A candidate with **quantitative aptitude** knowledge will be in a better position to analyse and make sense of the given data. Quantitative Aptitude knowledge is an **important** measure for a prospective business executive’s **abilities**.

The article **SSC CPO Quantitative Aptitude Quiz 6** provides Quantitative Aptitude questions with answers useful to the candidates preparing for** Competitive exams, Entrance exams, Interviews** etc. The article **SSC CPO Quantitative Aptitude Quiz 6** will assist the students to know the expected questions from **Quantitative Aptitude**.

- A. 10 mps

B. 12 mps

C. 14 mps

D. 17 mps

**Answer**: Option A

**Explanation**:

36 \(\frac{5}{18}\) = 10 mps

**2. Express 25 mps in kmph?**

- A. 15 kmph

B. 99 kmph

C. 90 kmph

D. None

**Answer**: Option C

**Explanation**:

25 * \(\frac{18}{5}\) = 90 kmph

**3. In what time will a railway train 60 m long moving at the rate of 36 kmph pass a telegraph post on its way?**

- A. 9 sec

B. 8 sec

C. 7 sec

D. 6 sec

**Answer**: Option D

**Explanation**:

\(\frac {60}{36}\)* \(\frac {18}{5}\).

**4. A train 240 m in length crosses a telegraph post in 16 seconds. The speed of the train is?**

- A. 50 kmph

B. 52 kmph

C. 54 kmph

D. 56 kmph

**Answer**: Option C

**Explanation**:

S = \(\frac {240}{16}\) * \(\frac {18}{5}\) = 54 kmph

**5. The speed of a car is 90 km in the first hour and 60 km in the second hour. What is the average speed of the car?**

- A. 72 kmph

B. 75 kmph

C. 30 kmph

D. 80 kmph

E. None of these

**Answer**: Option B

**Explanation**:

\(\frac {(90 + 60)}{2}\) = 75 kmph

- A. 3.75 days

B. 4 days

C. 5 days

D. 6 days

**Answer**: Option A

**Explanation**:

\(\frac {1}{6}\) + \(\frac {1}{10}\) = \(\frac {8}{30}\) = \(\frac {4}{15}\)

\(\frac {15}{4}\) = 3.75 days

**2. A and B together can do a piece of work in 8 days. If A alone can do the same work in 12 days, then B alone can do the same work in? **

- A. 20 days

B. 16 days

C. 24 days

D. 28 days

**Answer**: Option B

**Explanation**:

B = \(\frac {1}{8}\) – \(\frac {1}{2}\) = \(\frac {1}{24}\) => 24 days

**3. A can do a piece of work in 4 days. B can do it in 5 days. With the assistance of C, they completed the work in 2 days. Find in how many days can C alone do it?**

- A. 10 days

B. 20 days

C. 5 days

D. 4 days

**Answer**: Option B

**Explanation**:

C = \(\frac {1}{2}\) – \(\frac {1}{4}\) – \(\frac {1}{5}\) = \(\frac {1}{20}\) => 20 days

**4. A and B can do a piece of work in 6 2/3 days and 5 days respectively. They work together for 2 days and then A leaves. In how many days after that B will complete the work alone.**

- A. 2 days

B. 1 \(\frac {1}{2}\) days

C. 3 days

D. 3 \(\frac {1}{2}\) days

**Answer**: Option B

**Explanation**:

\(\frac {3}{20}\) * 2 + \(\frac {(2 + x)}{5}\) = 1

x = 1 \(\frac {1}{2}\) days

**5. A and B can do a piece of work in 12 days and 16 days respectively. Both work for 3 days and then A goes away. Find how long will B take to complete the remaining work?**

- A. 15 days

B. 12 days

C. 10 days

D. 9 days

**Answer**: Option D

**Explanation**:

\(\frac {3}{12}\) + \(\frac { (3 + x)}{16}\) = 1

x = 9 days

- A. 18%

B. 9%

C. 15%

D. 6%

** Answer**: Option A

**Explanation**:

1500 —- 270

100 —- ? => 18%

**2. A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?**

- A. Rs.1000

B. Rs.1140

C. Rs.860

D. Rs.760

** Answer**: Option B

**Explanation**:

90%

104%

——–

14% —- 140

100% —- ? => Rs.1000

**3. A single discount equivalent to the discount series of 20%, 10% and 5% is?**

- A. 25%

B. 30%

C. 31.6%

D. 33.5%

** Answer**: Option C

**Explanation**:

100*(\(\frac {80}{100}\))*(\(\frac {90}{100}\))*(\(\frac {95}{100}\)) = 68.4

100 – 68.4 = 31.6

**4. A trader bought a car at 20% discount on its original price. He sold it at a 40% increase on the price he bought it. What percent of profit did he make on the original price?**

- A. 10%

B. 11%

C. 12%

D. 15%

** Answer**: Option C

**Explanation**:

Original price = 100

CP = 80

S = 80*(\(\frac {140}{100}\)) = 112

100 – 112 = 12%

**5. A man sells a horse for Rs.800 and loses something, if he had sold it for Rs.980, his gain would have been double the former loss. Find the cost price of the horse?**

- A. Rs.900

B. Rs.875

C. Rs.850

D. Rs.860

** Answer**: Option D

**Explanation**:

CP = SP + 1CP = SP – g

800 + x = 980 – 2x

3x = 180 => x = 60

CP = 800 + 60 = 860