**Example**: 10% = \(\frac{10}{100}\) = \(\frac{1}{10}\)

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**Answer**: Option B

**Explanation**:

Males and females are 3x and 7x respectively

(3x)*\(\frac{75}{100}\) = 18000. X = 8000

so total population = 10*8000 = 80000

\(\frac{75}{100}\)

**2. Pankaj gave 50 percent of the amount to akash. Akash in turn gave two-fifth of the amount to venu. After paying a bill of 500 rupees, venu now have 8000 rupees left with him. Find the amount hold by pankaj initially.**

**Answer**: Option B

**Explanation**:

Let pankaj have P amount initially

\(\frac{50}{100}\)*P*\(\frac{2}{5}\) â€“ 500 = 8000

P = 42500

**3. Rakesh spent 30 percent of his monthly income on food items. Of the remaining amount he spent 60 percent on clothes and bills. Now he save five-seventh of the remaining amount and the he saves 120000 yearly, then find his monthly income. **

**Answer**: Option B

**Explanation**:

Let monthly income is P

(\(\frac{70}{100}\))*P*(\(\frac{40}{100}\))*\(\frac{5}{7}\) = 10000

P = 50000

**4. Weight of A and B are in the ratio of 3:5. If the weight of A is increased by 20 percent and then the total weight becomes 132 kg with an increase of 10 percent. B weight is increased by what percent. **

**Answer**: Option C

**Explanation**:

Weight of A and B are 3x and 5x.

Initial weight before increase = \(\frac{(132*100)}{110}\) = 120

8x = 120. X = 15

Initial weight of A and B are 45 and 75 kg respectively.

New weight of A = 54 so weight of B = 132 â€“ 54 = 78.

So % increase = \(\frac{(78-75)}{75}\)*100 = 4 %

**5. When the price of rice is increased by 25 percent, a family reduces its consumption such that the expenditure is only 10 percent more than before. If 40 kg of rice is consumed by family before, then find the new consumption of family.**

**Answer**: Option B

**Explanation**:

Suppose initially price per kg of rice is 100 then their expenditure is 4000.

Now their expenditure is only increased by only 10% i.e â€“ 4400.

The increased price of rice = 125.

So new consumption = \(\frac{4400}{125}\) = 35.2

**Answer**: Option A

**Explanation**:

Let initial price of rice â€“ 100 and new price of rice â€“ 120

suppose initial consumption is 100kg and new consumption is 85kg

Initial expenditure = 10000

New expenditure = 10200

\(\frac{200}{10000}\)*100 = 2 percent increase

**2. A salary is 40 percent more than B. Bâ€™s salary is 30 percent less than C. If the difference between the salary of C and A is 1200 rupees, then what is the monthly income of C **

**Answer**: Option B

**Explanation**:

A = \(\frac{140}{100}\)*B

B = (\(\frac{70}{100}\)*C

[(\(\frac{100}{70}\)) â€“ (\(\frac{140}{100}\))]*B = 1200.

B = 42000.

C = (\(\frac{100}{70}\))*42000 = 60000

**3. When the price of rice is increased by 30 percent, a family reduces its consumption such that the expenditure is only 20 percent more than before. If 50 kg of rice is consumed by family before, then find the new consumption of family (approx.)**

**Answer**: Option D

**Explanation**:

Suppose initially price per kg of rice is 100 then their expenditure is 5000.

Now their expenditure is only increased by only 20% i.e â€“ 6000.

The increased price of rice = 130.

So new consumption = \(\frac{6000}{130}\) = 46.1

**4. One type of liquid contains 20 percent of milk and second type of liquid contains 40 percent milk. If 4 part of the first and 6 part of the second are mix, then what is the percent of water in the mixture.**

**Answer**: Option C

**Explanation**:

Do these type of question by taking 100 litre

water = 80ltr and 60ltr in first and second mixture respectively

now percent of water = (\(\frac{(80*4 + 60*6)}{1000}\))100 = 68%

**5. 40% of the students like Mathematics, 50% like English and 10% like both Mathematics and English. What % of the students like neither English nor Mathematics? **

**Answer**: Option C

**Explanation**:

n(M or E) = n(M) + n(E) â€“ n(M and E)

n(M or E) = 40+50-10 = 80

so % of the students who like neither English nor Mathematics = 100 â€“ 80 = 20%

**Answer**: Option D

**Explanation**:

Let new weight be x kg

Since the pulp is not being evaporated, the quantity of pulp should remain same in both cases. This gives

(100 – 96)% of 20 = (100 – 95)% of x

Solve, x = 16 kg

**2. If the price of wheat is reduced by 2%. How many kilograms of wheat a person can buy with the same money which was earlier sufficient to buy 49 kg of wheat? **

**Answer**: Option D

**Explanation**:

Let the original price = 100 Rs per kg

Then money required to buy 49 kg = 49*100 = Rs 4900

New price per kg is (100-98)% of Rs 100 = 98

So quantity of wheat bought in 4900 Rs is \(\frac{4900}{98}\) = 50 kg

**3. The number of seats in a cinema hall is decreased by 12 percent and the price of tickets also decreased by 4 percent. Find the change in the collection of revenue. **

**Answer**: Option A

**Explanation**:

Let initial seats = 100 and cost per seat = 100, so initial revenue = 10000

now final revenue = 88*96 = 8448

% percent change in revenue = \(\frac{(10000 â€“ 8448)}{10000}\)*100 = 15.52%

**4. A man has 2000 rupees in his account two years ago. In the first year he deposited 20 percent of the amount in his account. In the next year he deposited 10 percent of the increased amount in the account. Find the total amount in the account of the person after 2 years.**

**Answer**: Option B

**Explanation**:

2000 + 400 + 240 = 2640 (400 in first year and 240 is added in the second year)

**5. In an election contested by two parties A and B, party A secured 25 percent of the total votes more than Party B. If party B gets 15000 votes. By how much votes does party B loses the election? **

**Answer**: Option B

**Explanation**:

Let total votes = T and party B gets 15000 votes then party A will get T -15000 votes

T â€“ 15000 â€“ 15000 = \(\frac{25T}{100}\)

T = 40000, so A get 25000 and B gets 15000 votes, so difference = 10000