latex]\sqrt{5}[/latex] = 17.88 [latex]\sqrt{5}[/latex] = 2.235 = [latex]\sqrt{80}[/latex] + 6[latex]\sqrt{5}[/latex] = [latex]\sqrt{16 \times 5}[/latex] + 6[latex]\sqrt{5}[/latex] = 4[latex]\sqrt{5}[/latex] + 6[latex]\sqrt{5}[/latex] = 10[latex]\sqrt{5}[/latex] = (10 x 2.235) = 22.35