**Example**: 10% = \(\frac{10}{100}\) = \(\frac{1}{10}\)

**Percentages** is one of the important topic in the **Quantitative Aptitude** section. The article Percentages Practice Set 2 consists of different models of questions with answers useful for candidates preparing for different competitive examinations like **RRB ALP/Technical Exams/Junior Engineer Recruitment Exams, SSC, IBPS PO** Exams and other examinations across the globe that include **Quantitative Aptitude section**

**Answer**: Option C

**Explanation**:

I |
II |
III |

120 | 125 | 100 |

125 ———- 120

100 ———– ? => 96%

**2. A sells his goods 50% cheaper than B but 50% dearer than C. The cheapest is?**

**Answer**: Option C

**Explanation**:

Let, B = 100

A = 50

C Ã— (\(\frac{150}{100}\)) = 50

3C = 100

C = 33.3 then ‘C’ Cheapest

**3. The salary of a typist was at first raised by 10% and then the same was reduced by 5%. If he presently draws Rs.1045.What was his original salary?**

**Answer**: Option C

**Explanation**:

x Ã— (\(\frac{110}{100}\)) Ã— (\(\frac{95}{100}\)) = 1045

x Ã—(\(\frac{11}{10}\)) Ã— (\(\frac{1}{100}\)) = 11

x = 1000

**4. The tax on a commodity is diminished by 20% and its consumption increased by 15%. The effect on revenue is?**

**Answer**: Option B

**Explanation**:

100 Ã— 100 = 10000

80 Ã— 115 = 9200

———–

10000 ———- 800

100 ———– ? => 8% decrease

**5. A candidate got 35% of the votes polled and he lost to his rival by 2250 votes. How many votes were cast?**

**Answer**: Option A

**Explanation**:

35% ———– L

65% ———– W

——————

30% ———- 2250

100% ——— ? => 7500

**Answer**: Option B

**Explanation**:

100

150

——

150 ——- 50

100 ——- ? => 33\(\frac{1}{3}\)%

**2. Subtracting 10% from X is the same as multiplying X by what number?**

**Answer**: Option B

**Explanation**:

x – (\(\frac{10}{100}\)) x = x Ã— ?

? = 90%

**3. If the numerator of a fraction is increased by 20% and its denominator is diminished by 25% value of the fraction is 2/15. Find the original fraction.**

**Answer**: Option A

**Explanation**:

x Ã— \(\frac{120}{100}\)

——— =\(\frac{2}{15}\)

y Ã— \(\frac{75}{100}\)

\(\frac{x}{y}\) = \(\frac{1}{12}\)

**4. An engineering student has to secure 36% marks to pass. He gets 130 marks and fails by 14 marks. The maximum No. of marks obtained by him is?**

**Answer**: Option B

**Explanation**:

130

14

——-

36% —— 144

100% —— ? => 400

**5. A and Bâ€™s salaries together amount to Rs. 2,000. A spends 95% of his salary and B spends 85% of his. If now their savings are the same, what is Aâ€™s salary?**

**Answer**: Option D

**Explanation**:

(\(\frac{5}{100}\)) A = (\(\frac{15}{100}\)) B

A = 3B

A + B = 2000

4B = 2000 => B = 500

A = 1500

**Answer**: Option B

**Explanation**:

[1000 + (x – 4000) Ã— (\(\frac{2.5}{100}\))] – x Ã— (\(\frac{5}{100}\)) = 600

x = 12000

**2. 5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3553, how much was it in the beginning?**

**Answer**: Option C

**Explanation**:

x Ã— (\(\frac{95}{100}\))Ã— (\(\frac{85}{100}\)) = 3553

x = 4400

**3. In a factory, there are 40% technicians and 60% non-technicians. If the 60% of the technicians and 40% of non-technicians are permanent employees, then the percentage of workers who are temporary is?**

**Answer**: Option C

**Explanation**:

Total = 100 | |

T= 40 | NT= 60 |

40 Ã— (\(\frac{60}{100}\)) = 24 | 60 Ã— (\(\frac{40}{100}\)) = 24 |

24 + 24 = 48 => 100 – 48 = 52%

**4. A mixture of 70 liters of wine and water contains 10% water. How much water must be added to make water 12Â½% of the total mixture?**

**Answer**: Option D

**Explanation**:

70 Ã— (\(\frac{10}{100}\)) = 7

Wine | Water | |

87\(\frac{1}{2}\)% | 12\(\frac{1}{2}\)% |

87\(\frac{1}{2}\)% ——- 63

12\(\frac{1}{2}\)% ——- ? => 9-7 = 2

**5. The amount of water (in ml) that should be added to reduce 9 ml. Lotion, containing 50% alcohol, to a lotion containing 30% alcohol, is?**

**Answer**: Option D

**Explanation**:

4.5 | 4.5 |

30% | 70% |

30% —– 4.5

70% ——? => 10.5 – 4.5 = 6 ml

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