A candidate with **quantitative aptitude** knowledge will be in a better position to analyse and make sense of the given data. Quantitative Aptitude knowledge is an **important** measure for a prospective business executive’s **abilities**.

The article **TS CAB Recruitment Quantitative Aptitude Quiz 7** provides Quantitative Aptitude questions with answers useful to the candidates preparing for** Competitive exams, Entrance exams, Interviews** etc. The article **TS CAB Recruitment Quantitative Aptitude Quiz 7** will assist the students to know the expected questions from **Quantitative Aptitude**.

- A. 2 hours

B. 3 hours

C. 4 hours

D. 5 hours

**Answer**: Option C

**Explanation**:

Speed downstream = (13 + 4) km/hr = 17 km/hr.

Time taken to travel 68 km downstream = \(\frac {68}{17}\)hrs = 4 hrs

**2. A man’s speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man’s speed against the current is:**

- A. 8.5 km/hr

B. 9 km/hr

C. 10 km/hr

D. 12.5 km/hr

**Answer**: Option C

**Explanation**:

Man’s rate in still water = (15 – 2.5) km/hr = 12.5 km/hr.

Man’s rate against the current = (12.5 – 2.5) km/hr = 10 km/hr.

**3. What least number must be added to 1056, so that the sum is completely divisible by 23 ?**

- A. 2

B. 3

C. 18

D. 21

**Answer**: Option A

**Explanation**:

23) 1056 (45

92

—

136

115

—

21

—

Required number = (23 – 21)

= 2.

**4. How many of the following numbers are divisible by 132 ?
264, 396, 462, 792, 968, 2178, 5184, 6336**

- A. 4

B. 5

C. 6

D. 7

**Answer**: Option A

**Explanation**:

132 = 4 x 3 x 11

So, if the number divisible by all the three numbers 4, 3 and 11, then the number is divisible by 132 also.

264 11,3,4 (/)

396 11,3,4 (/)

462 11,3 (X)

792 11,3,4 (/)

968 11,4 (X)

2178 11,3 (X)

5184 3,4 (X)

6336 11,3,4 (/)

Therefore the following numbers are divisible by 132: 264, 396, 792 and 6336.

Required number of number = 4.

**5. 331, 482, 551, 263, 383, 362, 284**

- A. 263

B. 383

C. 331

D. 551

**Answer**: Option B

**Explanation**:

In each number except 383, the product of first and third digits is the middle one.

- A. 751

B. 853

C. 981

D. 532

**Answer**: Option A

**Explanation**:

In each number except 751, the difference of third and first digit is the middle one.

**2. A man purchased a cow for Rs. 3000 and sold it the same day for Rs. 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of:**

- A. 0%

B. 5%

C. 7.5%

D. 10%

**Answer**: Option A

**Explanation**:

C.P. = Rs. 3000.

S.P. = Rs. \({3600 Ã— 100}{100 + (10 Ã— 2}\) = Rs. 3000.

100 + (10 x 2)

Gain = 0%.

**3. If Rs. 10 be allowed as true discount on a bill of Rs. 110 due at the end of a certain time, then the discount allowed on the same sum due at the end of double the time is:**

- A. Rs. 20

B. Rs. 21.81

C. Rs. 22

D. Rs. 18.33

**Answer**: Option D

**Explanation**:

S.I. on Rs. (110 – 10) for a certain time = Rs. 10.

S.I. on Rs. 100 for double the time = Rs. 20.

T.D. on Rs. 120 = Rs. (120 – 100) = Rs. 20.

T.D. on Rs. 110 = Rs. \({20}{120}\) x 110 = Rs. 18.33

**4. Rs. 20 is the true discount on Rs. 260 due after a certain time. What will be the true discount on the same sum due after half of the former time, the rate of interest being the same?**

- A. Rs. 10

B. Rs. 10.40

C. Rs. 15.20

D. Rs. 13

**Answer**: Option B

**Explanation**:

S.I. on Rs. (260 – 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs. \(\frac {10 }{250}\) X 260 = = Rs. 10.40

Sagar’s present age = (5x + 6) = 16 years.

**5. The simple interest and the true discount on a certain sum for a given time and at a given rate are Rs. 85 and Rs. 80 respectively. The sum is:**

- A. Rs. 1800

B. Rs. 1450

C. Rs. 1360

D. Rs. 6800

**Answer**: Option C

**Explanation**:

Sum = \(\frac {S.I. Ã— T.D. }{(S.I.) – (T.D.)}\) = \(\frac {85 Ã— 80 }{(85 – 80) }\) = Rs. 1360.

- A. 276

B. 299

C. 322

D. 345

**Answer**: Option C

**Explanation**:

Clearly, the numbers are (23 x 13) and (23 x 14).

Larger number = (23 x 14) = 322.

**2. Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?**

- A. 4

B. 10

C. 15

D. 16

**Answer**: Option D

**Explanation**:

L.C.M. of 2, 4, 6, 8, 10, 12 is 120.

So, the bells will toll together after every 120 seconds(2 minutes).

In 30 minutes, they will toll together \(\frac {30}{2}\) + 1 = 16 times.

**3. Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:**

- A.4

B. 5

C. 6

D. 8

**Answer**: Option A

**Explanation**:

N = H.C.F. of (4665 – 1305), (6905 – 4665) and (6905 – 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

**4. The greatest number of four digits which is divisible by 15, 25, 40 and 75 is:**

- A. 9000

B. 9400

C. 9600

D. 9800

**Answer**: Option C

**Explanation**:

Greatest number of 4-digits is 9999.

L.C.M. of 15, 25, 40 and 75 is 600.

On dividing 9999 by 600, the remainder is 399.

Required number (9999 – 399) = 9600.

**5. In order to obtain an income of Rs. 650 from 10% stock at Rs. 96, one must make an investment of:**

- A. Rs. 3100

B. Rs. 6240

C. Rs. 6500

D. Rs. 9600

**Answer**: Option B

**Explanation**:

To obtain Rs. 10, investment = Rs. 96.

To obtain Rs. 650, investment = Rs \(\frac {96}{10}\) x 650 = Rs. 6240.