# Percentages Practice Set 9

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# Percentages Practice Set 9

### Introduction

Percentages: A Percentage is a dimensionless ratio or number expressed as a fraction of 100. It is often denoted by the character (%).

Example: 10% = $$\frac{10}{100}$$ = $$\frac{1}{10}$$

Percentages is one of the important topic in the Quantitative Aptitude section. The article Percentages Practice Set 9 consists of different models of questions with answers useful for candidates preparing for different competitive examinations like RRB ALP/Technical Exams/Junior Engineer Recruitment Exams, SSC, IBPS PO Exams and other examinations across the globe that include Quantitative Aptitude section. Prepare better for all exams with this Percentages Practice Set 9 for SSC CGL & Railways. This Percentages Practice Set 9 for SSC, Railways Exams will help you learn concepts of mensuration.

### Quiz

1. What percent of a day in 6 hours?

A. 25%
B. 52%
C. 50%
D. 5%

Answer: Option A

Explanation:
($$\frac{6}{24}$$ × 100 = 25%

2. Two-fifth of one-third of three seventh of a number is 15.What is 40% of that number?

A. 501
B. 105
C. 525
D. 150

Answer: Option C

Explanation:
X * $$\frac{2}{5}$$ x $$\frac{1}{3}$$ x $$\frac{3}{7}$$ × x = 15
X = 15 x ($$\frac{7}{3}$$) x ($$\frac{5}{2}$$) x 3 = $$\frac{525}{2}$$
40% of x = $$\frac{40}{100}$$ $$\frac{525}{2}$$=>105

3. The population of of a town is 176000.If it increase at the rate of 5% per annum,what will be it’s population 2 years hence?

A. 194000
B. 194040
C. 190440
D. 194104

Answer: Option B

Explanation:

176000 x $$\frac{105}{100}$$ = 88 × 105 × 21 = 194040

4. The length and breath of a rectangle are increased by 20% and 30%.The area of the resulting rectangle exceeds the area of the original rectangle?

A. 50%
B. 65%
C. 56%
D. 156%

Answer: Option C

Explanation:
$$\frac{120}{100}$$ x $$\frac{130}{100}$$ x 150 = 156.
156 – 100 = 56.

5. Water tax is is increased by 20% but its consumption is decreased by 20%.Then increase or decrease in the expenditure of the money is

A. 40%
B. 4%
C. 96%
D. None of the above

Answer: Option B

Explanation:
X – $$\frac{20 × 20 }{100}$$ = 4

1. Sugar contain 5% water .What quantity of pure Sugar should be added to 10 liters of water to reduce this to 2%.

A. 5 lit
B. 6 lit
C. 10 lit
D. 15 lit

Answer: Option D

Explanation:
$$\frac{ 0.5 }{x + 10}$$ = $$\frac{ 2 }{100}$$
2x = 30
X = 15

2. In an election between 2 candidates,Candidate who gets 40% of the total vote defeated by 15000.The no of votes polled by winner

A. 10000
B. 45000
C. 30000
D. 6000

Answer: Option B

Explanation:
40% – looser, 60% – winner, defeated 15000 = 20%
Winner = 60% = 15000 × 3 = 45000.

3. The price of a fan is decreased by 20%.as a result of wh ich the sale increased by 40%.What will be the effect on the total revenue of the shop?

A. 12%
B. 10%
C. 20%
D. 30%

Answer: Option A

Explanation:

Original revenue = 100 × 100 = 10000.
After 20% decrease = 80 × 140 = 11200.

X * $$\frac{(11200-10000)}{10000}$$) ×100 = $$\frac{1200}{10000}$$) × 100
= 12%.

4. Raj save 10%,after 2 years when his income is increased by 10%,he could save the same money then how much his expenditure increased?

A. 10%
B. 20%
C. 50%
D. 15%

Answer: Option A

Explanation:
Let income = 100, saving = 10 and expenditure =90.
New income = 110, saving = 11 and e = 99.

alcohol = $$\frac{99-90}{90}$$ × 100 = $$\frac{9}{90}$$ × 100 = 10%

5. 45% of ? = 25% of 355

A. 195
B. 176
C. 127
D. 197.22

Answer: Option D

Explanation:
$$\frac{45}{100}$$ x X = $$\frac{25}{100}$$ × 355

$$\frac{100}{45}$$ x $$\frac{25}{100}$$ = 197.22

1. Out of 500 students of a school 35% students plays football, 25% plays cricket and 20% neither play football nor cricket.How many students play football and cricket ?

A. 200
B. 100
C. 50
D. 94

Answer: Option A

Explanation:

Football = n(A) = ($$\frac{35}{100}$$) × 500 = 175
Cricket = n(B) = ($$\frac{25}{100}$$) × 500 = 125
neither play football nor cricket = ( $$\frac{20}{100}$$) × 500 = 100
both football and cricket = n(A U B) = 175 + 125 -100 = 200

2. The price of sugar is reduced by 3%.How many kg of sugar can now be bought for the money which was sufficient to buy 50kg of rice earlier ?

A. 50 kg
B. 55 kg
C. 51.5 kg
D. 56 kg

Answer: Option C

Explanation:
Let one kg of sugar earlier = Rs. 100
50 kg of sugar earlier = Rs. 5000
Now 1 kg of sugar = Rs.97
Quantity to buy now = $$\frac{5000}{97}$$ = 51.5 kg

3. Fresh fruits contains 70% of water and dry fruits contain 20% of water.How much dry fruit can be obtained from 100 kg of fresh fruits ?

A. 35
B. 37
C. 37.5
D. 40

Answer: Option C

Explanation:

Quantity of pulb in 100 kg of fresh fruit = (100 – 70) × 100 = 30 kg
Quantity of dry fruit be x kg
(100 – 20 ) % of x = 30
($$\frac{80}{100}$$) x = 30
X = $$\frac{(30 × 100)}{80}$$ = 37.5

4. In an examination , full mark is 500, A gets 25% more than B, B gets 40% more than C and C gets 60% more than D.If A got 320, what percentage of full marks did D got (approx)?

A. 21
B. 22
C. 23
D. 24

Answer: Option C

Explanation:
A = $$\frac{125}{100}$$ of B => B = $$\frac{4}{5}$$ A
B = $$\frac{140}{100}$$ of C => C = $$\frac{5}{7}$$ B
C = $$\frac{160}{100}$$ 0f D => D = $$\frac{5}{8}$$ C
B = ($$\frac{4}{5}$$ ) × 320 = 256
C = ($$\frac{5}{7}$$ ) × 256 = 183
D = ($$\frac{5}{8}$$ ) × 183 = 114
D percentage = ($$\frac{114}{500}$$ ) × 100 = 23%

5. The population of a city is increased 5% ,7% and 11% in the last three years, What will be the present population if the population of a town is 2,40,000 three years ago ?

A. 2,99,600
B. 2,99,500
C. 2,99,400
D. 2,99,300

Answer: Option D

Explanation:
2,40,000 × ($$\frac{105}{100}$$) × ($$\frac{107}{100}$$) × ($$\frac{111}{100}$$) = 2,99,300