  # Simplification Practice Set 1 5 Steps - 3 Clicks

# Simplification Practice Set 1

### Introduction

Simplification Practice Set 1 is useful for the aspirants of several bank exams and competitive exams. The Simplification Practice Set 1 contains important questions from Simplification which match the pattern of Banking exams. Simplification Quiz Questions will consume more time. BODMAS technique is very useful to score maximum marks in Simplification concept related questions.

### Quiz

1. $$\frac{4}{9}$$× 1701 + $$\frac{2}{11}$$× 1386

A. 180
B. 1080
C. 1008
D. 1800

Answer: Option C

Explanation: $$\frac{4}{9}$$× 1701 + $$\frac{2}{11}$$× 1386 = ?
? = (4 × 189) + (2 × 126)
? = 756 + 252 = 1008.
Hence, option C is correct.

2. 9 $$\frac{3}{7}$$ + 6 $$\frac{4}{7}$$ – ? = 14 $$\frac{4}{7}$$× 1701

A. $$\frac{3}{7}$$
B. $$\frac{4}{7}$$
C. 2 $$\frac{4}{7}$$
D. 1$$\frac{3}{7}$$

Answer: Option D

Explanation: ? = 9 $$\frac{3}{7}$$ + 6 $$\frac{4}{7}$$ – ? = 14 $$\frac{4}{7}$$× 1701
⇒ ? = 9 + $$\frac{3}{7}$$ + 6 + $$\frac{4}{7}$$ – 14 – $$\frac{4}{7}$$
On solving the whole number part separately, we get

⇒ ? = 1 + $$\frac{3}{7}$$ + $$\frac{4}{7}$$ – $$\frac{4}{7}$$
⇒ ? = 1 + $$\frac{3}{7}$$ = 1$$\frac{3}{7}$$

3. $$\frac{4}{5}$$ x ? x $$\frac{3}{7}$$ = $$\frac{16}{105}$$

A. $$\frac{8}{9}$$
B. $$\frac{5}{7}$$
C. 2 $$\frac{4}{9}$$
D. 1$$\frac{3}{7}$$

Answer: Option C

Explanation: Let’s the number (?) be x, then

From the given equation,
$$\frac{4}{5}$$ x X x $$\frac{3}{7}$$ = $$\frac{16}{105}$$
$$\frac{12x }{35}$$ = $$\frac{16}{105}$$ ⇒ x = $$\frac{16 × 35}{105 × 12}$$
⇒ x = $$\frac{4}{9}$$

4. $${5}^{2}$$ + $${13}^{2}$$ – $${11}^{2}$$ = $${?}^{3}$$ – 52

A. 6
B. 3
C. 4
D. 5

Answer: Option D

Explanation: From the given equation

⇒ 25 + 169 – 121 = $${?}^{3}$$ – 52

⇒ 25 + 48 + 52 = $${?}^{3}$$

⇒$${?}^{3}$$ = 125

⇒ $${?}^{3}$$ = $${5}^{3}$$ ⇒ ? = 5.

5. 98643 – 21748 = 51212 + ?

A. 24383
B. 24713
C. 25683
D. 25973

Answer: Option C

Explanation: Given eqn,

98643 – 21748 = 51212 + ?

⇒ ? = 98643 – 21748 – 51212

⇒ ? = 25683

1. (764 × ?) ÷ 250 = 382

A. 115
B. 145
C. 135
D. 125

Answer: Option D

Explanation: $$\frac{760 ×}{250}$$ = 382
? = $$\frac{382 × 250}{764}$$ = 125

2. $$\frac{1}{4}$$ × (4856 × 0.5) × 12 = ?

A. 7284
B. 7462
C. 7262
D. 7414

Answer: Option A

3. 853 + ? ÷ 17 = 1000

A. 2516
B. 2482
C. 2499
D. 16147

Answer: Option C

Explanation:
853 + $$\frac{7}{?}$$ = 1000
$$\frac{7}{?}$$ = = 1000 – 853 = 147
? = 17 × 147 = 2499

4. 6156 ÷ √? × 53 = 4028

A. 6889
B. 6241
C. 5929
D. 6561

Answer: Option D

Explanation:
853 + $$\frac{6153 × 53}{√?}$$ = 4028
⇒ {√?} = 80.96 ≈ 81
⇒ ? = 6561

5. 9643 – 7750 + ? = 4990

A. 3079
B. 3097
C. 3090
D. 4010

Answer: Option B

Explanation:
853 + $$\frac{6153 × 53}{√?}$$ = ? = 4990 – 9643 + 7750 = 3097

Hence, option B is correct.

1. (608.40 × ?) ÷ 225 + 37 = 375

A. 115
B. 135
C. 130
D. 125

Answer: Option D

Explanation: $$\frac{6040 × ?}{225}$$+ 37 = 375
⇒ 608.40 × ? = (375 – 37) × 225 = 76050 ⇒ ? = 125

2. 12.25 × 7.2 + 84.33 = ?

A. 182.51
B. 177.44
C. 174.33
D. 172.53

Answer: Option D

Explanation: 12.25 × 7.2 + 84.33 = 88.2 + 84.33 = 172.53

3. √? + 416 = (60% of 920) – 110

A. 576
B. 676
C. 784
D. 1024

Answer: Option B

Explanation: √? + 416 = (60% of 920) – 110
⇒ √? = (50% of 920 + 10% of 920) – 110 – 416
⇒ √? = (460 + 92) –526
⇒ √? = 552 – 526 = 26

⇒ ? = $${26}^{2}$$ = 676

4. (14896 ÷ 19) ÷ 16 = ?

A. 49
B. 54
C. 58
D. 62

Answer: Option A

Explanation: (14896 ÷ 19) ÷ 16 = ?
⇒ ? = $$\frac{14896}{19}$$÷ 16

$$\frac{784}{16}$$ = 49

5. 12% of 555 + 15% of 666 = ?

A. 166.5
B. 167.5
C. 168.5
D. 169.5

Answer: Option A

Explanation: ? = 12% of 555 + 15% of 666

= (10 + 2)% of 555 + (10 + 5)% of 666

= 10% of 555 + 2% of 555 + 10% of 666 + 5% of 666

= 55.5 + 11.1 + 66.6 + 33.3 = 166.5

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