# SSC CPO Percentages Quiz 4

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# SSC CPO Percentages Quiz 4

### Introduction

Percentages: A Percentage is a dimensionless ratio or number expressed as a fraction of 100. It is often denoted by the character (%).

Example: 10% = $$\frac{10}{100}$$ = $$\frac{1}{10}$$

Percentages is one of the important topic in the Quantitative Aptitude section. The article SSC CPO Percentages Quiz 4 consists of different models of questions with answers useful for candidates preparing for different competitive examinations like RRB ALP/Technical Exams/Junior Engineer Recruitment Exams, SSC, IBPS PO Exams and other examinations across the globe that include Quantitative Aptitude section. Prepare better for all exams with this SSC CPO Percentages Quiz 4 for SSC CGL & Railways. This SSC CPO Percentages Quiz 4 for SSC, Railways Exams will help you learn concepts of mensuration. Candidates can check the daily updates on SSC Official Website.

### Samples

1. Two numbers are less than third number by 30% and 37% respectively. How much percent is the second number less than by the first

A. 8%
B. 9%
C. 10%
D. 11%

Explanation:
Let the third number is x.
then first number = (100-30)% of x
= 70% of x = $$\frac{7x}{10}$$

The second number is ($$\frac{63x}{100}$$)

Difference = $$\frac{7x}{10}$$ – $$\frac{63x}{100}$$ = $$\frac{7x}{10}$$

So the required percentage is, the difference is what percent of the first number

=> ($$\frac{7x}{100}$$ * $$\frac{10}{7x}$$)% = 10%

2. In an examination, 34% of the students failed in mathematics and 42% failed in English. If 20% of the students failed in both the subjects, then find the percentage of students who passed in both the subjects.

A. 40%
B. 42%
C. 44%
D. 46%

Failed in mathematics, n(A) = 34
Failed in English, n(B) = 42
n(A∪B) = n(A) + n(B) − n(A∩B) = 34 + 42 − 20 = 56 Failed in either or both subjects are 56Percentage passed = (100 − 56)% = 44%

3. Out of 450 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricket ?

A. 75
B. 100
C. 125

D. 150

Explanation:
Students who play cricket, n(A) = 325
Students who play football, n(B) = 175
Total students who play either or both games,
= n(A∪B) = 450 − 50 = 400Required Number, n(A∩B) = n(A) + n(B) − n(A∪B) = 325 + 175 − 400 = 100

4. The teacher took the exam for English, the average for the entire class was 80 marks. If we say that 10% of the students scored 95 marks and 20% scored 90 marks then calculate average marks of the remaining students of the class.

A. 60

B. 70
C. 75

D. 80

Explanation:

Lets assume that total number of students in class is 100 and required average be x.
Then from the given statement we can calculate :
(10 * 95) + (20 * 90) + (70 * x) = (100 * 80)

=> 70x = 8000 – (950 + 1800) = 5250

=> x = 75.

5. How many liters of pure acid are there in 8 liters of a 20% solution

A. 1.5

B. 1.6

C. 1.7

D. 1.8

Explanation:
Question of this type looks a bit typical, but it is too simple, as below…

It will be 8 * $$\frac{20}{100}$$ = 1.6

6. Raman’s salary was decreased by 50% and subsequently increased by 50%. How much percent does he loss.

A. 75

B. 65
C. 45

D. 25

Explanation:
Let the origianl salary = Rs. 100

It will be 150% of (50% of 100)
= (150/100) * (50/100) * 100 = 75

So New salary is 75, It means his loss is 25%

7. If x% of y is 100 and y% of z is 200, then find the relation between x and z.

A. z = x

B. 2z = x

C. z = 2x

D. None of above

Explanation:
It is , y% of z = 2(x% of y)
=> $$\frac{YZ}{100}$$ = $$\frac{2XY}{100}$$
=> z = 2x

8. If 15% of 40 is greater than 25% of a number by 2, the number is

A. 14

B. 16

C. 18

D. 20

Explanation:
$$\frac{15}{100}$$ * 40 – $$\frac{25}{100}$$ * x = 2 or $$\frac{X}{4}$$ = 4 so x = 16

9. A batsman scored 120 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets.

A. 40%

B. 50%

C. 60%

D. 70%

Explanation:
Number of runs made by running = 110 – (3 x 4 + 8 x 6)
= 120 – (60)
= 60

Now, we need to calculate 60 is what percent of 120.

=> $$\frac{60}{120}$$* 100 = 50 %

10. Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get

A. 55%

B. 56%
C. 57%

D. 58%

Explanation:
Total number of votes polled = (1136 + 7636 + 11628) = 20400

So, Required percentage = $$\frac{11628}{20400}$$* 100 = 57%

11. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are

A. 42,30
B. 42,31
C. 42,32

D. 42,33

Explanation:
Let their marks be (x+9) and x.
Then, x+9 = $$\frac{56}{100}$$(x + 9 +x)
=> 25(x + 9)
=> 14 (2x + 9)
=> 3x = 99
=> x = 33.
So, their marks are 42 and 33

12. One-fourth of one-third of two-fifth of a number is 15. What will be40% of that number

A. 140

B. 150
C. 180
D. 200

Explanation:

($$\frac{1}{4}$$) * ($$\frac{1}{3}$$) * ($$\frac{2}{5}$$) * x = 15 then x = 15 * 30 = 450
40% of 450 = 180

13. Rahul’s Mathematics test had 75 problems, 10 arithmetic, 30 algebra, 35 geometry problems. Although he answered 70% of arithmetic, 40% of arithmetic and 60% of geometry problems correctly, still he got less than 60% problems right. How many more questions he would have to answer more to get passed

A. 5

B. 6

C. 7
D. 8

Explanation:
Number of questions attempted correctly = (70% of 10 + 40% of 30 + 60% of 35)
= 7 + 12 + 21 = 40.

Questions to be answered correctly for 60% = 60% of total quations
= 60 % of 75 = 45.

He would have to answer 45 – 40 = 5

14. 10% of inhabitants of a village having died of cholera, a panic set in, during which 25% of the remaining inhabitants left the village. The population is then reduced to 4050. Find the original inhabitants

A. 5500
B. 6000

C. 6500

D. 7000

Explanation:

Let the total number is x,
then,

(100-25)% of (100 – 10)% x = 4050
=> 75% of 90% of x = 4050
=> $$\frac{75}{100}$$ * $$\frac{90}{100}$$ * x = 4050
=> x = $$\frac{(4050*50)}{27}$$ = 6000

15. If a sales tax is reduced from 5% to 4%, then what difference it will make if you purchase an item of Rs. 1000

A. 10

B. 20
C. 30

D. 40