**Example**: 10% = \(\frac{10}{100}\) = \(\frac{1}{10}\)

**Percentages** is one of the important topic in the **Quantitative Aptitude** section. The article **SSC CPO Percentages Quiz 3** consists of different models of questions with answers useful for candidates preparing for different competitive examinations like **RRB ALP/Technical Exams/Junior Engineer Recruitment Exams, SSC, IBPS PO** Exams and other examinations across the globe that include **Quantitative Aptitude section**. Prepare better for all exams with this **SSC CPO Percentages Quiz 3** for SSC CGL & Railways. This **SSC CPO Percentages Quiz 3** for SSC, Railways Exams will help you learn concepts of mensuration. Candidates can check the daily updates on **SSC Official Website**.

**Answer**: Option D

**Explanation**:

Let us assume that Arun uses X units of petrol everyday.

So the amount of petrol in the tank when it is fuel will be 10X.

If he started using 25% more petrol every day, then the amount of petrol he how uses everyday will be

X (1 +25/100) =1.25x

Therefore, number of days his petrol will how last = Amount of petrol in tank / amount of petrol used everyday = 10x/1.25x = 10/1.25 = 8 Days

**2. In an examination, every candidate took physics or mathematics or both 65.8% took physics and 59.2% took mathematics the total number of candidates was 2000. How many candidates took both physics and mathematics?
**

**Answer**: Option B

Let the marks of each question be 10

Let x% candidates take both the subjects.

Therefore, Percentage of candidates who opted physics = 65.8%

And percentage of candidates who opted mathematics = 59.2%

Therefore, x =(65.8 + 59.2 – 100)%

= (125 -100)% = 25%

Also total number of candidates = 2000

Therefore, Number of candidates who opted both the subjects = 25/100 x 2000 =500

**3. In a survey it was found that 80% of those surveyed owned a car while 60% of those surveyed owned a mobile phone, if 55% owned both a car and a Mobile phone, What percent of those surveyed owned a car or a mobile phone or both?
**

**D. ** 97.5%

**Answer**: Option C

**Explanation**:

Given that percentage of car owners = 80%

Percentage of mobile phone owners = 60%

Percentage of people having both car and mobile phone = 55%

Percentage of people having only car = 80 -55 = 25%

Percentage of people having only mobile phone = 60 -55 =5%

Percentage of people having car or mobile phone or both = 55% + 25% + 5% = 85%

**4. In a college Anjana scored 80 marks out of 150 in History and 95 marks out of 120 in English. If she wants to score 70% marks in 3 subjects, find the minimum marks she should score in Geography out of 100.**

**B.** 55

**C.** 76

**D. ** 84

**Answer**: Option D

**Explanation**:

Total maximum marks = 100 + 120 + 150 = 370

Total marks in History and English = 95 + 80 = 175

Total marks required by her to get 70% = 370 × 70% = 259

So, she needs 259 – 175 = 84 marks to score 70%.

**5. Shobha’s Mathematics test had 75 problems i.e. 10 arithmetic, 30 algebra and 35 geometry problems. Although she answered 70% of the arithmetic, 40% of the algebra and 60% of the geometry problems correctly, she did not pass the test because she got less than 60% of the problems right . How many more question she would have needed to answer correctly to earn a 60% passing grade?**

**B.** 4

**C.** 5

**D. ** 7

**Answer**: Option C

**Explanation**:

Number of questions attempted correctly = (70% of 10 + 40% of 30 + 60% of 35 )

⇒ (7 + 12 + 21) = 40.

Questions to be answered correctly for 60% grade = 60% of 75 = 45 .

So, Required number of questions = (45 – 40) = 5.

**B.** 100

**C.** 50

**D. ** 250

**Answer**: Option B

**Explanation**:

Let the maximum marks be x.

Putting the given info in th eq. form, we get pass marks = (20% of x) + 10 = (42% of x) – (12% of x)

⇒ (20% of x) + 10 = (30% of x)

⇒ (30% of x) – (20% of x) = 10

⇒ 10% of x = 10

∴ x = 100 marks

**7. Rahul spends 50% of his monthly income on household items, 20% of his monthly income on buying clothes, 5% of his monthly income on medicines and the remaining amount of Rs. 11250 he saves. What is Rahul’s monthly income ?
**

**B.** Rs. 34000

**C.** Rs. 41600

**D. ** Rs. 45000

**Answer**: Option D

**Explanation**:

Let the monthly income of Rahul be Rs. x.

Total expenditure = (50 + 20 + 5)% of x = 75% of x

Now, savings = (100 – 75)% of x = 11250

⇒ 25% of x = 11250

⇒ \(\frac{x}{4}\)

= 11250

⇒ x = 4 × 11250 = Rs. 45000

=

**8. The price of an article is first increased by 20% and later on it is decreased by 25% due to reduction in sales. Find the net percentage change in final price of the article.**

**B.** 18%

**C.** 38%

**D. ** 10%

**Answer**: Option D

**Explanation**:

Net percentage change = 20 – 25 – 25 × 20 /100

100

= 20 – 25 – 5 = –10%

Valid votes = (\(\frac{80}{100}\) × 7500) = 6000

**9. If the difference of 35% of a number and 25% of the same number is 240 then find the 150% of that number.**

**B.** 3000

**C.** 2400

**D. ** 3600

**Answer**: Option D

**Explanation**:

35% of x – 25% of x = 240

10% of x = 240

∴ x = \(\frac{240 × 100}{10}\) = 2400

Now, \(\frac{150}{100}\)of 2400 = 150 × 2400 = 3600

**10. A salesman’s terms were changed from a flat commission of 5% on all his sales to a fixed salary of Rs.1000 plus 2.5% commission on all sales exceeding Rs. 4,000. If his remuneration as per new scheme was Rs. 600 more than that by the previous schema, his sales were worth?
**

**B.** Rs. 12,000

**C.** 52 kg

**D. ** Rs. 40,000

**Answer**: Option B

**Explanation**:

[1000 + (X-4000) * (\(\frac{2.5}{100}\))] – X * (\(\frac{5}{100}\)) = 600

X = 12000

**D. ** 5500

**Answer**: Option C

**Explanation**:

X * (\(\frac{95 }{100}\)) * (\(\frac{85 }{100}\)) = 3553

X = 4400

**12. In a factory, there are 40% technicians and 60% non-technicians. If the 60% of the technicians and 40% of non-technicians are permanent employees, then the percentage of workers who are temporary is?
**

**B.** 42%

**C.** 52%

**D. ** 62%

**Answer**: Option C

**Explanation**:

Total = 100

T= 40 NT= 60

40*(\(\frac{60}{100}\))=24 60*(\(\frac{40}{100}\))=24

24 + 24 = 48 => 100 – 48 = 52%

**13. A mixture of 70 liters of wine and water contains 10% water. How much water must be added to make water 12 ½% of the total mixture?
**

**B.** 10 liters

**C.** 4 liters

**D. ** 2 liters

**Answer**: Option D

**Explanation**:

70 * (10/100) = 7

Wine Water

87 \(\frac{1}{2}\)% 12 latex]\frac{1}{2}[/latex]%

87 latex]\frac{1}{2}[/latex]% ——- 63

12 latex]\frac{1}{2}[/latex]% ——-? => 9-7=2

**14. The amount of water (in ml) that should be added to reduce 9 ml. Lotion, containing 50% alcohol, to a lotion containing 30% alcohol, is?**

**C.** 5

**D. ** 6

**Answer**: Option D

**Explanation**:

4.5 4.5

30% 70%

30% —– 4.5

70% ——? => 10.5 – 4.5 = 6 ml

**15. The tax on a commodity is diminished by 20% but its consumption is increased by 10%. Find the decrease percent in the revenue derived from it?**

**B.** 18%

**C.** 15 %

**D. ** 12 %

**Answer**: Option D

**Explanation**:

100 * 100 = 10000

80 * 110 = 8800

10000——- 1200

100 ——- ? = 12%