Number Series is the arrangement of numbers in a certain order where some numbers are wrongly keptÂ or some numbers are missing from that series. So accurate series are to be found. Number Series in competitive exams are divided into two. One is **missing series** and the other is **wrong series**. A number series is given in which a number is wrongly placed is the **wrong series**. Candidates are asked to identify that particular wrong number. A number series in which a specific number is missing is the **missing series**. Candidates have to identify the missing number.

1. **Easy**–Â Under easyÂ type, there are two scenarios.

__Scenario 1__: One is based on addition/subtraction by common difference

__Scenario 2__: Other is based on multiplication/division-Here a certain no. is multiplied or divided to the previous number to get the next number.

2. **ModerateÂ **– a) we need to find out common difference and b)pattern of common difference (addition, subtraction, multiplication, division).

3. **DifficultÂ **– Here common difference does not follow the pattern.

**Wrong number series **– In this series all the numbers will be followed by one rule except the one which is wrong.

This Types of Series are based on square of a number which is in same order and one square number is missing in that given series.

**Example 1**:

841, ?, 2401, 3481, 4761

**Solution**:

- \(29^{2}\), \(39^{2}\), \(49^{2}\), \(59^{2}\), \(69^{2}\)

**Example 2**:

1, 9, 25, ?, 81, 121

**Solution**:

- \(1^{2}\), \(3^{2}\), \(5^{2}\), \(7^{2}\), \(9^{2}\), \(11^{2}\)

**Example 3**:

289, 225, 169, ?, 81

**Solution**:

- \(17^{2}\), \(15^{2}\), \(13^{2}\), \(11^{2}\), \(9^{2}\)

**Perfect Cube Series**:

This Types of Series are based on cube of a number which is in same order and one cube number is missing in that given series.

**Example 1**:

3375, ?, 24389, 46656, 79507

**Solution**:

- \(15^{3}\), \(22^{3}\), \(29^{3}\), \(36^{3}\), \(43^{3}\)

(Each cube digit added with seven to become next cube number)

**Example 2**:

729, 6859, 24389, ?, 117649, 205379

**Solution**:

- \(9^{3}\), \(19^{3}\), \(29^{3}\), \(39^{3}\), \(49^{3}\), \(59^{3}\)

**Example 3**:

1000, 8000, 27000, 64000, ?

**Solution**:

- \(10^{3}\), \(20^{3}\), \(30^{3}\), \(40^{3}\), \(50^{3}\)

**Ration Series**:

This type of series are based on ration series, where sequence are in form of ratio in difference between the numbers. All numbers are arranged in ratio sequence order.

**Example 1**:

11, 22, 44, 88, ?

**Solution**:

- Separate each number and

= 11 x 2 = 22,

= 22 x 2 = 44,

= 44 x 2 = 88,

= 88 x 2 = 176.

**Example 2**:

13, 26, 412, ?, 1648

**Solution**:

- Separate each number and

= (1+1 = 2, 3+3 = 6) = 26,

= (2+2=4, 6+6 = 12) = 412,

= (41+41=82, 2+2=4 = 824,

= (82+82=164,4+4= 8)=1648.

So, the missing term is 824.

**Geometric Series**:

This type of series are based on ascending or descending sequence of numbers and each continuous number is obtain by multiplying or dividing the preceding number with static number.

**Example 1**:

3, ?, 45, 144, 585

**Solution**:

- 3 x 0 +9 = 9, 9 x 1 + 9 = 18, 18 x 2 + 9 = 45, 45 x 3 + 9 = 144, 144 x 4 + 9 = 585.

**Example 2**:

5, 45, 405, 3645, ?

**Solution**:

- 5 x 9 = 45, 45 x 9 = 405, 405 x 9 = 3645, 3645 x 9 = 32805.

**Example 3**:

73205, 6655, 605, 55, ?

**Solution**:

- 5 x 11 = 55, 55 x 11 = 605, 605 x 11 = 6655, 6655 x 11 = 73205.

**Two stage Type Series**:

A two stage Arithmetic series is one in which the formation of arithmetic series are obtain from differences of continuous numbers themselves.

**Example**:

1, 3, 6, 10, 15…..

**Solution**:

- 3 – 1 = 2, 6 – 3 = 3, 10 – 6 = 4, 15 – 10 = 5….

Now, we get an arithmetic sequence 2, 3, 4, 5

**Mixed Series**:

This type of series are more than one different order are given in a series which arranged in alternatively in a single series or created according to any non-conventional rule. This mixed series Examples are describes in separately.

**Example**:

11, 24, 50, 102, 206, ?

**Solution**:

- 11 x 2 = 22 +2 = 24,

24 x 2 = 48 + 2 = 50,

50 x 2 = 100 + 2 = 102,

102 x 2 = 204 + 2 = 206,

206 x 2 = 412 + 2 = 414.

So the missing number is 414.

- GivenÂ series 291, 304, 317, ?, 343

First, find the common difference between the numbers

i.e. 304 – 291 = 13

317 – 304 = 13

Now, just add 13 to 317

â‡’ 317 + 13 = 330

Therefore series is 291, 304, 317,

**2. Find out the series 9, 18, 36, 72, ?**

**Solution**:

- Given series is 9, 18, 36, 72, ?

Notice that every number is a multiple of 2 i.e.

9 Ã— 2 = 18

18 Ã— 2 = 36

36 Ã— 2 = 72

72 Ã— 2 = 144

Therefore, the series is 9, 18, 36, 72,

**3. Find out the series 30, 45, 75, 120, 180, 255, ?**

**Solution**:

- Given series 30, 45, 75, 120, 180, 255, ?

First, find out the common difference between the numbers i.e.

45 – 30 = 15

75 – 45 = 30

120 – 75 = 45

180 – 120 = 60

Now see the pattern of common difference i.e.

15 Ã— 1 = 15

15 Ã— 2 = 30

15 Ã— 3 = 45

15 Ã— 4 = 60

15 Ã— 5 = 75

15 Ã— 6 +

Therefore, the series is 30, 45, 75, 120, 180, 255,

**4. Find out the series 9, 90, 154, 203, 239, 264, ?**

**Solution**:

- Given series 9, 90, 154, 203,

Multiply second last number by 2 i.e. 2 Ã— 239=478 > 264

So, take common difference between them

90 – 9 = 81

154 – 90 = 64

203 – 154 = 49

239 – 203 = 36

264 – 239 = 25

By observing theÂ above pattern, they are square numbers i.e \(9^2, 8^2, 7^2, 6^2, 5^2, 4^2\) respectively

So, \(4^2\) + 264 = 280

Therefore, series is 9, 90, 154, 203, 239, 264,

**5. Find out the series 7, 13, 25, 49, 97, 194, 385?**

**Solution**:

- Given series 7, 13, 25, 49, 97, 194, 385?

7 Ã— 2 – 1 = 13

So, 13 Ã— 2 – 1 = 25

25 Ã— 2 – 1 = 49

49 Ã— 2 – 1 = 97

97 Ã— 2 – 1 = 193

193 Ã— 2 – 1 = 385

Therefore, the wrong number is 194