Time and distance as a topic involves a variety of areas which include speed-time-distance concepts, relative speed, moving and stationary bodies, boats and streams, circular motion, and so on. **Time and Distance Practice Quiz** article is useful for candidates preparing for different competitive examinations like RRB ALP/Technical Exams/Junior Engineer Recruitment Exams, SSC, IBPS PO Exams and etc.

**Answer**: Option A

**Explanation**: \( {x}^{2}\) = \( {24}^{2}\) + \( {18}^{2}\)

= 576 + 324 = 900

i.e, x = \(\sqrt {900}\) = 30 km

**2. A man goes from Delhi to Dehradun. Half the distance he covers by bus at an average speed of 50 km/hr and the other half by train at an average speed of 70 km/hr. The average speed for the whole journey was **

**Answer**: Option D

**Explanation**:

v – bar = \(\frac {2uv} {u + v}\) = \(\frac {2 * 50 * 70} {50 + 70}\) =\( 58 \frac {1} {3}\)

**3. A man covers a distance of 100 km partly by bus at 40 km/hr and partly by scooter at 30 km/hr. His average speed for the whole journey was 32 km/hr. How far did he go by bus?**

**Answer**: Option B

**Explanation**:

\(\frac {x km (100 – x) km} {@ 40kph @ 30 lph}\)

Average speed = \(\frac {Total distance} {Total time}\)

i.e, 32 = \(\frac {100} {\frac {x}{40} – \frac {100 – x}{30}}\)

x = 25 km

**4. A person shooting at a target from a distance of 450 metres finds that the sound of the bullet hitting the target comes \(\frac {1} {2}\) seconds after he fired. A person equidistant from the target and shooting point hears the bullet hit 3 seconds after he heard the gun. The speed of sound is**

**Answer**: Option A

**Explanation**:

v – bar = \(\frac {450m} {1s\frac{1}{2}}\) = 300 m/s

**5. A monkey climbs a slippery pole 12 m high. It rises 1 meter in every one minute and slip \(\frac {1} {2}\) meter in every next minute. Find how soon it will reach the top?**

**Answer**: Option A

**Explanation**:

Average speed = 1 meter/ 4 minutes

For 11 m, time taken = 44 minutes

For last 1 m, jump add 1 minutes

i.e, Time taken = 45 minutes

and start at the same time, reaches his school 10 minutes. early. How far is the school from his house?

**Answer**: Option B

**Explanation**:

\(\frac {d} {4} – \frac {d}{5}\) \(\frac {15} {60}\)

\(\frac {5d – 4d} {20}\) = \(\frac {15} {60}\)

\(\frac {d} {20}\) = \(\frac {1} {4}\)

d = 5 km

**7. A train starts from Delhi with a certain number of passengers. At Ghaziabad 110 get down and 100 get in. At Aligrah 50% get down and 25 get in. At Kanpur 5 half of them get down and 50 get in. When t he t r ai n leaves Kanpur there are 200 passengers. How many did board the train at Delhi?**

**Answer**: Option C

**Explanation**:

Let there were n passengers at Delhi.

n = Delhi, \(\frac {n} {10} + 10 \) = Ghaziabad, \(\frac {n} {20} + 50 + 25 \) = Aligarh, \(\frac {n} {40} + \frac {75} {2} + 50 \) = Kanpur (200)

\(\frac {n} {40} + \frac {75} {2} + 50 \) = 200

n = 500

**8. The radius of a circular wheel is 35 cm and it moves at the rate of 500 revolutions per minute. The speed of wheel is**

**Answer**: Option D

**Explanation**:

Speed = 500 rpm

= 500 * 2 * \(\frac {22} {7}\) * \(\frac {35} {100}\) * 60 * \(\frac {1} {100}

\) = 66 km/hr

**9. Diameter of the front wheel and hind wheel of a van are 70 cm and 98 cm respectively. How many more revolutions the front wheel will make when the hind wheel in going over a distance of 154 kms?**

**Answer**: Option C

**Explanation**:

\( {n}_{1} {c}_{1}\) = 154 km

i.e, \({n}_{1}\) * \(\frac {22} {7}\) * 70 cm = 15400000 cm

\({n}_{1}\) = 70000

and \( {n}_{1} {c}_{2}\) = 154 km

i.e, \({n}_{2}\) * \(\frac {22} {7}\) * 98 cm = 15400000 cm

\({n}_{2}\) = 50000

i.e, \( {n}_{1} – {n}_{2}\) = 20000 cm

**10. Two men X and Y start from a place P, walking at 3 km/hr, and 4 km/hr. By how much distance apart they will be after 4 hours if they are walking in the same direction?**

**Answer**: Option A

**Explanation**:

d = v * t = (4 – 3) * 4 = 4 km

**Answer**: Option A

**Explanation**:

d = (4 + 3) * 5 = 35 km

**12. A person has to make a journey of 72 km. He rides a cycle at 12 kms/hr. After going certain distance, the cycle got punctured and he walks the remaining distance at \( 4 \frac {1} {2}\) km/hr. Where did the cycle got punctured if total time taken for the journey was \( 8 \frac {1} {2}\) hours?**

**Answer**: Option B

**Explanation**:

\( 8 \frac {1} {2}\) = \(\frac {x} {12}\) + \(\frac {72 – x} {4 \frac {1}{2}}\)

x = 54 km

**13. A car is stolen at 4.00 a.m the thief drives it towards north at a speed of 50 k m/hr. The theft is discovered at 4.30 a.m. and a police jeep is set towards north at 60 kms/hr. At what time did the jeep will overtake the car?**

**Answer**: Option B

**Explanation**:

\( \frac {d} {50} – \frac {d} {60}\) = \( \frac {1} {2}\)

\( \frac {d} {300}\) = \( \frac {1} {2}\)

d = 150

i.e, t = \( \frac {150} {50}\) = 3 hrs

Hence jeep will overtake the car at 7.00 a.m.

**14. A student goes to his school from his house walking at 4 km/hr. and reaches his school 10 min. late Next day starting at same the time he walks at 6 km/ hr and reaches his school 15 minutes early. How far is the school from the house?**

**Answer**: Option B

**Explanation**:

\( \frac {d} {4} – \frac {d} {6}\) = \( \frac {25} {60}\)

\( \frac {3d – 2d} {12}\) = \( \frac {5} {12}\)

d = 5 km

**15. A train traveled from A to B and back in a certain time at the rate of 60 km/hr. But if the train had traveled from A to B at the rate of 80 km/hr. and back from B to A at the rate of 40 km/hr it would take two hour longer. The distance bet ween A and B is**

**Answer –** Option A

**Explanation –**

\( \frac {d} {80} – \frac {d} {40}\) = \( \frac {d} {60} + \frac {d} {60}\) = 2

\( \frac {3d + 6d -4d -4d} {240} \) 2

\( \frac {d} {240}\) = 2

d = 480

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