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Simple Interest Quiz 4

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Simple Interest Quiz 4

shape Introduction

What is simple interest? Simple interest is a quick and easy method of calculating the interest charge on a loan. Simple interest is determined by multiplying the daily interest rate by the principal by the number of days that elapse between payments.
Important Formulae :
1. Simple interest(S.I) = [latex]\frac{principal(P) \times rate(R) \times time(T)}{100}[/latex]
2. Principal(P) = [latex]\frac{100 \times Simple interest}{Rate \times time}[/latex]
3. Rate = [latex]\frac{100 \times Simple interest}{principal \times time}[/latex]
4. Time = [latex]\frac{100 \times Simple interest}{principal \times rate}[/latex]
5. Amount = Principal+ simple interest (or) Amount = P(1 + [latex]\frac{R \times T}{100} [/latex])
Simple Interest is one of important topic in Quantitative Aptitude Section. In Simple Interest Quiz 4 article candidates can find questions with answer. By solving this questions candidates can improve and maintain, speed, and accuracy in the exams. Simple Interest Quiz 4 questions are very useful for different exams such as IBPS PO, Clerk, SSC CGL, SBI PO, NIACL Assistant, NICL AO, IBPS SO, RRB, Railways, Civil Services etc.

shape Q1

Suresh lends 40% of his money at 15% p.a, 50% of the rest at 10% per annum and the rest at 18% p.a. rate of interest. What would be the annual rate of interest, if the interest is calculated on the whole sum?
    A. 18.5% B. 14.4% C. 16.5% D. 19.5%


x – [latex](\frac {40}{100}) × x = \frac {60x}{100}[/latex]
[latex]\frac {40}{100} at 15% p.a = \frac {40}{100} × \frac {15}{100} = \frac {60x}{1000}[/latex]
[latex]\frac {50}{100} × \frac {40x}{100} × \frac {30x}{100} at 10% p.a = \frac {30x}{100} × \frac {10}{100} = \frac {30x}{1000}[/latex]
Balance amount = [latex] \frac {40x}{100} - \frac {30x}{100} = \frac {30x}{100}[/latex]at 18% p.a = [latex] \frac {18}{100} × \frac {30x}{100} = \frac {54x}{1000}[/latex]
R = [latex] [\frac {\frac {144x}{1000}}{x}] × 100 = 14.4 [/latex]%

shape Q2

Ajay borrows Rs 1000 at the rate of 12% per annum S.I. and Babu borrows Rs 1050 at the rate of 10% per annum simple interest. In how many years will their amounts of debts be equal?
    A. [latex]\frac {18}{5}[/latex] B. [latex]\frac {10}{3}[/latex] C. [latex]\frac {22}{3}[/latex] D. [latex]\frac {10}{5}[/latex]


Let Time = x years Then,
[latex][1000 + \frac {(1000 × 12 × x)}{100}] = [1050 + \frac {(1050 × 10 × x)}{100}] \Rightarrow 1000 + 120x = 1050 + 105x[/latex]
[latex]\Rightarrow 15x = 50 \Rightarrow x = \frac {10}{3}[/latex] years

shape Q3

A sum of Rs. 8800 is to be divided among three brothers A, D and R in such a way that S.I. on each part at 5% p.a. after 1, 2 and 3 year respectively remains equal. The share of A is more than that of R by?
    A. Rs. 3200 B. Rs. 2500 C. Rs. 3000 D. Rs. 2700


[latex]x × 5 × \frac {1}{100} = y × 5 × \frac {2}{100} = z × 5 × \frac {3}{100}[/latex]
x:y:z = 6:3:2
The share of A is more than that of R by = [latex]\frac {4}{11}[/latex] × 8800 = 3200

shape Q4

Mayank invested a certain sum of money in a S.I. bond, that value grew to Rs. 300 at the end of 3 year and to Rs. 400 at the end of another 5 year. Then what was the rate of interest in which he invested his sum?
    A. 12% B. 12.5% C. 6.67% D. 8.33%


[latex]\frac {P × R × 3}{100}[/latex] + P = 300 –(i)
[latex]\frac {P × R × 8}{100}[/latex] + P = 400 –(ii)
From (i) and (ii)
[latex]\frac {P × R × 5}{100}[/latex] = 100
P × R = 2000 —(iii)
Sub (iii) in (i)
[latex]\frac {6000}{100}[/latex] + P = 300
P = 240
240 × R = 2000 [latex]\Rightarrow[/latex] R = 8.33%

shape Q5

A borrows Rs.7000 at S.I. from a lender. At the end of 3 years, A again borrows Rs.3000 and settled that amount after paying Rs.4615 as interest after 8 years from the time A made the first borrowing. What is the rate of interest?
    A. 5.5% B. 9.5% C. 7.5% D. 6.5%


SI for Rs.7000 for 8 years = [latex] \frac {(7000 × r × 8)}{100}[/latex]
Again borrowed = 3000
SI = [latex]\frac{(3000 × r × 5)}{100}[/latex]
Total interest= [latex][\frac{(7000 × r × 8)}{100}] + [\frac {(3000 × r × 5)}{100}] = 4615[/latex]
560r + 150r = 4615
710r = 4615
r = 6.5%

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