A candidate with **quantitative aptitude** knowledge will be in a better position to analyse and make sense of the given data. Quantitative Aptitude knowledge is an **important** measure for a prospective business executive’s **abilities**.

The article **TS CAB Recruitment Quantitative Aptitude Quiz 6** provides Quantitative Aptitude questions with answers useful to the candidates preparing for** Competitive exams, Entrance exams, Interviews** etc. The article **TS CAB Recruitment Quantitative Aptitude Quiz 6** will assist the students to know the expected questions from **Quantitative Aptitude**.

- A. 3 months

B. 4 months

C. 6 months

D. 8 months

**Answer**: Option B

**Explanation**:

S.I. on Rs. 1600 = T.D. on Rs. 1680.

Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is on Rs. 1600 at 15%.

Time = \(\frac {(100 × 80}{1600 × 15}\)year = \(\frac {1}{3}\) year = 4 months.

**2. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:**

- A. Rs. 1 : 3

B. 3 : 2

C. 3 : 4

D. None of these

**Answer**: Option B

**Explanation**:

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, the length of the first train = 27x meters,

and length of the second train = 17y meters.

z = \(\frac {27x + 17y}{x+ y}\) = 23

27x + 17y = 23x + 23y

4x = 6y

\(\frac {x}{y}\) = \(\frac {3}{2}\)

**3. In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?**

- A. 160

B. 175

C. 180

D. 195

**Answer**: Option D

**Explanation**:

Let the number of hens be x and the number of cows be y.

Then, x + y = 48 …. (i)

and 2x + 4y = 140 x + 2y = 70 …. (ii)

Solving (i) and (ii) we get: x = 26, y = 22.

The required answer = 26.

**4. A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.**

- A. 2 hours

B. 3 hours

C. 4 hours

D. 5 hours

**Answer**: Option C

**Explanation**:

Speed downstream = (13 + 4) km/hr = 17 km/hr.

Time taken to travel 68 km downstream = \(\frac {68}{17}\) hrs = 4 hrs

**5. A man’s speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man’s speed against the current is:**

- A. 8.5 km/hr

B. 9 km/hr

C. 10 km/hr

D. 12.5 km/hr

**Answer**: Option C

**Explanation**:

Man’s rate in still water = (15 – 2.5) km/hr = 12.5 km/hr.

Man’s rate against the current = (12.5 – 2.5) km/hr = 10 km/hr.

- A. Rs. 500

B. Rs. 1500

C. Rs. 2000

D. None of these

**Answer**: Option C

**Explanation**:

Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.

Then, 4x – 3x = 1000

x = 1000.

B’s share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.

**2. The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:**

- A. 17 kg

B. 20 kg

C. 26 kg

D. 31 kg

**Answer**: Option D

**Explanation**:

Let A, B, C represent their respective weights. Then, we have:

A + B + C = (45 x 3) = 135 …. (i)

A + B = (40 x 2) = 80 …. (ii)

B + C = (43 x 2) = 86 ….(iii)

Adding (ii) and (iii), we get: A + 2B + C = 166 …. (iv)

Subtracting (i) from (iv), we get : B = 31.

B’s weight = 31 kg.

**3. 1, 4, 9, 16, 20, 36, 49**

- A. 1

B. 9

C. 20

D. 49

**Answer**: Option C

**Explanation**:

The pattern is \({1}^{2}\), \({2}^{2}\), \({3}^{2}\), \({4}^{2}\), \({5}^{2}\), \({6}^{2}\), \({7}^{2}\). But, instead of \({5}^{2}\), it is 20 which to be turned out.

**4. At a game of billiards, A can give B 15 points in 60 and A can give C to 20 points in 60. How many points can B give C in a game of 90?**

- A. 30 points

B. 20 points

C. 10 points

D. 12 points

**Answer**: Option C

**Explanation**:

A : B = 60 : 45.

A : C = 60 : 40.

\(\frac {B}{C}\) = \(\frac {B}{A}\) x \(\frac {A}{C}\) = \(\frac {45}{60}\) x \(\frac {60}{40}\) = \(\frac {45}{40}\) = \(\frac {90}{80} = \) = 90:80

B can give C 10 points in a game of 90.

**5. How many bricks, each measuring 25 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm?**

- A. 5600

B. 6000

C. 6400

D. 7200

**Answer**: Option C

**Explanation**:

Number of bricks = \(\frac { Volume of the wall}{Volume of 1 brick}\) = \(\frac {800 × 600 × 22.5}{25 × 11.25 × 6}\) = 6400

- A. 0.172

B. 1.72

C. 17.2

D. 172

**Answer**: Option C

**Explanation**:

\(\frac { 29.94}{1.45}\) = \(\frac { 299.4}{14.5}\)

\(\frac {2994}{14.5}\) X \(\frac { 1}{10}\)

\(\frac {172}{10}\) = 17.2

**2. The expression (11.98 x 11.98 + 11.98 x x + 0.02 x 0.02) will be a perfect square for x equal to:**

- A. 0.02

B. 0.2

C. 0.04

D. 0.4

**Answer**: Option C

**Explanation**:

Given expression =\({11.98}^{2}\) + \({0.0}^{2}\) + 11.98 x x.

For the given expression to be a perfect square, we must have

11.98 x x = 2 x 11.98 x 0.02 or x = 0.04

Then, Sachin’s age = (x – 7) years.

**3. A hall is 15 m long and 12 m broad. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, the volume of the hall is:**

- A. 720

B. 900

C. 1200

D. 1800

**Answer**: Option C

**Explanation**:

2(15 + 12) x h = 2(15 x 12)

h = \(\frac {180}{27}\)m = \(\frac {20}{3}\)m

Volume = 15 x 12 x \(\frac {20}{3}\)\({m}^{3}\)

**4. A man purchased a cow for Rs. 3000 and sold it the same day for Rs. 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of:**

- A. 0%

B. 5%

C. 7.5%

D. 10%

**Answer**: Option A

**Explanation**:

C.P. = Rs. 3000.

S.P. = Rs. \(\frac {3600 × 100 }{100 + (10 × 2) }\) = Rs. 3000.

100 + (10 x 2)

Gain = 0%.

**5. In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay’s speed is:**

- A. 5 kmph

B. 6 kmph

C. 6.25 kmph

D. 7.5 kmph

**Answer**: Option A

**Explanation**:

Let Abhay’s speed be x km/hr.

Then, \(\frac {30 }{X }\) – \(\frac {30}{2X }\) = 3

6x = 30

x = 5 km/hr.