Answer: Option A
Explanation:
Total cost price = 20 × 12
= 240
Total selling price = 5 × 10 + 14 × 7 + 8 × 11
= 50 + 98 + 88
= 236
Loss percent = 240 – \(\frac{236}{240}\) × 100
= 1.66%
2. Marked price of an article is Rs 300 and a discount of 20% is given. If profit percent is 20% then what is the cost price ?
Answer: Option B
Explanation:
MP = 300
SP = MP – discount
SP = 300 × \(\frac{80}{100}\)
SP = 240
Cost price = 240 × \(\frac{100}{120}\)
Cost price = Rs 200
3. Arif sold his two mobiles for Rs 5000 each without any profit or loss. If he sold one of the mobile at 20% loss then at what profit percent should he sell the other mobile ?
Answer: Option A
Explanation:
Total SP = 10000
Cost price of First mobile = 5000(\(\frac{100}{80}\))
= 6000
Selling price of Second mobile = 5000
Cost price of Second mobile = 10000 – 6000
= 4000
Profit percent = 5000 – \(\frac{4000}{4000}\) × 100
= 25%
4. A person purchased 20 apples for Rs 11 each and sold each apple at a different price,every price is between 1 and 20 both inclusive then what is his loss/profit percent?
Answer: Option A
Explanation:
Total Cost price = 20 × 11
= 220
As we have 20 different prices and 20 apples and eah apple is sold at a different price and so
Total SP = 1 + 2 + 3 + 4 ….. 20
= \(\frac{20(20 + 1)}{2}\)
= 210
Loss percent = \(\frac{220 – 210}{220}\) × 100
= \(\frac{50}{11}\)%
5.The cost price of 40 articles is the same as the selling price of 25 articles. Find the gain per cent
Answer: Option B
Explanation:
If the cost price of x articles is equal to the selling price of y articles, then the profit percentage
= \(\frac{x – y}{y}\) × 100%.
x is the number of articles the cost price of which is given = 40
y is the number of articles the selling price of which is given = 25
By the short trick approach, we get
Gain% = \(\frac{40 – 25}{25}\)4×100 = \(\frac{15}{25}\) × 100= 60%
Answer: Option A
Explanation:
\(\frac{(x + y)}{100 – y}\) × 100%
where x = gain% after allowing the discount = 17%,
And y = discount offered on marked price = 10%
Now, on putting values of x and y in the short trick approach, we get
= \(\frac{17 + 10}{100 – 10}\) × 100 = \(\frac{27}{90}\) × 100 = 30%.
2. Cost price of 100 books is equal to the selling price of 60 books. The gain percentage or loss percentage is:
Answer: Option D
Explanation:
To solve this question, now we can apply a short trick approach
Gain% or Loss% = \(\frac{x – y}{y}\) × 100%
x is the number of books the cost price of which is given = 100
y is the number of books the selling price of which is given = 60
By the short trick approach, we get
Gain percentage = \(\frac{100 – 60}{60}\) × 100% = \(\frac{40}{60}\) × 100%
= 66 \(\frac{2}{3}\)%.
3. List price of a book is Rs 100. A dealer sells three such books for Rs 274.50 after allowing discount at a certain rate. Find the rate of discount.
Answer: Option A
Explanation:
Discount% = CP – SP × 100%
CP = \(\frac{300 – 274.50 }{300}\) × 100 = \(\frac{25.50}{3}\) = 8.5%.
4. The printed price of an article is 40% higher than its cost price. Then the rate of discount so that he gains 12% profit is:
Answer: Option C
Explanation:
Let’s assume CP = 100, therefore MP = 140 and SP = 112.
Discount% = \(\frac{MP – SP}{MP}\) × 100%
{As discount is always calculated on Marked Price.}
= \(\frac{140 – 112}{140}\) × 100 = \(\frac{28 × 100}{140}\) = 20%.
5. Mohan sold his watch at 10% loss. If he had sold it for Rs. 45 more, he would have made 5% profit. The selling price (in Rs.) of watch was
Answer: Option D
Explanation:
Let the original SP = x
Therefore, new SP = (x + 45)
New SP = \(\frac{100 + Profit%}{100 – Discount%}\) × old SP
⇒ \(\frac{(x + 45)}{100 – 10}\) = 100 + 5 × x
⇒ \(\frac{(x + 45)}{90}\) = 105 × x
⇒ 90x + 90 × 45 = 105x
⇒ 15x = 90 × 45 ⇒ x = \(\frac{90 × 45}{15}\) = 270.
Answer: Option C
Explanation:
Given,
In case of loss,
36 CP – 36 SP = 4 SP
⇒ 36 CP = 40 SP
To solve this question now, we can apply a short trick approach
Gain% or Loss% = \(\frac{x – y}{y}\) × 100%
x is the number of oranges the cost price of which is given = 36
y is the number of oranges the selling price of which is given = 40
By the short trick approach, we get
Loss% = \(\frac{36 – 40}{40}\) × 100% = \(\frac{–4}{40}\) × 100% = – 10%.
2.The total discount on Rs. 1860 due after a certain time at 5% is Rs. 60. Find the time after which it is due
Answer: Option C
Explanation:
Amount (A) = 1860/-, True Discount = 60/-, Rate of interest (R) = 5%
Time (T) = 100 ×\(\frac{TD}{(A – TD) × R}\) = 100 × \(\frac{60}{(1860 – 60) × 5 1800 × 5}\)
⇒ T = \(\frac{100 × 60}{3}\) = 2 years
Total months = \(\frac{12 × 2}{3}\) = 8 months.
3. Simon purchased a bicycle for Rs. 6810. He had paid a VAT of 13.5%. The list price of the bicycle was
Answer: Option C
Explanation:
let’s take the original price (list price) of the bicycle be x, then
113.5% of x = 6810 ⇒ x = \(\frac{6810 × 100}{113.5}\) = \(\frac{6810 × 1000}{1135}\) = 6000/-
4. There is 10% loss if an article is sold at Rs. 270. Then the cost price of the article is
Answer: Option B
Explanation:
let’s take CP = x, then
90% of x = 270 ⇒ x = \(\frac{270 × 100}{90}\) = 300/-
5. An article is sold at a gain of 15%. Had it been sold for ₹ 27 more, the profit would have been 20%. The cost price of the article is
Answer: Option C
Explanation:
Let the CP of article be Rs x, then
120% of x – 115% of x = 27
⇒ 5% of x = 27
⇒ x = \(\frac{27 × 100}{5}\) = Rs. 540
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