**Example**: 10% = \(\frac{10}{100}\) = \(\frac{1}{10}\)

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**Answer**: Option D

**Explanation**:

Total maximum marks = 100 + 120 + 150 = 370

Total marks in History and English = 95 + 80 = 175

Total marks required by her to get 70% = 370 Ã— 70% = 259

So, she needs 259 â€“ 175 = 84 marks to scoring 70%.

**2. What percentage of the whole week does Pirkandu spend in office, if his office hours are 9 am to 5 pm from Monday to Friday?
**

**Answer**: Option A

Total number of hours in a week = 24 Ã— 7 hrs

Hours spend by Pirkandu = 5 Ã— 8 hrs

Required percentage = \(\frac{5 Ã— hrs }{24 Ã— 7 hrs}\)

= 23.80%

**3. Anuj and Meetu work in a shop and Anuj’s salary is 5/6th of the salary of Meetu. They spend same money of Rs 2000 and after that save all the money. Find the salary of Anuj and Meetu if the ratio of their savings is 4 : 5.
**

**D. ** Rs. 11000, Rs 8000

**Answer**: Option A

**Explanation**:

Let Meetu’s salary = Rs x

Anuj’s salary = Rs \(\frac{5x }{6}\)

According to the question,

\(\frac{5x }{6}\) â€“ 2000 : x â€“ 2000 = 4 : 5

5 (\(\frac{5x }{6}\) â€“ 2000) = 4 (x â€“ 2000)

\(\frac{25x }{6}\) â€“ 10000 = 4x â€“ 8000

\(\frac{25x }{6}\) â€“ 4x = 10000 â€“ 8000

\(\frac{x }{6}\) = 2000

x = 12000

**4. The price of two apples X and Y are in the ratio of 2 : 3. X’s price increased by 20% and the total price of X and Y together becomes Rs 175.5, with an increase of 17%. By what percent the price of Y increased?
**

**B.** 25%

**C.** 20%

**D. ** 15%

**Answer**: Option D

**Explanation**:

After increment price of X and Y together = Rs 175.5

Price before increment =\(\frac{175.5 }{117}\) Ã— 100 = Rs 150

Price of apple X = \(\frac{150 }{5}\)Ã— 2 = Rs 60

Price of apple Y = \(\frac{150 }{5}\)Ã— 3 = Rs 90

X’s price increased by 20%, X’s price = 60 Ã— 120% = Rs 72

Y’s new price = Rs.(175.5 â€“ 72) = Rs.103.5

Y’s price increased by \(\frac{103.5 â€“ 90 }{90}\) Ã— 100 = 15%

**5. A man earns x% on the first Rs. 2,000 and y% on the rest of his income. If he earns Rs. 700 from Rs. 4,000 and Rs. 900 from Rs. 5,000 of income, find x%.
**

**B.** 25%

**C.** 15%

**D. ** Can’t be determined

**Answer**: Option C

**Explanation**:

As per the given information, two equations can be written

2000 \(\frac{x }{100}\) + 2000 \(\frac{y }{100}\) = 700

2000 \(\frac{x }{100}\) + 2000 \(\frac{y }{100}\) = 900

The equations can be simplified to

x + y = 35

and 2x + 3y = 90.

After Solving this equation, we get

x = 15%

**B.** 47% increase

**C.** 52% increase

**D. ** 32% increase

**Answer**: Option A

**Explanation**:

Suppose the production of the company in the year 1994 be x.

Then production of the company in the year 1998

x Ã— \(\frac{115 }{100}\) X \(\frac{115 }{100}\) X \(\frac{90 }{100}\) X \(\frac{115 }{100}\) = = 1.368x

âˆ´ Increase % in the production in the year 1998

\(\frac{(1.368x â€“ x) Ã— 100 }{X}\) = 36.8% â‰ˆ 37%

**7. After decreasing 24% in the price of an article costs Rs.912. Find the actual cost of an article?**

**B.** 1300

**C.** 1200

**D. ** 1100

**Answer**: Option C

**Explanation**:

CP* (\(\frac{76 }{100}\) ) = 912

CP= 12 * 100 => CP = 1200

**8. Sohan spends 23% of an amount of money on an insurance policy. 33% on food, 19% on children’s education and 16% on recreation. He deposits the remaining amount of Rs. 504 in bank. How much total amount does he spend on food and insurance policy together?
**

**B.** Rs. 3126

**C.** Rs. 3136

**D. ** Rs. 3048

**Answer**: Option C

**Explanation**:

Let the total amount be â‚¹ x

Total expenditure = (23 + 33 + 19 + 16)% = 91%

Remaining money = (100 â€“ 91)% % of x = 504 â‡’ 9% of x = 504

X = \(\frac{504 Ã— 100 }{9}\) = Rs. 5600

Now, total money (food + insurance)% = (23 + 33)% of x = 56% of x

= 56% of 5600 = Rs. 3136.

**9. Out of his total income, Mr Kapoor spends 20% on house rent and 70% of the rest on household expenses. If he saves Rs. 1800 what is his total income (in rupees)?
**

**B.** Rs. 7000

**C.** Rs. 8000

**D. ** Rs.. 7500

**Answer**: Option D

**Explanation**:

100/-

â†“ â€“ 20%

80

â†“ â€“ 70%

24 (save)

Now, 24 â‰¡ 1800

Let the total income be 100, then

24 â‰¡ 1800

100 â‰¡ x

By the cross multiplication, we get

x = \(\frac{1800 Ã— 100 }{24}\) = 7500/-

**10. The price of an article is first increased by 20% and later on, it is decreased by 25% due to the reduction in sales. Find the net percentage change in the final price of the article.
**

**B.** 18%

**C.** 38%

**D. ** 10%

**Answer**: Option D

**Explanation**:

Net percentage change = 20 â€“ 25 â€“ \(\frac{25 Ã— 20 }{100}\)

= 20 â€“ 25 â€“ 5 = â€“10%

**D. ** 250

**Answer**: Option B

**Explanation**:

Let the maximum marks be x.

Putting the given info in th eq. form, we get pass marks = (20% of x) + 10 = (42% of x) â€“ (12% of x)

â‡’ (20% of x) + 10 = (30% of x)

â‡’ (30% of x) â€“ (20% of x) = 10

â‡’ 10% of x = 10

âˆ´ x = 100 marks

**12. Manish spends 17% of his monthly income in traveling. He spends 25% of his monthly income on household expenses and spends 36% of his monthly income on family medical expenses. He has the remaining amount of Rs. 10032 as cash with him. What is Manish’s annual income?
**

**B.** Rs. 536500

**C.** Rs. 547200

**D. ** Can’t be determined

**Answer**: Option C

**Explanation**:

Let Manish’s monthly income be Rs. 100.

Total expenditure = (17 + 25 + 36)% = 78%

âˆ´ Savings = (100 â€“ 78)% of 100 = Rs. 22

Now, 22 : 100 : : 10032 : x

x = \(\frac{100 Ã— 10032 }{22}\) = Rs. 45600

Manish’s monthly income = Rs. 45600

âˆ´ Manish’s annual income = Rs. 12 Ã— 45600 = Rs. 547200

**13. Rahul spends 50% of his monthly income on household items, 20% of his monthly income on buying clothes, 5% of his monthly income on medicines and the remaining amount of Rs. 11250 he saves. What is Rahul’s monthly income?
**

**B.** Rs. 34000

**C.** Rs. 41600

**D. ** Rs. 45000

**Answer**: Option D

**Explanation**:

Let the monthly income of Rahul be Rs. x.

Total expenditure = (50 + 20 + 5)% of x = 75% of x

Now, savings = (100 â€“ 75)% of x = 11250

â‡’ 25% of x = 11250

\(\frac{X }{4}\) = 11250

â‡’ x = 4 Ã— 11250 = Rs. 45000

**14. Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?**

**C.** 65%

**D. ** 90%

**Answer**: Option A

**Explanation**:

Total number of votes polled = (1136 + 7636 + 11628) = 20400.

[\(\frac{11628 }{20400}\) X 100]% = 57%

**15. If y exceeds x by 20%, then x is less than y by?**

**B.** 16 \(\frac{1 }{3}\)%

**C.** 16 \(\frac{2 }{3}\)%

**D. ** 16 \(\frac{3 }{5}\)%

**Answer**: Option C

**Explanation**:

X=100 y=120

120——20

100——-? => 16 \(\frac{2 }{3}\)%