A candidate with **quantitative aptitude** knowledge will be in a better position to analyse and make sense of the given data. Quantitative Aptitude knowledge is an **important** measure for a prospective business executive’s **abilities**.

The article **IBPS RRB PO Quantitative Aptitude Quiz 8** provides Quantitative Aptitude questions with answers useful to the candidates preparing for** Competitive exams, Entrance exams, Interviews** etc. **IBPS RRB** has released **IBPS RRB Officer 2019 **Official Notification for Officer Scale(I, II, and II). Quantitative Aptitude plays major role to qualify examination. The article **IBPS RRB PO Quantitative Aptitude Quiz 8** will assist the students to know the expected questions from **Quantitative Aptitude**.

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**Answer**: Option D

**Explanation**:

Sum of ages is 360 years.The ratio of children and parents ages is 2:1.

Total age of parents = 360 x \(\frac{1}{3}\) = 120 years

Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x \(\frac{7}{12}\) = 70

Hence the age of husband is 70 years.

**2. The ratio between the present ages of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years?**

**Answer**: Option B

**Explanation**:

Let A’s age and B’s age be 6X years and 7X years respectively

Then, 7X – 6X = 4

X = 4

Required ratio = (6X + 4) : (7X + 4) = (6*4 + 4) : (7*4 + 4) =28 : 32 = 7 : 8

**3. Sush was thrice as old as Poonam 6 years back. Sush will be 5/3 times as old as Poonam 6 years hence. How old is Poonam today?**

**Answer**: Option C

**Explanation**:

Let Poonam age 6 years back = x.

Then, Sush age 6 years back = 3x.

(5/3) * (X + 6 + 6) = (3X + 6 + 6)

So 5(x + 12) = 3(3x + 12),

so x = 6.

Poonam Age = (x + 6) years = 12 years

**4. Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years?**

**Answer**: Option B

**Explanation**:

Let the present ages of Simmi and Anu be 5x years and 4x years respectively

Then, \(\frac{[5X + 3]}{[4X + 3]}\) = \(\frac{11}{9}\)

x = 6

Anu’s present age = 4X = 24 years

**5. If 6 years are subtracted from the present age of Anuj and the remainder is divided by 18, then the present age of his grandson Gopal is obtained.If Gopal is 2 years younger to Mohan whose age is 5 years, then what is the age of Anuj?**

**Answer**: Option B

**Explanation**:

Let Anuj’s age be X

Gopal is 2 years younger than Mohan, so Gopal is 3 years (i.e 5 – 2 = 3)

If Arun had born 6 years before, his age would had been X – 6. As per the question, X – 6 should be 18 times as that of Gokul’s age.

i.e. \(\frac{(X – 6)}{18}\) = 3

X – 6 = 3 x 18

x = 60

**Answer**: Option B

**Explanation**:

Total age of 5 members, 3 years ago = (17 x 5) years = 85 years

Total age of 5 members now = (85 + 3 x 5) years = 100 years

Total age of 6 members now = (17 x 6) years = 102 years

Age of the baby = (102 – 100) years = 2 years

**2. Of the four numbers, the first is twice the second, the second is one-third of the third and the third is 5 times the fourth. The average of the numbers is 24.75. The largest of these numbers is:**

**Answer**: Option D

**Explanation**:

Let the fourth number be a

then hen, third number = 5a, second number = \(\frac{5a}{3}\) and first = \(\frac{10a}{3}\)

a+ 5a+ \(\frac{5a}{3}\) + \(\frac{10}{3}\) = 24.75 x 4

so, a = 9

So, the numbers are 9, 45, 15 and 30

**3. The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ratio of the number of boys to the number of girls in the class is:**

**Answer**: Option B

**Explanation**:

Let the ratio be k:1

Then, k x 16.4 + 1 x 15.4 = (k + 1) x 15.8

(16.4 – 15.8) k = (15.8 – 15.4)

k = \(\frac{2}{3}\)

**4. The average price of 10 books is Rs. 12 while the average price of 8 of these books is Rs. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?**

**Answer**: Option C

**Explanation**:

Total ages of 30 boys = 14 x 30 = 420 years

Total age when class teacher is included = 15 x 31 = 465 years

Age of class teacher = 465 – 420 = 45 years

**5. The average age of 30 boys of a class is equal to 14 years. When the age of the class teacher is included the average becomes 15 years. Find the age of the class teacher?**

**Answer**: Option B

**Explanation**:

Let Anuj’s age be X

Gopal is 2 years younger than Mohan, so Gopal is 3 years (i.e 5 – 2 = 3)

If Arun had born 6 years before, his age would had been X – 6. As per the question, X – 6 should be 18 times as that of Gokul’s age.

i.e. \(\frac{(X – 6)}{18}\) = 3

X – 6 = 3 x 18

x = 60

**Answer**: Option B

**Explanation**: a + b = 6

5x × 3x = 3375

15\({x}^{2}\) = 3375

\({x}^{2}\) = \(\frac{3375}{15}\) = 225

x = 15

3x = 3*15 = 45

**2. The perimeter of a square is twice the perimeter of a rectangle. If the perimeter of a square is 48cms and the length of the rectangle is 7cm. Find the breadth of the rectangle? **

**Answer**: Option A

**Explanation**:

P of Square = 4a = 48

A = \(\frac{48}{4}\) = 12cm

P of rectangle = \(\frac{48}{2}\) = 24cm = 2( l + b)

2(7 + b) = 24

B = 12-7 = 5

**3. The area of a square is 7sqm less than half of the area of a rectangle. The length of the rectangle is 14m and breadth is 6m less than its length. What is the perimeter of the square ?**

**Answer**: Option A

L = 14, b = 8

L*b = 14*8 = 112

Area of square = (\(\frac{112}{2}\)) – 7 = 56-7 = 49

A = 7

Perimeter = 4a = 4*7 = 28cm

**4. A cow is tethered to a peg with 7m long rope at the corner of a 35m long and 20m wide rectangular grass field, What area of the field will the cow graze ?**

**Answer**: Option A

**Explanation**:

A = \(\frac{1}{4}\)(3.14r2) = \(\frac{3.14*7*7}{4}\) = 38.47\({m}^{2}\)

**5. Inside a square plot a circular garden is developed which exactly fits in the square plot and the diameter of the garden is equal to the side of the square plot which is 14m. What is the area of space left out in the square plot after developing the garden ?**

**Answer**: Option C

**Explanation**:

area of space left = 14*14 – (3.14*7*7)

= 196 – 153.86

= 42.14 = 42\({m}^{2}\)