Introduction
Permutation and Combination is one of important topic in Quantitative Aptitude Section. In Permutation and Combination – Quiz 2 article candidates can find questions with an answer. By solving this questions candidates can improve and maintain, speed, and accuracy in the exams. Permutation and Combination – Quiz 2 questions are very useful for different exams such as IBPS PO, Clerk, SSC CGL, SBI PO, NIACL Assistant, NICL AO, IBPS SO, RRB, Railways, Civil Services etc.
Q1
From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?
- A. 21
B. 12
C. 9
D. 108
The boy can select one trouser in nine ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 [latex]\times[/latex] 12 = 108 ways.
Q2
How many three letter words are formed using the letters of the word TIME?
- A. 20
B. 16
C. 18
D. 24
The number of letters in the given word is four.
The number of three letter words that can be formed using these four letters is [latex]^{4}{P}_{3}[/latex] = 4 [latex]\times[/latex] 3 [latex]\times[/latex] 2 = 24.
Q3
Using all the letters of the word "THURSDAY", how many different words can be formed?
- A. 8
B. 8!
C. 7
D. 7!
Total number of letters = 8
Using these letters the number of 8 letters words formed is [latex]^{8}{P}_{8}[/latex] = 8!.
Q4
Using all the letters of the word "NOKIA", how many words can be formed, which begin with N and end with A?
- A. 3
B. 6
C. 24
D. 120
There are five letters in the given word.
Consider 5 blanks ....
The first blank and last blank must be filled with N and A all the remaining three blanks can be filled with the remaining 3 letters in 3! ways.
The number of words = 3! = 6.
Q5
The number of arrangements that can be made with the letters of the word MEADOWS so that the vowels occupy the even places?
- A. 720
B. 144
C. 120
D. 36
The word MEADOWS has 7 letters of which 3 are vowels.
- V - V - V -
As the vowels have to occupy even places, they can be arranged in the 3 even places in 3! i.e., 6 ways. While the consonants can be arranged among themselves in the remaining 4 places in 4! i.e., 24 ways.
Hence the total ways are 24 [latex]\times[/latex] 6 = 144.