Introduction
Ratios and Proportions is one of important topic in Quantitative Aptitude Section. In Ratios and Proportions – Quiz 1 article candidates can find questions with answers. By solving this question candidates can improve and maintain, speed, and accuracy in the exams. Ratios and Proportions - Quiz 1 questions are very useful for different exams such as IBPS PO, Clerk, SSC CGL, SBI PO, NIACL Assistant, NICL AO, IBPS SO, RRB, Railways, Civil Services etc.
Q1
A and B together have Rs. 1210. If 4/15 of A's amount is equal to 2/5 of B's amount, how much amount does B have?
- A. Rs. 460
B. Rs. 484
C. Rs. 550
D. Rs. 664
[latex]\frac{4}{15} A = \frac{2}{5} B[/latex]
[latex]\Rightarrow A = (\frac{2}{5} \times \frac{15}{4}) B[/latex]
[latex]\Rightarrow A = \frac{3}{2} B[/latex]
[latex]\Rightarrow \frac{A}{B}= \frac{3}{2} [/latex]
[latex]\Rightarrow A : B = 3 : 2 [/latex]
i.e, B's share = Rs. [latex](1210 \times \frac{2}{5}) = Rs. 484.[/latex]
Q2
A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B's share?
- A. Rs. 500
B. Rs. 1500
C. Rs. 2000
D. None of these
Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.
Then, 4x - 3x = 1000
[latex]\Rightarrow[/latex] x = 1000.
i.e, B's share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.
Q3
Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
- A. 2 : 5
B. 3 : 5
C. 4 : 5
D. 6 : 7
Let the third number be x.
Then, first number = 120% of x = [latex]\frac{120x}{100}[/latex] = [latex]\frac{6x}{5}[/latex]
Second number = 150% of x = [latex]\frac{150x}{100}[/latex] = [latex]\frac{3x}{2}[/latex]
i.e, Ratio of first two numbers = [latex]\frac{6x}{5} : \frac{3x}{2}[/latex] = 12x : 15x = 4 : 5.
Q4
Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40 : 57. What is Sumit's salary?
- A. Rs. 17,000
B. Rs. 20,000
C. Rs. 25,500
D. Rs. 38,000
Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
Then, [latex]\frac{2x + 4000}{3x + 4000} = \frac{40}{57}[/latex]
[latex]\Rightarrow[/latex] 57(2x + 4000) = 40(3x + 4000)
[latex]\Rightarrow[/latex] 6x = 68,000
[latex]\Rightarrow[/latex] 3x = 34,000
Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000.
Q5
If 0.75 : x :: 5 : 8, then x is equal to:
- A. 1.12
B. 1.2
C. 1.25
D. 1.30
(x x 5) = (0.75 x 8) [latex]\Rightarrow x = \frac{6}{5} = 1.20[/latex]