Calendar deals with odd days, leap year, ordinary year, counting of odd days, and day of the week related to odd days. To find the day of the week on a given date concept of odd days is used. Clocks and Calendars Practice Set 1 Presents most important questions related to Clocks and Calendars.
Answer: D
Elplanation:
On straight line means 180 degree angle
180= \(\frac {11}{{2}{m}} – 30 h\)
180= \(\frac {11}{{2}{m}} – 30 \times 3\)
180= \(\frac {11}{{2}{m}} – 90\)
(180 + 90) 2 = 11 m
m = \(\frac {540}{11} = 49 \frac {1}{4}\)
Q2. At what time, between 3 oâ€™clock and 4 oâ€™clock, both the hour hand and minute hand coincide each other?
Answer: B
Explanation:
Coincide means 00 angle.
0 = \(\frac {11}{2} m – 30 \times 3\)
11 m = \( \times 2\) = 180
m = 90 \( \times 2\) = 180
\( \frac {180}{11} = 16 \times \frac {4}{11}\)
So, Time = 3 : 16 \(\frac {4}{11}\)
Q3. How many years have 29 days in February from 2001 to 2100.
Answer: D
Elplanation:
100th year is not a leap year. So 24 Februaryâ€™s has 29 days
Q4. 2012 January 1st is Sunday, then which day is the Indian Independence day of the same year.
Answer: B
Elplanation:
30 + 29 + 31 + 30 + 31 + 30 + 31 + 15 = 227/7 = reminder = 3
So Independence day is Wednesday
Q5. Which year has the same calendar as 1700 ?
Answer: B
Elplanation:
Year:  1700  1701  1702  1703  1704  1705 
Odd Days:  1  1  1  1  2  1 
Answer: A
Elplanation:
Reference day : May 25th Monday
Days from May 25th to July 13 = 6 + 30 + 13 = 49
No of Odd Days : \( \frac {49}{7}\) = 0
Q2. March 1st is Wednesday. Which month of the same year starts with the same day?
Answer: B
Elplanation:
Month:  Mar  April  May  June  July  Aug  Sep.  Oct. 
Odd Days:  3  2  3  2  3  3  2  3 
Total 21 odd days. \( \frac {21}{7}\) = 0. So November has start with the same day.
Q3. How many times does the 29th days of the month occur in 400 consecutive years
Answer: C
Elplanation:
In 400 consecutive years there are 97 leap years. Hence in 400 consecutive years, February has the 29th day 97 times, and the remaining 11 months have the 29th day 400 x 11 or 4400 times.
Therefore, 29th day of the month occurs (4400 + 97) or 4497 times
Q4. Given that on 10th November 1981 is Tuesday, what was the day on 10th November 1581
Answer: D
Elplanation:
After every 400 years, the same day comes.
Thus if 10th November1981 was Tuesday, before 400 years i.e on 10th November 1581, it has to be Tuesday.
Q5. The angle bounded by the hands of a clock at 3:30 is
Answer: C
Elplanation:
Required angle = \({90}^{0} – 30 \times \frac {1}{{2}^{0}}\)
Answer: B
Elplanation:
If both the hands start moving together from the same position they will coincide after 65\(\frac {5}{11}\) minutes
Q2. After 12 noon the first right angle will be formed between the hands of a clock at
Answer: C
Elplanation:
The minute hand gains 5 \(\frac {{1}^{0}}{2}\) over the hour hand in one minute.
therefore, \({90}^{0}\) are gained in \(\frac {90}{5 \frac {1}{2}}\) min
Q3. Two clocks are set correctly at 10 a.m. on Friday. The first clock gains two minutes every hour, which is twice as much as the second. What time will be the second clock register when the correct time is 2 p.m. on the following Monday?
Answer: B
Elplanation:
The second clock gains(24 + 24 + 24 + 4 minutes)
Q4. At how many minutes past 5 p.m. are the hands of a clock at right angles to one another between 5 p.m. and 6 p.m.?
Answer: A
Elplanation:
The hands of the clock will be at right angels after 5 p.m. once the minute hands has traversed 150Â° + 90Â°=240Â° over the minute hand.
Note that 330Â° is gained in 60 minutes.
Q5. How much does a watch gain or lose per day if its hands coincide every 64 minutes of the correct time?
Answer: D
Elplanation:
in a correct watch, the minute hand gains 60 minutes over the hour hand (i.e. coincident) in 65 \(\frac {5}{11}\) minutes.
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